{"id":189009,"date":"2025-02-08T10:25:11","date_gmt":"2025-02-08T10:25:11","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=189009"},"modified":"2025-02-08T10:25:14","modified_gmt":"2025-02-08T10:25:14","slug":"use-the-molar-mass-of-al2so43-to-calculate-the-number-of-formula-units-in-10-0-g-of-as","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/08\/use-the-molar-mass-of-al2so43-to-calculate-the-number-of-formula-units-in-10-0-g-of-as\/","title":{"rendered":"Use the molar mass of Al2(SO4)3 to calculate the number of formula units in 10.0 g of AS"},"content":{"rendered":"\n<p>Use the molar mass of Al2(SO4)3 to calculate the number of formula units in 10.0 g of AS. Everything about a chemical formula is a direct proportion. We calculated the molar mass of aluminium sulphate as 342.15 g\/mol. In the previous problem we calculated that there are 0.0292274 moles in 10.0 g.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/02\/image-166.png\" alt=\"\" class=\"wp-image-189010\"\/><\/figure>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>To find the number of formula units in 10.0 g of aluminum sulfate (Al\u2082(SO\u2084)\u2083), we&#8217;ll use the moles we have calculated and Avogadro&#8217;s number, which gives the number of particles (in this case, formula units) in one mole of a substance.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Moles of Aluminum Sulfate<\/h3>\n\n\n\n<p>From the given information, we know that the number of moles of aluminum sulfate (Al\u2082(SO\u2084)\u2083) in 10.0 g is <strong>0.0292274 moles<\/strong>. This was calculated using the molar mass of aluminum sulfate (342.15 g\/mol) in the previous problem.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Avogadro&#8217;s Number<\/h3>\n\n\n\n<p>Avogadro&#8217;s number, <strong>6.022 \u00d7 10\u00b2\u00b3 formula units\/mole<\/strong>, is the constant used to convert moles to individual formula units.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Formula Units Calculation<\/h3>\n\n\n\n<p>To calculate the number of formula units, we multiply the number of moles of the substance by Avogadro&#8217;s number:<\/p>\n\n\n\n<p>[<br>\\text{Number of formula units} = \\text{moles} \\times \\text{Avogadro&#8217;s number}<br>]<\/p>\n\n\n\n<p>Substituting the values:<\/p>\n\n\n\n<p>[<br>\\text{Number of formula units} = 0.0292274 \\, \\text{moles} \\times 6.022 \\times 10^{23} \\, \\text{formula units\/mole}<br>]<\/p>\n\n\n\n<p>[<br>\\text{Number of formula units} = 1.759 \\times 10^{22} \\, \\text{formula units}<br>]<\/p>\n\n\n\n<p>Thus, there are <strong>1.759 \u00d7 10\u00b2\u00b2 formula units<\/strong> of aluminum sulfate in 10.0 g.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation<\/h3>\n\n\n\n<p>The concept of moles is fundamental to understanding chemical reactions and stoichiometry. A <strong>mole<\/strong> is simply a way to count particles, whether atoms, molecules, or formula units, much like a dozen counts 12 objects. The number of particles in one mole is fixed by Avogadro\u2019s number, which is approximately ( 6.022 \\times 10^{23} ) particles. This number is constant for any substance, so by knowing the moles of a substance, we can calculate how many individual formula units are present.<\/p>\n\n\n\n<p>In this problem, we were given the number of moles of aluminum sulfate (0.0292274 moles) and its molar mass (342.15 g\/mol). Using this information, we converted the amount of aluminum sulfate from grams to moles and then used Avogadro&#8217;s number to find the number of formula units in the given sample. This approach allows us to understand the scale of particles in even a small quantity of a substance, helping chemists predict how substances will react in a chemical reaction.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Use the molar mass of Al2(SO4)3 to calculate the number of formula units in 10.0 g of AS. Everything about a chemical formula is a direct proportion. We calculated the molar mass of aluminium sulphate as 342.15 g\/mol. In the previous problem we calculated that there are 0.0292274 moles in 10.0 g. The Correct Answer [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-189009","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/189009","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=189009"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/189009\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=189009"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=189009"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=189009"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}