{"id":191154,"date":"2025-02-14T07:59:01","date_gmt":"2025-02-14T07:59:01","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=191154"},"modified":"2025-02-14T07:59:04","modified_gmt":"2025-02-14T07:59:04","slug":"classify-the-following-molecules-into-chiral-o-achiral-oh-9","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/14\/classify-the-following-molecules-into-chiral-o-achiral-oh-9\/","title":{"rendered":"Classify the following molecules into chiral o achiral OH 9"},"content":{"rendered":"\n

Classify the following molecules into chiral o achiral OH 9. Draw an enantiomer of each of the following molecule: ?? SH H H2N 10. Draw a diastereomer of each of the following molecule: Br Br ? NH2 OH OH Br OH NH2 OH OH OH OH OH ???? OH NH2<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n

To classify the molecules as chiral or achiral, let’s first define the terms:<\/p>\n\n\n\n

    \n
  1. Chiral molecule<\/strong>: A molecule that lacks any symmetry and cannot be superimposed on its mirror image. Chiral molecules usually have at least one chiral center (a carbon atom bonded to four different groups).<\/li>\n\n\n\n
  2. Achiral molecule<\/strong>: A molecule that is superimposable on its mirror image, meaning it has symmetry (no chiral centers or it has a plane of symmetry).<\/li>\n<\/ol>\n\n\n\n

    The molecules you provided are described in a way that I will need to analyze. Since you\u2019ve included an image link but I can’t view it directly, I’ll address the typical types of molecules based on the descriptions. Let’s break down your request:<\/p>\n\n\n\n

      \n
    1. Molecule with SH, H, H2N groups<\/strong>:<\/li>\n<\/ol>\n\n\n\n
        \n
      • If this molecule has a central carbon (C) bonded to four different groups (SH, H, NH2, and the other group not specified), it would be chiral<\/strong> because it has no symmetry and cannot be superimposed on its mirror image. This would be a typical chiral center.<\/li>\n\n\n\n
      • