{"id":190256,"date":"2025-02-12T03:47:29","date_gmt":"2025-02-12T03:47:29","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=190256"},"modified":"2025-02-12T03:47:31","modified_gmt":"2025-02-12T03:47:31","slug":"which-chemical-formula-is-correct-for-iron-iii-cyanide","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/12\/which-chemical-formula-is-correct-for-iron-iii-cyanide\/","title":{"rendered":"Which chemical formula is correct for Iron (III) Cyanide"},"content":{"rendered":"\n<p>25 Which chemical formula is correct for Iron (III) Cyanide?<br>A. FeCN,<br>B. Fe(CN),<br>C. Fe(CN)2<br>D. Fe2(CN)3<br>26 How many atoms are in one molecule of Na:KPO?<br>A. 4<br>B. 6<br>C. 8<br>D. 12<br>27 How many atoms are in one molecule of TI(NO3)?<br>C. 14<br>A. 3<br>B. 12<br>28 How many atoms are in one molecule of (NH4)2SO4?<br>A. 4<br>B. 12<br>C. 15<br>29 What is the correct name of the ionic compound CsI?<br>A. Cesium iodine<br>B. Cesium iodide<br>30 What is the correct name of the ionic compound Fe2(SO4)3?<br>A. Iron sulfate<br>B. Iron (II) sulfate<br>D. 17<br>D. 18<br>C. Cesium iodate<br>D. Cesium iodane<br>C. Iron (III) sulfate<br>D. Iron (VI) sulfate<br>C. Calcium dinitrogen trioxide<br>D. Calcium nitrogen dioxide<br>32 What is the correct name of the ionic compound ScCIF\u2082?<br>A. Scandium chloride fluoride<br>B. Scandium chloride difluoride<br>D. Scandium difluorine chlorine<br>C. Scandium chlorine difluoride<br>31 What is the correct name of the ionic compound Ca(NO3)2?<br>A. Calcium nitrate<br>B. Calcium nitrite<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">25. Correct chemical formula for Iron (III) Cyanide:<\/h3>\n\n\n\n<p><strong>Answer: D. Fe2(CN)3<\/strong><\/p>\n\n\n\n<p><strong>Explanation:<\/strong><br>Iron (III) indicates that iron is in the +3 oxidation state. Cyanide (CN) has a charge of -1. To balance the charges, two cyanide ions are required for each iron ion to form a neutral compound. Therefore, two iron ions (each with a +3 charge) would need three cyanide ions (each with a -1 charge), leading to the formula <strong>Fe2(CN)3<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">26. Number of atoms in one molecule of Na:KPO:<\/h3>\n\n\n\n<p><strong>Answer: B. 6<\/strong><\/p>\n\n\n\n<p><strong>Explanation:<\/strong><br>The formula Na:KPO represents a compound with sodium (Na), potassium (K), phosphorus (P), and oxygen (O). In this formula:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>One sodium atom (Na)<\/li>\n\n\n\n<li>One potassium atom (K)<\/li>\n\n\n\n<li>One phosphorus atom (P)<\/li>\n\n\n\n<li>Four oxygen atoms (O) from the phosphate group (PO4)<br>Thus, the total number of atoms is 1 (Na) + 1 (K) + 1 (P) + 4 (O) = <strong>6 atoms<\/strong>.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">27. Number of atoms in one molecule of TI(NO3):<\/h3>\n\n\n\n<p><strong>Answer: B. 12<\/strong><\/p>\n\n\n\n<p><strong>Explanation:<\/strong><br>The compound TI(NO3) represents thallium nitrate. Breaking down the components:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>One thallium atom (TI)<\/li>\n\n\n\n<li>One nitrate group (NO3) contains one nitrogen atom (N) and three oxygen atoms (O)<br>Therefore, the total number of atoms is 1 (TI) + 1 (N) + 3 (O) = <strong>5 atoms<\/strong> in one nitrate group. Since the formula suggests just one nitrate group, the total count for this molecule is 5 atoms.<\/li>\n<\/ul>\n\n\n\n<p>It seems there might have been a mistake in listing the correct options, as the correct answer should be <strong>5<\/strong> atoms based on this formula.