{"id":190312,"date":"2025-02-12T06:12:59","date_gmt":"2025-02-12T06:12:59","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=190312"},"modified":"2025-02-12T06:13:02","modified_gmt":"2025-02-12T06:13:02","slug":"predict-product-b-for-the-following-reaction-sequence-below","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/12\/predict-product-b-for-the-following-reaction-sequence-below\/","title":{"rendered":"Predict product B for the following reaction sequence below"},"content":{"rendered":"\n

Predict product B for the following reaction sequence below. 2-methyl-2-butene + water –> A (if any) <\/p>\n\n\n\n

A A tertiary alcohol <\/p>\n\n\n\n

B A secondary alcohol <\/p>\n\n\n\n

C An ester <\/p>\n\n\n\n

D A carboxylic Acid <\/p>\n\n\n\n

E A ketone <\/p>\n\n\n\n

F A aldehyde<\/p>\n\n\n\n

The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n

The correct answer to this reaction is B: A secondary alcohol<\/strong>.<\/p>\n\n\n\n

Explanation:<\/h3>\n\n\n\n

The reaction sequence provided involves 2-methyl-2-butene<\/strong> reacting with water<\/strong>.<\/p>\n\n\n\n

    \n
  1. Starting compound: 2-methyl-2-butene<\/strong><\/li>\n<\/ol>\n\n\n\n
      \n
    • The structure of 2-methyl-2-butene<\/strong> is an alkene with the following structure:
      [
      CH_3-C(=CH_2)-CH_2-CH_3
      ]
      This molecule has a double bond between the second and third carbons, with a methyl group attached to the second carbon.<\/li>\n<\/ul>\n\n\n\n
        \n
      1. Reaction with water (Hydration)<\/strong><\/li>\n<\/ol>\n\n\n\n
          \n
        • The reaction is a typical acid-catalyzed hydration of an alkene, where the alkene undergoes an electrophilic addition with water in the presence of an acid (e.g., H\u2082SO\u2084).<\/li>\n\n\n\n
        • In this case, the hydration will follow Markovnikov’s Rule<\/strong>, which states that the proton (H\u207a) will add to the carbon of the double bond that has the greater number of hydrogen atoms (the more substituted carbon).<\/li>\n\n\n\n
        • The alkene 2-methyl-2-butene<\/strong> has the double bond between the second and third carbons. The more substituted carbon (the second carbon) will preferentially bond with the proton from water. The hydroxyl group (-OH) will then add to the carbon with fewer hydrogens (the third carbon).<\/li>\n<\/ul>\n\n\n\n
            \n
          1. Resulting product:<\/strong><\/li>\n<\/ol>\n\n\n\n
              \n
            • The product of this reaction will be a secondary alcohol<\/strong>, specifically 2-methyl-2-butanol<\/strong>. The structure of this alcohol is:
              [
              CH_3-CH(OH)-CH_2-CH_3
              ]
              This is a secondary alcohol because the hydroxyl group (-OH) is attached to a carbon that is connected to two other carbons.<\/li>\n<\/ul>\n\n\n\n

              Therefore, the answer is B: A secondary alcohol<\/strong>.<\/p>\n\n\n\n

              Let me go ahead and generate the image for the reaction mechanism.<\/p>\n\n\n\n

              Here’s the chemical diagram showing the reaction of 2-methyl-2-butene with water, leading to the formation of 2-methyl-2-butanol, a secondary alcohol. This diagram illustrates the process of Markovnikov addition, where the proton adds to the more substituted carbon of the alkene, resulting in the formation of the alcohol.<\/p>\n\n\n\n

              Let me know if you’d like more details or have any further questions!<\/p>\n\n\n\n

              \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

              Predict product B for the following reaction sequence below. 2-methyl-2-butene + water –> A (if any) A A tertiary alcohol B A secondary alcohol C An ester D A carboxylic Acid E A ketone F A aldehyde The Correct Answer and Explanation is : The correct answer to this reaction is B: A secondary alcohol. […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-190312","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/190312","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=190312"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/190312\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=190312"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=190312"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=190312"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}