A 10 ohm resistor dissipates 1W of power when connected to a DC voltage source if the DC voltage is double the resistor will dissipate how much power<\/p>\n\n\n\n
The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n To solve this problem, we need to apply the relationship between power, resistance, and voltage. The formula for power dissipation in a resistor is:<\/p>\n\n\n\n [ Where:<\/p>\n\n\n\n The power dissipated in a resistor is directly related to the square of the voltage applied across it. If the voltage is doubled, the power increases by a factor of four, because:<\/p>\n\n\n\n [ Thus, doubling the voltage results in four times the original power dissipation. In this case, since the initial power was 1W, doubling the voltage results in approximately 4W of power dissipation.<\/p>\n","protected":false},"excerpt":{"rendered":" A 10 ohm resistor dissipates 1W of power when connected to a DC voltage source if the DC voltage is double the resistor will dissipate how much power The Correct Answer and Explanation is : To solve this problem, we need to apply the relationship between power, resistance, and voltage. The formula for power dissipation […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-189612","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/189612","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=189612"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/189612\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=189612"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=189612"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=189612"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
P = \\frac{V^2}{R}
]<\/p>\n\n\n\n\n
Step-by-step Calculation:<\/h3>\n\n\n\n
\n
\n
\n
P = \\frac{V^2}{R} \\quad \\Rightarrow \\quad V^2 = P \\times R
] Substituting the given values for power and resistance: [
V^2 = 1 \\, \\text{W} \\times 10 \\, \\Omega = 10 \\quad \\Rightarrow \\quad V = \\sqrt{10} \\approx 3.16 \\, \\text{V}
] So the initial voltage across the resistor is approximately 3.16V.<\/li>\n\n\n\n
V_{\\text{new}} = 2 \\times 3.16 \\, \\text{V} = 6.32 \\, \\text{V}
]<\/li>\n\n\n\n
P_{\\text{new}} = \\frac{V_{\\text{new}}^2}{R} = \\frac{(6.32)^2}{10} = \\frac{39.94}{10} = 3.994 \\, \\text{W}
] So, when the voltage is doubled, the power dissipated by the resistor is approximately 4 watts.<\/li>\n<\/ol>\n\n\n\nExplanation:<\/h3>\n\n\n\n
P \\propto V^2
]<\/p>\n\n\n\n