{"id":190878,"date":"2025-02-13T10:16:07","date_gmt":"2025-02-13T10:16:07","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=190878"},"modified":"2025-02-13T10:16:10","modified_gmt":"2025-02-13T10:16:10","slug":"dibenzalacetone-molecular-weight-234-2980-acetone-benzaldehyde","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/13\/dibenzalacetone-molecular-weight-234-2980-acetone-benzaldehyde\/","title":{"rendered":"dibenzalacetone Molecular Weight: 234.2980 acetone benzaldehyde"},"content":{"rendered":"\n<p> + dibenzalacetone Molecular Weight: 234.2980 acetone benzaldehyde<\/p>\n\n\n\n<p>Mechanism for the reaction.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/02\/image-485.png\" alt=\"\" class=\"wp-image-190879\"\/><\/figure>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>The reaction you are referring to is the <strong>Claisen-Schmidt condensation<\/strong>, a type of aldol condensation that forms <strong>dibenzalacetone<\/strong> from acetone and benzaldehyde in the presence of a base.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Mechanism of Dibenzalacetone Formation<\/strong><\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Enolate Formation:<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Acetone (CH\u2083COCH\u2083) is deprotonated at the \u03b1-carbon by a base (usually NaOH or KOH), forming an <strong>enolate ion<\/strong>.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Nucleophilic Attack on Benzaldehyde:<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The enolate ion attacks the electrophilic <strong>carbonyl carbon of benzaldehyde (C\u2086H\u2085CHO)<\/strong>, forming a \u03b2-hydroxyketone intermediate.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Dehydration to Form \u03b1,\u03b2-Unsaturated Ketone:<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The \u03b2-hydroxyketone undergoes elimination of water (<strong>E1cB mechanism<\/strong>) to form <strong>benzalacetone<\/strong> (C\u2086H\u2085CH=CHCOCH\u2083).<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Second Aldol Condensation:<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Another molecule of benzaldehyde reacts with benzalacetone, following the same steps.<\/li>\n\n\n\n<li>This results in the final product: <strong>dibenzalacetone (C\u2086H\u2085CH=CHCOCH=CHC\u2086H\u2085).<\/strong><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation (300 Words)<\/strong><\/h3>\n\n\n\n<p>The reaction between <strong>benzaldehyde and acetone<\/strong> under basic conditions is an example of a <strong>Claisen-Schmidt condensation<\/strong>, a widely used method to form \u03b1,\u03b2-unsaturated carbonyl compounds. The process begins with the <strong>deprotonation of acetone<\/strong> at the \u03b1-carbon, forming a resonance-stabilized enolate. This enolate acts as a nucleophile and attacks the carbonyl carbon of benzaldehyde, leading to a <strong>\u03b2-hydroxyketone intermediate<\/strong>.<\/p>\n\n\n\n<p>Under basic conditions, the intermediate readily undergoes <strong>dehydration<\/strong>, losing a water molecule to form <strong>benzalacetone<\/strong>, which has a conjugated double bond system. However, since acetone has two \u03b1-hydrogens, another molecule of benzaldehyde can undergo the same condensation reaction with benzalacetone. This second reaction leads to <strong>dibenzalacetone<\/strong>, a yellow solid widely used in organic synthesis and UV-blocking applications.<\/p>\n\n\n\n<p>The overall reaction follows the <strong>E1cB mechanism<\/strong>, where the \u03b2-hydroxyketone intermediate forms a stabilized carbanion before eliminating a hydroxide ion. This step is favored under strongly basic conditions because the conjugated product is more stable than the intermediate.<\/p>\n\n\n\n<p>The reaction is <strong>highly selective<\/strong>, as benzaldehyde lacks an \u03b1-hydrogen, preventing self-condensation. The base <strong>catalyzes the reaction<\/strong>, but it does not get consumed in the process. The efficiency of the reaction depends on the <strong>molar ratio of reactants<\/strong>, the <strong>strength of the base<\/strong>, and <strong>reaction temperature<\/strong>.<\/p>\n\n\n\n<p>This synthesis is a crucial example in organic chemistry, demonstrating principles of <strong>nucleophilic addition, enolate chemistry, and conjugation stabilization<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>+ dibenzalacetone Molecular Weight: 234.2980 acetone benzaldehyde Mechanism for the reaction. The Correct Answer and Explanation is : The reaction you are referring to is the Claisen-Schmidt condensation, a type of aldol condensation that forms dibenzalacetone from acetone and benzaldehyde in the presence of a base. Mechanism of Dibenzalacetone Formation Explanation (300 Words) The reaction [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-190878","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/190878","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=190878"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/190878\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=190878"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=190878"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=190878"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}