{"id":188808,"date":"2025-02-07T10:02:28","date_gmt":"2025-02-07T10:02:28","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=188808"},"modified":"2025-02-07T10:02:30","modified_gmt":"2025-02-07T10:02:30","slug":"compound-ch3ch2oh-ethanol","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/07\/compound-ch3ch2oh-ethanol\/","title":{"rendered":"Compound: CH3CH2OH (Ethanol)"},"content":{"rendered":"\n<p>Compound: CH3CH2OH (Ethanol) Lewis Structure 3-D Structure Skeletal Structure Functional Group(s) Present: Central Atom(s) Geometry: Polar or Non-Polar 5. Compound: CH3COOH (Ethanoic Acid) Lewis Structure 3-D Structure Skeletal Structure Functional Group(s) Present Central Atom(s) Geometry: Polar or Non-Polar 6. Compound: C2H2Cl2 Lewis Structure A Find all 3 Isomers Lewis Structure B Lewis Structure C Skeletal Structure A Skeletal Structure B Skeletal Structure C Functional Group(s) Present Functional Group(s) Present Functional Group(s) Present Central Atom(s) Geometry: Central Atom(s) Geometry: Central Atom(s) Geometry: Polar or Nonpolar (Circle one Polar or Nonpolar Circle one) Polar or Nonpolar (Circle one)<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Drawing Organic Compounds,<\/li>\n<\/ul>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">1. <strong>Ethanol (CH3CH2OH)<\/strong><\/h3>\n\n\n\n<p><strong>Lewis Structure:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Ethanol consists of two carbon atoms, five hydrogen atoms, and one hydroxyl group (-OH).<\/li>\n\n\n\n<li>The central structure can be drawn with each carbon bonded to hydrogen atoms, and the oxygen is bonded to hydrogen, completing the structure.<\/li>\n<\/ul>\n\n\n\n<pre class=\"wp-block-code\"><code>H   H\n|   |\nH-C-C-O-H\n|   |\nH   H<\/code><\/pre>\n\n\n\n<p><strong>3-D Structure:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>In 3D, ethanol adopts a tetrahedral geometry around both carbon atoms and the oxygen atom. The molecule is flexible, with the ethanol&#8217;s polar hydroxyl group (-OH) capable of forming hydrogen bonds.<\/li>\n<\/ul>\n\n\n\n<p><strong>Skeletal Structure:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The skeletal structure omits the hydrogens attached to carbon atoms. Only bonds between carbon and oxygen atoms are drawn.<\/li>\n<\/ul>\n\n\n\n<pre class=\"wp-block-code\"><code>CH3-CH2-OH<\/code><\/pre>\n\n\n\n<p><strong>Functional Group(s) Present:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Hydroxyl group (-OH).<\/li>\n<\/ul>\n\n\n\n<p><strong>Central Atom(s):<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The central atoms are carbon and oxygen.<\/li>\n<\/ul>\n\n\n\n<p><strong>Geometry:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The geometry around the carbon atoms is <strong>tetrahedral<\/strong>.<\/li>\n\n\n\n<li>The geometry around oxygen is <strong>bent<\/strong> due to lone pairs on oxygen.<\/li>\n<\/ul>\n\n\n\n<p><strong>Polar or Non-Polar:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Ethanol is <strong>polar<\/strong> because the oxygen atom in the hydroxyl group makes the molecule have a partial positive and partial negative charge, creating an overall dipole moment.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">2. <strong>Ethanoic Acid (CH3COOH)<\/strong><\/h3>\n\n\n\n<p><strong>Lewis Structure:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Ethanoic acid consists of a carboxyl group (-COOH) attached to a methyl group (-CH3).<\/li>\n<\/ul>\n\n\n\n<pre class=\"wp-block-code\"><code>H   O\n|   ||\nH-C-C-O-H\n|   |\nH   H<\/code><\/pre>\n\n\n\n<p><strong>3-D Structure:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The molecule adopts a tetrahedral geometry around the two carbon atoms.<\/li>\n\n\n\n<li>The oxygen atoms in the carboxyl group are connected through a double bond (C=O) and a single bond (C-O).<\/li>\n<\/ul>\n\n\n\n<p><strong>Skeletal Structure:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The skeletal structure can be simplified to:<\/li>\n<\/ul>\n\n\n\n<pre class=\"wp-block-code\"><code>CH3-COOH<\/code><\/pre>\n\n\n\n<p><strong>Functional Group(s) Present:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Carboxyl group (-COOH).<\/li>\n<\/ul>\n\n\n\n<p><strong>Central Atom(s):<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The central atoms are carbon and oxygen.<\/li>\n<\/ul>\n\n\n\n<p><strong>Geometry:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The geometry around the carbon in the carboxyl group is <strong>trigonal planar<\/strong> (due to the double bond).