{"id":190121,"date":"2025-02-11T07:15:20","date_gmt":"2025-02-11T07:15:20","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=190121"},"modified":"2025-02-11T07:15:38","modified_gmt":"2025-02-11T07:15:38","slug":"form-pocl3-in-co-ordinate-covalent-bond-pcl3-1-2o2-pocl3","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/11\/form-pocl3-in-co-ordinate-covalent-bond-pcl3-1-2o2-pocl3\/","title":{"rendered":"form POCl3-in co-ordinate covalent bond"},"content":{"rendered":"\n<p>form POCl3-in co-ordinate covalent bond. PCl3 +1\/2O2 &#8212;&#8212;POCl3<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>The reaction you have described is the formation of phosphorus oxychloride (POCl\u2083) from phosphorus trichloride (PCl\u2083) and oxygen gas (O\u2082):<\/p>\n\n\n\n<p>[ \\text{PCl}_3 + \\frac{1}{2} \\text{O}_2 \\rightarrow \\text{POCl}_3 ]<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step-by-step Explanation:<\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Reactants<\/strong>:<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>PCl\u2083<\/strong> (phosphorus trichloride) consists of one phosphorus (P) atom covalently bonded to three chlorine (Cl) atoms.<\/li>\n\n\n\n<li><strong>O\u2082<\/strong> (oxygen) is a diatomic molecule composed of two oxygen atoms held together by a double bond.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Reaction Mechanism<\/strong>:<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Phosphorus trichloride reacts with oxygen gas in a stoichiometric ratio of 1:\u00bd. This means that one mole of PCl\u2083 combines with half a mole of O\u2082.<\/li>\n\n\n\n<li>The phosphorus atom in PCl\u2083 has a lone pair of electrons and can form bonds with oxygen atoms. The oxygen molecule (O\u2082) will undergo a cleavage to provide one oxygen atom for bonding.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Coordination and Bond Formation<\/strong>:<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Phosphorus in PCl\u2083 has an incomplete octet, meaning it has room for more bonds. This property makes it capable of accepting a lone pair of electrons from the oxygen atom during the reaction.<\/li>\n\n\n\n<li>The oxygen atom from O\u2082 will use its lone pair of electrons to form a coordinate covalent bond with the phosphorus atom.<\/li>\n\n\n\n<li>The resulting product, POCl\u2083, consists of a phosphorus atom bonded to three chlorine atoms and one oxygen atom, forming a tetrahedral structure.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Nature of the Bond<\/strong>:<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The bond formed between the phosphorus and the oxygen is a <strong>coordinate covalent bond<\/strong> (also called a dative bond). This is because the oxygen atom donates a lone pair of electrons to phosphorus to form the bond.<\/li>\n\n\n\n<li>In a coordinate covalent bond, one atom provides both electrons needed to form the bond, unlike a regular covalent bond, where each atom contributes one electron.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Final Product<\/strong>:<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The product of this reaction is <strong>POCl\u2083<\/strong>, where the phosphorus atom has an expanded octet (it can accommodate more than eight electrons in its valence shell, thanks to its position in the third period of the periodic table). The oxygen atom is bonded to phosphorus via a coordinate covalent bond, completing the molecular structure of POCl\u2083.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Summary:<\/h3>\n\n\n\n<p>In this reaction, the PCl\u2083 molecule reacts with oxygen to form POCl\u2083, and during this process, a coordinate covalent bond is formed between the phosphorus and the oxygen atom. The oxygen donates a lone pair of electrons to phosphorus, forming a dative bond and resulting in the tetrahedral molecular structure of POCl\u2083.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>form POCl3-in co-ordinate covalent bond. PCl3 +1\/2O2 &#8212;&#8212;POCl3 The Correct Answer and Explanation is : The reaction you have described is the formation of phosphorus oxychloride (POCl\u2083) from phosphorus trichloride (PCl\u2083) and oxygen gas (O\u2082): [ \\text{PCl}_3 + \\frac{1}{2} \\text{O}_2 \\rightarrow \\text{POCl}_3 ] Step-by-step Explanation: Summary: In this reaction, the PCl\u2083 molecule reacts with oxygen [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-190121","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/190121","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=190121"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/190121\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=190121"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=190121"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=190121"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}