{"id":190052,"date":"2025-02-11T06:05:11","date_gmt":"2025-02-11T06:05:11","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=190052"},"modified":"2025-02-11T06:05:13","modified_gmt":"2025-02-11T06:05:13","slug":"c-has-a-conditional-operator","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/11\/c-has-a-conditional-operator\/","title":{"rendered":"C++ has a “conditional operator”"},"content":{"rendered":"\n

C++ has a “conditional operator”, ?: (question mark together with is used in a conditional expression as follows: Boolean_expression ? expression1: expression2 For example: x > y + 5 ? 125: 3f(45) If x > y + 5 is true, the value of the conditional expression is 125 otherwise the value is 3<\/em>f(45) Consider the following program: #include using namespace std; int p(int i, int j){\/\/base case if(i\/10 ==0) return i>j?i:j; int left=i%10; int right=j%10; if(i\/10)*10+(right>left?right:left); if (k==i\/10) return i; else return j;} int main() {cout<<=”” span=””><\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n

The ternary conditional operator ?:<\/code> in C++ provides a concise way to perform conditional assignments or evaluations. Its syntax is:<\/p>\n\n\n\n

condition ? expression_if_true : expression_if_false;<\/code><\/pre>\n\n\n\n
This operator evaluates condition<\/code>; if it’s true, expression_if_true<\/code> is executed; otherwise, expression_if_false<\/code> is executed.<\/p>\n\n\n\n
Example:<\/strong><\/p>\n\n\n\n
int max = (a > b) ? a : b;<\/code><\/pre>\n\n\n\n
In this example, if a<\/code> is greater than b<\/code>, max<\/code> is assigned the value of a<\/code>; otherwise, it’s assigned the value of b<\/code>.<\/p>\n\n\n\n
Explanation of the Provided Code:<\/strong><\/p>\n\n\n\n
The provided code snippet appears to be incomplete and contains syntax errors. However, based on the available information, it seems to be attempting to implement a function p<\/code> that compares two integers i<\/code> and j<\/code> and returns the larger of the two.<\/p>\n\n\n\n
The function p<\/code> is intended to compare the digits of i<\/code> and j<\/code> from the least significant to the most significant. It extracts the least significant digits of i<\/code> and j<\/code> using the modulo operator %<\/code> and compares them. If the digit of i<\/code> is greater than the digit of j<\/code>, it recursively calls p<\/code> with the remaining digits of i<\/code> and j<\/code>. If the digit of j<\/code> is greater than the digit of i<\/code>, it returns j<\/code>.<\/p>\n\n\n\n
However, the code contains several issues:<\/p>\n\n\n\n
    \n
  1. Syntax Errors:<\/strong> The code contains incomplete statements and missing semicolons, which will result in compilation errors.<\/li>\n\n\n\n
  2. Uninitialized Variable k<\/code>:<\/strong> The variable k<\/code> is used without being declared or initialized, leading to undefined behavior.<\/li>\n\n\n\n
  3. Incorrect Recursive Call:<\/strong> The recursive call p(i \/ 10, j \/ 10)<\/code> is intended to compare the remaining digits of i<\/code> and j<\/code>. However, the logic for comparing the digits is flawed, and the function may not return the correct result.<\/li>\n\n\n\n
  4. Incomplete main<\/code> Function:<\/strong> The main<\/code> function is incomplete and lacks the necessary code to test the function p<\/code>.<\/li>\n<\/ol>\n\n\n\n
    Corrected Version:<\/strong><\/p>\n\n\n\n
    #include <iostream>\nusing namespace std;\n\nint p(int i, int j) {\n    \/\/ Base case: if both numbers are single digits\n    if (i < 10 && j < 10) {\n        return (i > j) ? i : j;\n    }\n    \/\/ Recursive case: compare the least significant digits\n    int left = i % 10;\n    int right = j % 10;\n    if (left > right) {\n        return p(i \/ 10, j);\n    } else if (right > left) {\n        return p(i, j \/ 10);\n    } else {\n        return p(i \/ 10, j \/ 10);\n    }\n}\n\nint main() {\n    int i = 123;\n    int j = 456;\n    cout << \"The larger number is: \" << p(i, j) << endl;\n    return 0;\n}<\/code><\/pre>\n\n\n\n
    Explanation:<\/strong><\/p>\n\n\n\n
      \n
    1. Base Case:<\/strong> The function first checks if both i<\/code> and j<\/code> are single-digit numbers. If they are, it returns the larger of the two using the ternary operator.<\/li>\n\n\n\n
    2. Recursive Case:<\/strong> If either i<\/code> or j<\/code> has more than one digit, the function compares the least significant digits (obtained using the modulo operator %<\/code>).<\/li>\n\n\n\n
    3. Comparison Logic:<\/strong><\/li>\n<\/ol>\n\n\n\n