What is the molar mass of calcium nitrate, Ca(NO3)2?
A 16 g
B 63 g
C 164 g
D 96 g
E 150.1 g<\/p>\n\n\n\n
The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n The correct answer is C) 164 g<\/strong>.<\/p>\n\n\n\n To calculate the molar mass of calcium nitrate, ( \\text{Ca(NO}_3)_2 ), we need to sum up the atomic masses of all the elements in the compound.<\/p>\n\n\n\n The formula ( \\text{Ca(NO}_3)_2 ) represents one calcium atom, two nitrogen atoms, and six oxygen atoms. This can be written as:<\/p>\n\n\n\n Now, we can sum the individual masses: Thus, the molar mass of calcium nitrate is approximately 164 g\/mol<\/strong>.<\/p>\n\n\n\n The correct answer is C) 164 g<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":" What is the molar mass of calcium nitrate, Ca(NO3)2?A 16 gB 63 gC 164 gD 96 gE 150.1 g The Correct Answer and Explanation is : The correct answer is C) 164 g. To calculate the molar mass of calcium nitrate, ( \\text{Ca(NO}_3)_2 ), we need to sum up the atomic masses of all the […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-189639","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/189639","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=189639"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/189639\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=189639"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=189639"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=189639"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}Step 1: Identify the elements and their atomic masses<\/h3>\n\n\n\n
\n
Step 2: Break down the formula ( \\text{Ca(NO}_3)_2 )<\/h3>\n\n\n\n
\n
Step 3: Calculate the total mass of each element<\/h3>\n\n\n\n
\n
[
1 \\times 40.08 \\, \\text{g\/mol} = 40.08 \\, \\text{g\/mol}
]<\/li>\n\n\n\n
[
2 \\times 14.01 \\, \\text{g\/mol} = 28.02 \\, \\text{g\/mol}
]<\/li>\n\n\n\n
[
6 \\times 16.00 \\, \\text{g\/mol} = 96.00 \\, \\text{g\/mol}
]<\/li>\n<\/ul>\n\n\n\nStep 4: Add up the masses<\/h3>\n\n\n\n
[
40.08 \\, \\text{g\/mol} + 28.02 \\, \\text{g\/mol} + 96.00 \\, \\text{g\/mol} = 164.10 \\, \\text{g\/mol}
]<\/p>\n\n\n\nConclusion:<\/h3>\n\n\n\n