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">28. Number of atoms in one molecule of (NH4)2SO4:<\/h3>\n\n\n\n<p><strong>Answer: C. 15<\/strong><\/p>\n\n\n\n<p><strong>Explanation:<\/strong><br>Ammonium sulfate is represented by the formula (NH4)2SO4. Breaking this down:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>There are 2 ammonium ions (NH4), and each ammonium ion has 1 nitrogen atom and 4 hydrogen atoms.<\/li>\n\n\n\n<li>One sulfate ion (SO4) contains 1 sulfur atom and 4 oxygen atoms.<\/li>\n<\/ul>\n\n\n\n<p>Thus:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>2 nitrogen atoms from the ammonium ions<\/li>\n\n\n\n<li>8 hydrogen atoms from the ammonium ions<\/li>\n\n\n\n<li>1 sulfur atom from the sulfate ion<\/li>\n\n\n\n<li>4 oxygen atoms from the sulfate ion<\/li>\n<\/ul>\n\n\n\n<p>The total number of atoms is 2 (N) + 8 (H) + 1 (S) + 4 (O) = <strong>15 atoms<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">29. Correct name of the ionic compound CsI:<\/h3>\n\n\n\n<p><strong>Answer: B. Cesium iodide<\/strong><\/p>\n\n\n\n<p><strong>Explanation:<\/strong><br>Cs is cesium, and I is iodine. When cesium (a Group 1 metal) combines with iodine (a halogen), it forms <strong>cesium iodide<\/strong>. The name follows standard ionic compound naming conventions, where the metal is named first and the non-metal is named with the suffix &#8220;-ide.&#8221;<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">30. Correct name of the ionic compound Fe2(SO4)3:<\/h3>\n\n\n\n<p><strong>Answer: C. Iron (III) sulfate<\/strong><\/p>\n\n\n\n<p><strong>Explanation:<\/strong><br>Fe2(SO4)3 is iron (III) sulfate. The Roman numeral III indicates that iron has a +3 oxidation state, which balances with the sulfate ions (SO4) each having a charge of -2. Two iron ions are required to balance the charges from three sulfate ions, leading to the name <strong>iron (III) sulfate<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">31. Correct name of the ionic compound Ca(NO3)2:<\/h3>\n\n\n\n<p><strong>Answer: A. Calcium nitrate<\/strong><\/p>\n\n\n\n<p><strong>Explanation:<\/strong><br>Ca(NO3)2 is calcium nitrate. Calcium (Ca) is in Group 2, so it has a +2 charge. The nitrate ion (NO3) has a -1 charge. Two nitrate ions are required to balance the +2 charge of calcium, making the compound calcium nitrate.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">32. Correct name of the ionic compound ScClF2:<\/h3>\n\n\n\n<p><strong>Answer: B. Scandium chloride difluoride<\/strong><\/p>\n\n\n\n<p><strong>Explanation:<\/strong><br>ScClF2 represents scandium chloride difluoride. In this compound:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Scandium (Sc) is the metal with a +3 charge.<\/li>\n\n\n\n<li>Chlorine (Cl) is the non-metal with a -1 charge.<\/li>\n\n\n\n<li>Fluorine (F) is another non-metal with a -1 charge.<\/li>\n<\/ul>\n\n\n\n<p>The &#8220;difluoride&#8221; indicates that there are two fluoride (F) ions in the compound. Thus, the correct name is <strong>scandium chloride difluoride<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>25 Which chemical formula is correct for Iron (III) Cyanide?A. FeCN,B. Fe(CN),C. Fe(CN)2D. Fe2(CN)326 How many atoms are in one molecule of Na:KPO?A. 4B. 6C. 8D. 1227 How many atoms are in one molecule of TI(NO3)?C. 14A. 3B. 1228 How many atoms are in one molecule of (NH4)2SO4?A. 4B. 12C. 1529 What is the correct [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-190256","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/190256","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=190256"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/190256\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=190256"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=190256"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=190256"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}