{"id":189122,"date":"2025-02-08T18:55:24","date_gmt":"2025-02-08T18:55:24","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=189122"},"modified":"2025-02-08T18:55:27","modified_gmt":"2025-02-08T18:55:27","slug":"in-pure-dielectrics-the-parameter-that-is-zero-is","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/08\/in-pure-dielectrics-the-parameter-that-is-zero-is\/","title":{"rendered":"\u00a0 \u00a0In pure dielectrics the parameter that is zero is"},"content":{"rendered":"\n<p>1.&nbsp;&nbsp;&nbsp; What is the following simplified product? Assume x&gt;=0. 2\\sqrt(8x^(3))(3\\sqrt(10x^(4))-x\\sqrt(5x^(2)))<\/p>\n\n\n\n<p>2.&nbsp;&nbsp;&nbsp; &nbsp;In pure dielectrics, the parameter that is zero is<br>a) Attenuation<br>b) Propagation<br>c) Conductivity<br>d) Resistivity<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\">The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The simplified product of the given expression is: 4&#215;72(65\u221210)4x^{\\frac{7}{2}}(6\\sqrt{5} &#8211; \\sqrt{10})<\/p>\n\n\n\n<p>Now, I&#8217;ll provide the answer and explanation for the second question.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Answer:<\/h3>\n\n\n\n<p><strong>(c) Conductivity<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>Pure dielectrics are insulating materials that do not allow free flow of electric charge under normal conditions. The parameter that is zero in pure dielectrics is <strong>conductivity<\/strong>.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>1. Understanding Conductivity in Dielectrics<\/strong><\/h4>\n\n\n\n<p>Conductivity (\u03c3\\sigma) is a measure of a material\u2019s ability to conduct electric current. It is defined as the reciprocal of resistivity (\u03c1\\rho): \u03c3=1\u03c1\\sigma = \\frac{1}{\\rho}<\/p>\n\n\n\n<p>In conductors like metals, conductivity is high due to the presence of free electrons. However, in dielectrics (insulators), there are no free electrons to facilitate conduction, leading to <strong>zero or extremely low conductivity<\/strong>.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>2. Why is Conductivity Zero in Pure Dielectrics?<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Lack of Free Charge Carriers:<\/strong> In a pure dielectric, all electrons are tightly bound to atoms or molecules, meaning there are no free electrons or mobile charge carriers available to conduct electricity.<\/li>\n\n\n\n<li><strong>Large Band Gap:<\/strong> Dielectrics have a large energy gap between the valence and conduction bands, making it difficult for electrons to move freely under an electric field.<\/li>\n\n\n\n<li><strong>No Ionic Movement:<\/strong> Unlike electrolytes, pure dielectrics do not contain free-moving ions that can conduct current.<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>3. Other Parameters in the Question<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Attenuation:<\/strong> This refers to the reduction of signal strength over distance and is not necessarily zero in dielectrics.<\/li>\n\n\n\n<li><strong>Propagation:<\/strong> Wave propagation occurs in dielectrics, especially in electromagnetic waves, so it is not zero.<\/li>\n\n\n\n<li><strong>Resistivity:<\/strong> Dielectrics have <strong>high resistivity<\/strong>, not zero resistivity.<\/li>\n<\/ul>\n\n\n\n<p>Thus, the only correct answer is <strong>(c) Conductivity<\/strong>, which is zero in pure dielectrics.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>1.&nbsp;&nbsp;&nbsp; What is the following simplified product? Assume x&gt;=0. 2\\sqrt(8x^(3))(3\\sqrt(10x^(4))-x\\sqrt(5x^(2))) 2.&nbsp;&nbsp;&nbsp; &nbsp;In pure dielectrics, the parameter that is zero isa) Attenuationb) Propagationc) Conductivityd) Resistivity The correct answer and explanation is: The simplified product of the given expression is: 4&#215;72(65\u221210)4x^{\\frac{7}{2}}(6\\sqrt{5} &#8211; \\sqrt{10}) Now, I&#8217;ll provide the answer and explanation for the second question. Answer: (c) Conductivity [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-189122","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/189122","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=189122"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/189122\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=189122"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=189122"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=189122"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}