{"id":189923,"date":"2025-02-10T19:03:26","date_gmt":"2025-02-10T19:03:26","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=189923"},"modified":"2025-02-10T19:03:29","modified_gmt":"2025-02-10T19:03:29","slug":"lewis-structure-illustrate-the-lewis-structure-for-c2cl4","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/10\/lewis-structure-illustrate-the-lewis-structure-for-c2cl4\/","title":{"rendered":"Lewis structure Illustrate the Lewis structure for C2Cl4"},"content":{"rendered":"\n<p>Lewis structure Illustrate the Lewis structure for C2Cl4. Determine the polarity of the compound.<br><br><br><br><br><br><\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\">The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Lewis Structure of C\u2082Cl\u2084 (Tetrachloroethene)<\/strong><\/h3>\n\n\n\n<p>Tetrachloroethene (C\u2082Cl\u2084), also known as perchloroethylene, consists of two carbon (C) atoms and four chlorine (Cl) atoms. The Lewis structure follows these steps:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Count the total valence electrons<\/strong>\n<ul class=\"wp-block-list\">\n<li>Carbon (C) has 4 valence electrons, and there are 2 C atoms: 4\u00d72=84 \\times 2 = 8.<\/li>\n\n\n\n<li>Chlorine (Cl) has 7 valence electrons, and there are 4 Cl atoms: 7\u00d74=287 \\times 4 = 28.<\/li>\n\n\n\n<li><strong>Total valence electrons<\/strong> = 8+28=368 + 28 = 36.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Determine the skeletal structure<\/strong>\n<ul class=\"wp-block-list\">\n<li>Carbon atoms are typically central due to their ability to form multiple bonds.<\/li>\n\n\n\n<li>The two carbon atoms form a <strong>double bond (C=C)<\/strong> to satisfy the octet rule.<\/li>\n\n\n\n<li>Each carbon forms <strong>two single bonds<\/strong> with two chlorine atoms.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Distribute the electrons<\/strong>\n<ul class=\"wp-block-list\">\n<li>The <strong>C=C double bond<\/strong> uses 4 electrons (2 per bond).<\/li>\n\n\n\n<li>Each <strong>C-Cl single bond<\/strong> uses 2 electrons per bond. With 4 Cl atoms, that accounts for 8 electrons.<\/li>\n\n\n\n<li>The remaining electrons go on Cl atoms as lone pairs.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Check the octet rule<\/strong>\n<ul class=\"wp-block-list\">\n<li>Each chlorine has <strong>8 valence electrons<\/strong> (1 bonding pair + 3 lone pairs).<\/li>\n\n\n\n<li>Each carbon has <strong>8 valence electrons<\/strong> (1 double bond + 2 single bonds).<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Polarity of C\u2082Cl\u2084<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Symmetry Analysis<\/strong>: The molecular structure is <strong>tetrahedral around each carbon<\/strong>, and the <strong>C=C bond is linear<\/strong>.<\/li>\n\n\n\n<li><strong>Dipole Moments<\/strong>: Although <strong>C-Cl bonds are polar<\/strong>, the symmetry cancels out dipole moments.<\/li>\n\n\n\n<li><strong>Overall Polarity<\/strong>: <strong>Nonpolar<\/strong>, because the symmetrical shape causes the dipoles to cancel.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Final Answer<\/strong><\/h3>\n\n\n\n<p><strong>C\u2082Cl\u2084 is a nonpolar molecule due to its symmetrical shape, even though it contains polar C-Cl bonds.<\/strong><\/p>\n\n\n\n<p>Now, I will generate the Lewis structure image.<\/p>\n\n\n\n<p>Here is the Lewis structure for C\u2082Cl\u2084 (tetrachloroethene). You can see the two carbon atoms connected by a double bond, each bonded to two chlorine atoms. The lone pairs on chlorine are also displayed. Let me know if you need any modifications or further explanations!<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/02\/image-258.png\" alt=\"\" class=\"wp-image-189924\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Lewis structure Illustrate the Lewis structure for C2Cl4. Determine the polarity of the compound. The correct answer and explanation is: Lewis Structure of C\u2082Cl\u2084 (Tetrachloroethene) Tetrachloroethene (C\u2082Cl\u2084), also known as perchloroethylene, consists of two carbon (C) atoms and four chlorine (Cl) atoms. The Lewis structure follows these steps: Polarity of C\u2082Cl\u2084 Final Answer C\u2082Cl\u2084 is [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-189923","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/189923","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=189923"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/189923\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=189923"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=189923"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=189923"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}