{"id":190771,"date":"2025-02-13T08:18:18","date_gmt":"2025-02-13T08:18:18","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=190771"},"modified":"2025-02-13T08:18:20","modified_gmt":"2025-02-13T08:18:20","slug":"draw-d-allose-the-c3-epimer-of-glucose","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/13\/draw-d-allose-the-c3-epimer-of-glucose\/","title":{"rendered":"Draw D-allose, the C3 epimer of glucose"},"content":{"rendered":"\n<p>(a) Draw D-allose, the C3 epimer of glucose.<\/p>\n\n\n\n<p>(b) Draw D-talose, the C2 epimer of D-galactose.<\/p>\n\n\n\n<p>(c) Draw D-idose, the C3 epimer of D-talose. Now compare your answers with Figure 23-3.<\/p>\n\n\n\n<p>(d) Draw the C4 \u201cepimer\u201d of D-xylose. Notice that this \u201cepimer\u201d is actually an L-series<\/p>\n\n\n\n<p>sugar, and we have seen its enantiomer. Give the correct name for this L-series sugar.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/02\/image-460.png\" alt=\"\" class=\"wp-image-190772\"\/><\/figure>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>Let&#8217;s break this down step by step and provide both the correct structures and an explanation.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">(a) D-Allose (C3 Epimer of D-Glucose)<\/h3>\n\n\n\n<p>D-Allose is an aldohexose and a C3 epimer of D-Glucose. This means that the hydroxyl (-OH) group at carbon 3 is flipped compared to D-Glucose.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">(b) D-Talose (C2 Epimer of D-Galactose)<\/h3>\n\n\n\n<p>D-Talose is another aldohexose and is a C2 epimer of D-Galactose. This means that the hydroxyl (-OH) group at carbon 2 is flipped compared to D-Galactose.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">(c) D-Idose (C3 Epimer of D-Talose)<\/h3>\n\n\n\n<p>D-Idose is obtained by flipping the hydroxyl (-OH) group at carbon 3 of D-Talose.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">(d) C4 \u201cEpimer\u201d of D-Xylose<\/h3>\n\n\n\n<p>D-Xylose is an aldopentose. If we attempt to create its C4 epimer, we actually obtain an L-series sugar. This sugar is L-Lyxose, which is the enantiomer of D-Lyxose.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation (300 Words)<\/h3>\n\n\n\n<p>Epimers are sugars that differ only at one specific chiral center, meaning that just one carbon has an opposite configuration. For example, D-Allose is the C3 epimer of D-Glucose, meaning that they are identical except for the configuration at the third carbon.<\/p>\n\n\n\n<p>Similarly, D-Talose is the C2 epimer of D-Galactose, so the hydroxyl (-OH) group at carbon 2 in D-Talose is flipped compared to D-Galactose.<\/p>\n\n\n\n<p>To determine D-Idose, we take D-Talose and modify the hydroxyl (-OH) configuration at the third carbon, producing a new sugar with distinct stereochemistry. This type of systematic modification helps understand the relationship between different aldohexoses.<\/p>\n\n\n\n<p>For D-Xylose, if we modify the hydroxyl (-OH) group at C4, we get an L-series sugar instead of a D-series sugar. This means the sugar belongs to the mirror-image family of common D-sugars. In this case, the correct name for the sugar is L-Lyxose, which is the enantiomer of D-Lyxose.<\/p>\n\n\n\n<p>This exercise demonstrates how systematically modifying stereochemistry affects sugar classification and highlights the interrelationships between different monosaccharides.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p>Now, I will generate the images for these structures.<\/p>\n\n\n\n<p>It looks like I can&#8217;t generate the molecular structures directly with RDKit here. However, I can manually illustrate the Fischer projections of D-Allose, D-Talose, D-Idose, and L-Lyxose. Let me generate an image with these structures for you.<\/p>\n\n\n\n<p>Here is the scientific diagram featuring the Fischer projections of D-Allose, D-Talose, D-Idose, and L-Lyxose. Let me know if you need any modifications or explanations!<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/02\/image-461.png\" alt=\"\" class=\"wp-image-190773\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>(a) Draw D-allose, the C3 epimer of glucose. (b) Draw D-talose, the C2 epimer of D-galactose. (c) Draw D-idose, the C3 epimer of D-talose. Now compare your answers with Figure 23-3. (d) Draw the C4 \u201cepimer\u201d of D-xylose. Notice that this \u201cepimer\u201d is actually an L-series sugar, and we have seen its enantiomer. Give the [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-190771","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/190771","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=190771"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/190771\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=190771"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=190771"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=190771"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}