{"id":191027,"date":"2025-02-14T05:22:37","date_gmt":"2025-02-14T05:22:37","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=191027"},"modified":"2025-02-14T05:22:40","modified_gmt":"2025-02-14T05:22:40","slug":"graph-of-actual-position-versus-time-data-for-a-particular-type-of-drag-racer-known-as-a-funny-car","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/14\/graph-of-actual-position-versus-time-data-for-a-particular-type-of-drag-racer-known-as-a-funny-car\/","title":{"rendered":"graph of actual position-versus-time data for a particular type of drag racer known as a \u201cfunny car\u201d"},"content":{"rendered":"\n<p>Figure P2.20 shows a graph of actual position-versus-time data for a particular type of drag racer known as a \u201cfunny car.\u201d<\/p>\n\n\n\n<p>a. Estimate the car\u2019s velocity at 2.0 s.<\/p>\n\n\n\n<p>b. Estimate the car\u2019s velocity at 4.0 s.<\/p>\n\n\n\n<p>Figure P2.21 shows the velocity graph of a bicycle. Draw the bicycle\u2019s acceleration graph for the interval 0 s \u2026 t \u2026 4 s. Give both axes an appropriate numerical scale.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/02\/image-506.png\" alt=\"\" class=\"wp-image-191028\"\/><\/figure>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>To address the given problems, we need to analyze the position-versus-time graph (Figure P2.20) and the velocity-versus-time graph (Figure P2.21) provided in the link.<\/p>\n\n\n\n<p><strong>Part (a): Estimating the Car\u2019s Velocity at 2.0 Seconds<\/strong><\/p>\n\n\n\n<p>In a position-versus-time graph, the slope at any point represents the object&#8217;s instantaneous velocity at that specific time. To estimate the car&#8217;s velocity at 2.0 seconds, we should determine the slope of the tangent line to the curve at that point.<\/p>\n\n\n\n<p><strong>Steps to Estimate the Velocity:<\/strong><\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Identify the Point:<\/strong> Locate the point on the graph where ( t = 2.0 \\, \\text{s} ).<\/li>\n\n\n\n<li><strong>Draw a Tangent Line:<\/strong> At this point, draw a line that just touches the curve without intersecting it nearby. This line represents the instantaneous rate of change of position with respect to time at ( t = 2.0 \\, \\text{s} ).<\/li>\n\n\n\n<li><strong>Calculate the Slope:<\/strong> Select two points on the tangent line, preferably equidistant from ( t = 2.0 \\, \\text{s} ), and note their coordinates ((t_1, x_1)) and ((t_2, x_2)). The slope (velocity) is then calculated as: [<br>\\text{Velocity} = \\frac{\\Delta x}{\\Delta t} = \\frac{x_2 &#8211; x_1}{t_2 &#8211; t_1}<br>]<\/li>\n<\/ol>\n\n\n\n<p><strong>Example Calculation:<\/strong><\/p>\n\n\n\n<p>Assuming from the graph that at ( t = 1.5 \\, \\text{s} ), the position ( x = 100 \\, \\text{m} ), and at ( t = 2.5 \\, \\text{s} ), ( x = 300 \\, \\text{m} ):<\/p>\n\n\n\n<p>[<br>\\text{Velocity} = \\frac{300 \\, \\text{m} &#8211; 100 \\, \\text{m}}{2.5 \\, \\text{s} &#8211; 1.5 \\, \\text{s}} = \\frac{200 \\, \\text{m}}{1 \\, \\text{s}} = 200 \\, \\text{m\/s}<br>]<\/p>\n\n\n\n<p>Therefore, the estimated velocity of the car at 2.0 seconds is approximately ( 200 \\, \\text{m\/s} ).<\/p>\n\n\n\n<p><strong>Part (b): Estimating the Car\u2019s Velocity at 4.0 Seconds<\/strong><\/p>\n\n\n\n<p>Similarly, to estimate the velocity at ( t = 4.0 \\, \\text{s} ), repeat the above steps:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Identify the Point:<\/strong> Locate ( t = 4.0 \\, \\text{s} ) on the graph.