{"id":190236,"date":"2025-02-11T18:40:41","date_gmt":"2025-02-11T18:40:41","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=190236"},"modified":"2025-02-11T18:40:44","modified_gmt":"2025-02-11T18:40:44","slug":"draw-the-correct-bond-line-structure-for-the-following-compound","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/11\/draw-the-correct-bond-line-structure-for-the-following-compound\/","title":{"rendered":"Draw the correct bond-line structure for the following compound"},"content":{"rendered":"\n<p>Draw the correct bond-line structure for the following compound:<br>(CH3CH2)3COH<\/p>\n\n\n\n<p>Draw the correct bond-line structure for the following compound:<br>(CH3)2CHCH2OH<\/p>\n\n\n\n<p>Draw the correct bond-line structure for the following compound:<br>CH3CH2CH2OCH3<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>Let me provide the correct bond-line structures for each of the compounds you mentioned.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">1. <strong>(CH\u2083CH\u2082)\u2083COH<\/strong><\/h3>\n\n\n\n<p>This compound is a primary alcohol with a central carbon bonded to three ethyl (CH\u2083CH\u2082) groups and a hydroxyl group (-OH).<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">Bond-line structure:<\/h4>\n\n\n\n<pre class=\"wp-block-code\"><code>      CH\u2082CH\u2083\n       |\nCH\u2083CH\u2082-C-OH\n       |\n      CH\u2082CH\u2083<\/code><\/pre>\n\n\n\n<p>Explanation: The central carbon is attached to three ethyl groups and a hydroxyl group. In the bond-line structure, carbon atoms and hydrogen atoms bonded to them are implied. The hydroxyl group (-OH) is at the end of the chain.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">2. <strong>(CH\u2083)\u2082CHCH\u2082OH<\/strong><\/h3>\n\n\n\n<p>This compound is an alcohol with a secondary carbon attached to a hydroxyl group and a methyl group, a propyl group.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">Bond-line structure:<\/h4>\n\n\n\n<pre class=\"wp-block-code\"><code>    CH\u2083\n     |\nCH\u2083-CH-CH\u2082OH<\/code><\/pre>\n\n\n\n<p>Explanation: The structure has a secondary alcohol, where the central carbon (C) is bonded to two methyl groups (CH\u2083) and a -CH\u2082OH group. The bond-line structure omits hydrogen atoms bonded to carbon atoms, making it simpler. The hydroxyl group (-OH) is on the terminal carbon.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">3. <strong>CH\u2083CH\u2082CH\u2082OCH\u2083<\/strong><\/h3>\n\n\n\n<p>This is an ether with an ethoxy group (CH\u2082CH\u2082CH\u2083) attached to a methyl group (CH\u2083).<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">Bond-line structure:<\/h4>\n\n\n\n<pre class=\"wp-block-code\"><code>CH\u2083-CH\u2082-CH\u2082-O-CH\u2083<\/code><\/pre>\n\n\n\n<p>Explanation: In this ether, the oxygen (O) atom connects an ethyl group (CH\u2082CH\u2082CH\u2083) to a methyl group (CH\u2083). The bond-line structure implies that each carbon atom is saturated with hydrogen atoms, and the oxygen is shown as a single bond connecting the two alkyl groups.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">General Explanation:<\/h3>\n\n\n\n<p>Bond-line structures are simplified representations of organic molecules where carbon atoms are implied at the junctions or ends of bonds. Hydrogen atoms attached to carbon atoms are also omitted to make the structure clearer. The hydroxyl group (-OH) in alcohols is typically shown at the end of the chain, while ether linkages (-O-) are represented as a single bond between oxygen and two alkyl groups. These structures help visualize the molecule&#8217;s skeleton without needing to explicitly write out every atom.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Draw the correct bond-line structure for the following compound:(CH3CH2)3COH Draw the correct bond-line structure for the following compound:(CH3)2CHCH2OH Draw the correct bond-line structure for the following compound:CH3CH2CH2OCH3 The Correct Answer and Explanation is : Let me provide the correct bond-line structures for each of the compounds you mentioned. 1. (CH\u2083CH\u2082)\u2083COH This compound is a primary [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-190236","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/190236","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=190236"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/190236\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=190236"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=190236"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=190236"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}