<\/li>\n\n\n\n<li>The geometry around the methyl group is <strong>tetrahedral<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p><strong>Polar or Non-Polar:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Ethanoic acid is <strong>polar<\/strong> due to the presence of the carboxyl group, which has a strong dipole.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">3. <strong>Dichloroethene (C2H2Cl2)<\/strong><\/h3>\n\n\n\n<p>There are three isomers for dichloroethene, based on the positions of the chlorine atoms.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">Isomer A: 1,1-Dichloroethene<\/h4>\n\n\n\n<p><strong>Lewis Structure:<\/strong><\/p>\n\n\n\n<pre class=\"wp-block-code\"><code>H-C=C-Cl\n   |   \n   Cl<\/code><\/pre>\n\n\n\n<p><strong>Skeletal Structure:<\/strong><\/p>\n\n\n\n<pre class=\"wp-block-code\"><code>Cl-C=C-Cl<\/code><\/pre>\n\n\n\n<p><strong>Functional Group(s) Present:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>None specifically.<\/li>\n<\/ul>\n\n\n\n<p><strong>Central Atom(s):<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Carbon atoms.<\/li>\n<\/ul>\n\n\n\n<p><strong>Geometry:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The carbon-carbon double bond results in a <strong>planar<\/strong> geometry.<\/li>\n<\/ul>\n\n\n\n<p><strong>Polar or Non-Polar:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Polar<\/strong> due to the asymmetric distribution of chlorine atoms.<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\">Isomer B: 1,2-Dichloroethene (Cis form)<\/h4>\n\n\n\n<p><strong>Lewis Structure:<\/strong><\/p>\n\n\n\n<pre class=\"wp-block-code\"><code>H-C=C-Cl\n   |   \n   Cl<\/code><\/pre>\n\n\n\n<p><strong>Skeletal Structure:<\/strong><\/p>\n\n\n\n<pre class=\"wp-block-code\"><code>H-C=C-Cl\n    |   \n    Cl<\/code><\/pre>\n\n\n\n<p><strong>Functional Group(s) Present:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>None specifically.<\/li>\n<\/ul>\n\n\n\n<p><strong>Central Atom(s):<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Carbon atoms.<\/li>\n<\/ul>\n\n\n\n<p><strong>Geometry:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The carbon-carbon double bond gives it a <strong>planar<\/strong> geometry.<\/li>\n<\/ul>\n\n\n\n<p><strong>Polar or Non-Polar:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Polar<\/strong> due to the cis configuration of the chlorine atoms, which introduces an uneven charge distribution.<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\">Isomer C: 1,2-Dichloroethene (Trans form)<\/h4>\n\n\n\n<p><strong>Lewis Structure:<\/strong><\/p>\n\n\n\n<pre class=\"wp-block-code\"><code>H-C=C-Cl\n   |   \n   Cl<\/code><\/pre>\n\n\n\n<p><strong>Skeletal Structure:<\/strong><\/p>\n\n\n\n<pre class=\"wp-block-code\"><code>H-C=C-Cl\n    |   \n    Cl<\/code><\/pre>\n\n\n\n<p><strong>Functional Group(s) Present:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>None specifically.<\/li>\n<\/ul>\n\n\n\n<p><strong>Central Atom(s):<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Carbon atoms.<\/li>\n<\/ul>\n\n\n\n<p><strong>Geometry:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Similar to the cis form, with a <strong>planar<\/strong> structure.<\/li>\n<\/ul>\n\n\n\n<p><strong>Polar or Non-Polar:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Non-polar<\/strong> as the chlorine atoms are opposite to each other, canceling out the dipoles.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Summary:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Ethanol (CH3CH2OH)<\/strong> is polar, with a hydroxyl group (-OH).<\/li>\n\n\n\n<li><strong>Ethanoic Acid (CH3COOH)<\/strong> is polar due to its carboxyl group (-COOH).<\/li>\n\n\n\n<li><strong>Dichloroethene (C2H2Cl2)<\/strong> has isomers, where the trans form is non-polar, and the cis form is polar.<\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>Compound: CH3CH2OH (Ethanol) Lewis Structure 3-D Structure Skeletal Structure Functional Group(s) Present: Central Atom(s) Geometry: Polar or Non-Polar 5. Compound: CH3COOH (Ethanoic Acid) Lewis Structure 3-D Structure Skeletal Structure Functional Group(s) Present Central Atom(s) Geometry: Polar or Non-Polar 6. Compound: C2H2Cl2 Lewis Structure A Find all 3 Isomers Lewis Structure B Lewis Structure C Skeletal [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-188808","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/188808","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=188808"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/188808\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=188808"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=188808"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=188808"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}