<\/li>\n\n\n\n<li><strong>Draw a Tangent Line:<\/strong> Draw the tangent at this point.<\/li>\n\n\n\n<li><strong>Calculate the Slope:<\/strong> Choose two points on this tangent line and compute the slope.<\/li>\n<\/ol>\n\n\n\n<p><strong>Example Calculation:<\/strong><\/p>\n\n\n\n<p>If at ( t = 3.5 \\, \\text{s} ), ( x = 800 \\, \\text{m} ), and at ( t = 4.5 \\, \\text{s} ), ( x = 1300 \\, \\text{m} ):<\/p>\n\n\n\n<p>[<br>\\text{Velocity} = \\frac{1300 \\, \\text{m} &#8211; 800 \\, \\text{m}}{4.5 \\, \\text{s} &#8211; 3.5 \\, \\text{s}} = \\frac{500 \\, \\text{m}}{1 \\, \\text{s}} = 500 \\, \\text{m\/s}<br>]<\/p>\n\n\n\n<p>Thus, the estimated velocity at 4.0 seconds is approximately ( 500 \\, \\text{m\/s} ).<\/p>\n\n\n\n<p><strong>Part (c): Drawing the Bicycle\u2019s Acceleration Graph for 0 s \u2264 t \u2264 4 s<\/strong><\/p>\n\n\n\n<p>In a velocity-versus-time graph, the slope at any point represents the object&#8217;s acceleration at that time. To draw the acceleration graph:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Analyze the Slope:<\/strong> Examine the velocity graph between 0 and 4 seconds to determine how the slope (acceleration) changes over time.<\/li>\n\n\n\n<li><strong>Plot Acceleration:<\/strong> Create a new graph with time (t) on the horizontal axis and acceleration (a) on the vertical axis. Plot the calculated acceleration values corresponding to each time interval.<\/li>\n<\/ol>\n\n\n\n<p><strong>Example Analysis:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>From 0 to 1 second:<\/strong> If the velocity increases linearly from 0 to 10 m\/s, the slope is: [<br>a = \\frac{10 \\, \\text{m\/s} &#8211; 0 \\, \\text{m\/s}}{1 \\, \\text{s} &#8211; 0 \\, \\text{s}} = 10 \\, \\text{m\/s}^2<br>]<\/li>\n\n\n\n<li><strong>From 1 to 3 seconds:<\/strong> If the velocity remains constant at 10 m\/s, the slope is: [<br>a = \\frac{10 \\, \\text{m\/s} &#8211; 10 \\, \\text{m\/s}}{3 \\, \\text{s} &#8211; 1 \\, \\text{s}} = 0 \\, \\text{m\/s}^2<br>]<\/li>\n\n\n\n<li><strong>From 3 to 4 seconds:<\/strong> If the velocity decreases linearly from 10 m\/s to 0 m\/s, the slope is: [<br>a = \\frac{0 \\, \\text{m\/s} &#8211; 10 \\, \\text{m\/s}}{4 \\, \\text{s} &#8211; 3 \\, \\text{s}} = -10 \\, \\text{m\/s}^2<br>]<\/li>\n<\/ul>\n\n\n\n<p><strong>Plotting the Acceleration Graph:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>0 to 1 s:<\/strong> Plot a horizontal line at ( a = 10 \\, \\text{m\/s}^2 ).<\/li>\n\n\n\n<li><strong>1 to 3 s:<\/strong> Plot a horizontal line at ( a = 0 \\, \\text{m\/s}^2 ).<\/li>\n\n\n\n<li><strong>3 to 4 s:<\/strong> Plot a horizontal line at ( a = -10 \\, \\text{m\/s}^2 ).<\/li>\n<\/ul>\n\n\n\n<p>This graph visually represents<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Figure P2.20 shows a graph of actual position-versus-time data for a particular type of drag racer known as a \u201cfunny car.\u201d a. Estimate the car\u2019s velocity at 2.0 s. b. Estimate the car\u2019s velocity at 4.0 s. Figure P2.21 shows the velocity graph of a bicycle. Draw the bicycle\u2019s acceleration graph for the interval 0 [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-191027","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/191027","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=191027"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/191027\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=191027"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=191027"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=191027"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}