A solution that is 7.56% by mass NaNO3 (molar mass=85.0 g\/mole) in water (molar mass=18.0 g\/mole) has a density of 1.09 g\/mL. What is its molarity?<\/p>\n\n\n\n
The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n To determine the molarity of a solution, we need to calculate the number of moles of NaNO\u2083 per liter of solution. Molarity (M) is defined as:<\/p>\n\n\n\n [ Given information:<\/p>\n\n\n\n A 7.56% mass percent means that in 100 g of solution, there are 7.56 g of NaNO\u2083.<\/p>\n\n\n\n Thus, for every 100 g of solution, we have: To find the volume of the solution, use the density equation:<\/p>\n\n\n\n [ Rearrange this to find the volume of the solution: Substitute the values: Using the molar mass of NaNO\u2083 (85.0 g\/mol), calculate the moles of NaNO\u2083: Now, calculate the molarity (M) by dividing the moles of NaNO\u2083 by the volume of the solution in liters:<\/p>\n\n\n\n [ Thus, the molarity of the solution is approximately 0.970 M<\/strong>.<\/p>\n\n\n\n The solution’s molarity was determined by first calculating the mass of NaNO\u2083 and the volume of the solution. By using density, we converted mass to volume. Then, using the molar mass of NaNO\u2083, we found the number of moles in the solution. Finally, molarity was determined by dividing the moles of NaNO\u2083 by the volume of the solution in liters.<\/p>\n","protected":false},"excerpt":{"rendered":" A solution that is 7.56% by mass NaNO3 (molar mass=85.0 g\/mole) in water (molar mass=18.0 g\/mole) has a density of 1.09 g\/mL. What is its molarity? The Correct Answer and Explanation is : To determine the molarity of a solution, we need to calculate the number of moles of NaNO\u2083 per liter of solution. Molarity […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-189048","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/189048","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=189048"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/189048\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=189048"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=189048"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=189048"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
M = \\frac{\\text{moles of solute}}{\\text{volume of solution in liters}}
]<\/p>\n\n\n\n\n
Step 1: Determine the mass of NaNO\u2083 in the solution<\/h3>\n\n\n\n
[
\\text{Mass of NaNO\u2083} = 7.56 \\, \\text{g}
]
[
\\text{Mass of solution} = 100 \\, \\text{g}
]<\/p>\n\n\n\nStep 2: Find the volume of the solution<\/h3>\n\n\n\n
\\text{Density} = \\frac{\\text{Mass of solution}}{\\text{Volume of solution}}
]<\/p>\n\n\n\n
[
\\text{Volume of solution} = \\frac{\\text{Mass of solution}}{\\text{Density}}
]<\/p>\n\n\n\n
[
\\text{Volume of solution} = \\frac{100 \\, \\text{g}}{1.09 \\, \\text{g\/mL}} = 91.74 \\, \\text{mL} = 0.09174 \\, \\text{L}
]<\/p>\n\n\n\nStep 3: Calculate the moles of NaNO\u2083<\/h3>\n\n\n\n
[
\\text{Moles of NaNO\u2083} = \\frac{\\text{Mass of NaNO\u2083}}{\\text{Molar mass of NaNO\u2083}} = \\frac{7.56 \\, \\text{g}}{85.0 \\, \\text{g\/mol}} = 0.08894 \\, \\text{mol}
]<\/p>\n\n\n\nStep 4: Calculate the molarity<\/h3>\n\n\n\n
M = \\frac{0.08894 \\, \\text{mol}}{0.09174 \\, \\text{L}} = 0.970 \\, \\text{M}
]<\/p>\n\n\n\nExplanation:<\/h3>\n\n\n\n