{"id":189696,"date":"2025-02-10T07:28:21","date_gmt":"2025-02-10T07:28:21","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=189696"},"modified":"2025-02-10T07:28:23","modified_gmt":"2025-02-10T07:28:23","slug":"balance-the-reactions-in-the-following","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/10\/balance-the-reactions-in-the-following\/","title":{"rendered":"Balance the reactions in the following"},"content":{"rendered":"\n


Balance the reactions in the following.
Balanced equation
SOLUTION.PDF
May 2013
H+N NH
CaCl\u2082+ AgNO\u2192 Ca(NO3)2 + AgCl
SnO:+H\u2082H\u2082O + Sn
Na2CO3 + HCI \u2192 NaCl + H2O + CO:
Fe2(SO) + KOH KSO+ Fe (OH)
CHOOCO:+H\u2082O
Fe(OH):F:O+H\u2082 + H\u2082O<\/p>\n\n\n\n

The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n

Let’s go through each of the reactions and balance them step by step:<\/p>\n\n\n\n

1. CaCl\u2082 + AgNO\u2083 \u2192 Ca(NO\u2083)\u2082 + AgCl<\/strong><\/h3>\n\n\n\n
    \n
  • This is a double displacement reaction where calcium chloride reacts with silver nitrate to form calcium nitrate and silver chloride.<\/li>\n\n\n\n
  • Balanced equation:<\/strong>
    [
    \\text{CaCl}_2 + 2\\text{AgNO}_3 \u2192 \\text{Ca(NO}_3)_2 + 2\\text{AgCl}
    ]<\/li>\n<\/ul>\n\n\n\n

    Explanation: The calcium ion (Ca\u00b2\u207a) pairs with two nitrate ions (NO\u2083\u207b) to form calcium nitrate (Ca(NO\u2083)\u2082), while silver (Ag\u207a) ions combine with chloride (Cl\u207b) ions to form silver chloride (AgCl).<\/p>\n\n\n\n

    \n\n\n\n

    2. SnO\u2082 + H\u2082 \u2192 Sn + H\u2082O<\/strong><\/h3>\n\n\n\n
      \n
    • Tin (IV) oxide reacts with hydrogen gas to produce tin and water.<\/li>\n\n\n\n
    • Balanced equation:<\/strong>
      [
      \\text{SnO}_2 + 2\\text{H}_2 \u2192 \\text{Sn} + 2\\text{H}_2\\text{O}
      ]<\/li>\n<\/ul>\n\n\n\n

      Explanation: Each tin (Sn) atom in SnO\u2082 gains two electrons from hydrogen (H\u2082) to reduce to elemental tin (Sn), while the hydrogen gas is oxidized to water (H\u2082O).<\/p>\n\n\n\n

      \n\n\n\n

      3. Na\u2082CO\u2083 + 2HCl \u2192 2NaCl + H\u2082O + CO\u2082<\/strong><\/h3>\n\n\n\n
        \n
      • Sodium carbonate reacts with hydrochloric acid to produce sodium chloride, water, and carbon dioxide.<\/li>\n\n\n\n
      • Balanced equation:<\/strong>
        [
        \\text{Na}_2\\text{CO}_3 + 2\\text{HCl} \u2192 2\\text{NaCl} + \\text{H}_2\\text{O} + \\text{CO}_2
        ]<\/li>\n<\/ul>\n\n\n\n

        Explanation: Sodium carbonate (Na\u2082CO\u2083) reacts with hydrochloric acid (HCl) in a double displacement reaction, releasing carbon dioxide (CO\u2082) gas and forming water.<\/p>\n\n\n\n

        \n\n\n\n

        4. Fe\u2082(SO\u2084)\u2083 + 6KOH \u2192 2Fe(OH)\u2083 + 3K\u2082SO\u2084<\/strong><\/h3>\n\n\n\n
          \n
        • Iron (III) sulfate reacts with potassium hydroxide to form iron (III) hydroxide and potassium sulfate.<\/li>\n\n\n\n
        • Balanced equation:<\/strong>
          [
          \\text{Fe}_2\\text{(SO}_4)_3 + 6\\text{KOH} \u2192 2\\text{Fe(OH)}_3 + 3\\text{K}_2\\text{SO}_4
          ]<\/li>\n<\/ul>\n\n\n\n

          Explanation: Iron (III) sulfate dissociates to provide Fe\u00b3\u207a ions, which combine with hydroxide ions from potassium hydroxide to form iron (III) hydroxide (Fe(OH)\u2083), while potassium ions pair with sulfate ions to form potassium sulfate (K\u2082SO\u2084).<\/p>\n\n\n\n

          \n\n\n\n

          5. CH\u2083COOH + H\u2082O \u2192 CH\u2083COO\u207b + H\u2083O\u207a<\/strong><\/h3>\n\n\n\n
            \n
          • Acetic acid reacts with water to form acetate ions and hydronium ions.<\/li>\n\n\n\n
          • Balanced equation:<\/strong>
            [
            \\text{CH}_3\\text{COOH} + \\text{H}_2\\text{O} \u2192 \\text{CH}_3\\text{COO}^- + \\text{H}_3\\text{O}^+
            ]<\/li>\n<\/ul>\n\n\n\n

            Explanation: Acetic acid (CH\u2083COOH) dissociates in water, donating a proton (H\u207a) to water molecules to form hydronium ions (H\u2083O\u207a), leaving behind acetate ions (CH\u2083COO\u207b).<\/p>\n\n\n\n

            \n\n\n\n

            6. Fe(OH)\u2083 + 3H\u2082 \u2192 Fe + 3H\u2082O<\/strong><\/h3>\n\n\n\n
              \n
            • Iron (III) hydroxide reacts with hydrogen gas to produce iron and water.<\/li>\n\n\n\n
            • Balanced equation:<\/strong>
              [
              \\text{Fe(OH)}_3 + 3\\text{H}_2 \u2192 \\text{Fe} + 3\\text{H}_2\\text{O}
              ]<\/li>\n<\/ul>\n\n\n\n

              Explanation: Iron (III) hydroxide is reduced to iron (Fe), while hydrogen gas is oxidized to form water (H\u2082O).<\/p>\n\n\n\n

              \n\n\n\n

              These reactions show common types such as displacement, acid-base reactions, and redox reactions. In balancing chemical equations, the law of conservation of mass ensures that the same number of atoms of each element are present on both sides of the reaction. Each type of reaction may require different strategies, such as using coefficients to balance the number of molecules or atoms involved.<\/p>\n","protected":false},"excerpt":{"rendered":"

              Balance the reactions in the following.Balanced equationSOLUTION.PDFMay 2013H+N NHCaCl\u2082+ AgNO\u2192 Ca(NO3)2 + AgClSnO:+H\u2082H\u2082O + SnNa2CO3 + HCI \u2192 NaCl + H2O + CO:Fe2(SO) + KOH KSO+ Fe (OH)CHOOCO:+H\u2082OFe(OH):F:O+H\u2082 + H\u2082O The Correct Answer and Explanation is : Let’s go through each of the reactions and balance them step by step: 1. CaCl\u2082 + AgNO\u2083 \u2192 […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-189696","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/189696","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=189696"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/189696\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=189696"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=189696"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=189696"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}