{"id":190299,"date":"2025-02-12T06:03:12","date_gmt":"2025-02-12T06:03:12","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=190299"},"modified":"2025-02-12T06:03:14","modified_gmt":"2025-02-12T06:03:14","slug":"referring-only-to-a-periodic-table-give-the-ionic-charge-expected-for-each-of-these-representative-elements","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/12\/referring-only-to-a-periodic-table-give-the-ionic-charge-expected-for-each-of-these-representative-elements\/","title":{"rendered":"Referring only to a periodic table, give the ionic charge expected for each of these representative elements"},"content":{"rendered":"\n<p>Referring only to a periodic table, give the ionic charge expected for each of these representative elements: (a) S, (b) K, (c) Br, (d) N, (e) Mg, (f) Ne, (g) C, and (h) Al. Write the Lewis symbols and structures that show how Na2O forms from sodium and oxygen atoms.<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>Here are the expected ionic charges for each of the representative elements based on their position in the periodic table:<\/p>\n\n\n\n<p>(a) <strong>S (Sulfur)<\/strong>:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Sulfur is in Group 16 (also known as Group VIA) of the periodic table. It has 6 valence electrons. Since nonmetals tend to gain electrons to achieve a stable octet configuration, sulfur will gain 2 electrons to form an ion with a charge of <strong>-2<\/strong>.<br>Ionic charge: <strong>-2<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p>(b) <strong>K (Potassium)<\/strong>:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Potassium is in Group 1 (Group IA), and it has 1 valence electron. Metals tend to lose electrons to achieve a stable configuration. Potassium will lose 1 electron to form an ion with a charge of <strong>+1<\/strong>.<br>Ionic charge: <strong>+1<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p>(c) <strong>Br (Bromine)<\/strong>:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Bromine is in Group 17 (Group VIIA), with 7 valence electrons. As a nonmetal, bromine will gain 1 electron to complete its octet, forming an ion with a charge of <strong>-1<\/strong>.<br>Ionic charge: <strong>-1<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p>(d) <strong>N (Nitrogen)<\/strong>:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Nitrogen is in Group 15 (Group VA) and has 5 valence electrons. To achieve a stable octet, nitrogen will gain 3 electrons and form an ion with a charge of <strong>-3<\/strong>.<br>Ionic charge: <strong>-3<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p>(e) <strong>Mg (Magnesium)<\/strong>:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Magnesium is in Group 2 (Group IIA), and it has 2 valence electrons. Magnesium will lose 2 electrons to form an ion with a charge of <strong>+2<\/strong>.<br>Ionic charge: <strong>+2<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p>(f) <strong>Ne (Neon)<\/strong>:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Neon is in Group 18 (Group VIIIA), and it has 8 valence electrons, making it a noble gas with a stable octet. It does not form an ion because it is already stable.<br>Ionic charge: <strong>0<\/strong> (neutral).<\/li>\n<\/ul>\n\n\n\n<p>(g) <strong>C (Carbon)<\/strong>:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Carbon is in Group 14 (Group IVA) and has 4 valence electrons. Carbon can either gain 4 electrons to form an ion with a charge of <strong>-4<\/strong>, or it can lose 4 electrons to form an ion with a charge of <strong>+4<\/strong>. However, it typically forms covalent bonds, so the charge is usually considered neutral.<br>Ionic charge: <strong>0<\/strong> or <strong>+4<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p>(h) <strong>Al (Aluminum)<\/strong>:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Aluminum is in Group 13 (Group IIIA) and has 3 valence electrons. Aluminum will lose 3 electrons to form an ion with a charge of <strong>+3<\/strong>.<br>Ionic charge: <strong>+3<\/strong>.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Formation of Na2O from Sodium and Oxygen:<\/h3>\n\n\n\n<p><strong>Sodium (Na)<\/strong> has 1 valence electron, and <strong>Oxygen (O)<\/strong> has 6 valence electrons.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li>Each sodium atom loses 1 electron to form Na\u207a ions (each with a +1 charge).<\/li>\n\n\n\n<li>Oxygen gains 2 electrons to form an O\u00b2\u207b ion (with a -2 charge).<\/li>\n<\/ol>\n\n\n\n<p>Since 2 sodium atoms (each with +1 charge) balance the charge of 1 oxygen atom (with a -2 charge), the formula for the compound formed is <strong>Na\u2082O<\/strong>.<\/p>\n\n\n\n<p><strong>Lewis Structures:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Sodium: Na \u2192 [Na]\u207a (after losing 1 electron).<\/li>\n\n\n\n<li>Oxygen: O \u2192 [O]\u00b2\u207b (after gaining 2 electrons).<\/li>\n<\/ul>\n\n\n\n<p>I&#8217;ll generate the Lewis structure showing this process now.<\/p>\n\n\n\n<p>Here is the Lewis structure showing how Na\u2082O forms from sodium (Na) and oxygen (O) atoms. Two sodium atoms each lose one electron to form Na\u207a ions, and one oxygen atom gains two electrons to form an O\u00b2\u207b ion. This results in the formation of the ionic compound Na\u2082O.<\/p>\n\n\n\n<p>Let me know if you&#8217;d like further details or have additional questions!<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/02\/image-353.png\" alt=\"\" class=\"wp-image-190300\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Referring only to a periodic table, give the ionic charge expected for each of these representative elements: (a) S, (b) K, (c) Br, (d) N, (e) Mg, (f) Ne, (g) C, and (h) Al. Write the Lewis symbols and structures that show how Na2O forms from sodium and oxygen atoms. The Correct Answer and Explanation [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-190299","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/190299","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=190299"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/190299\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=190299"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=190299"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=190299"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}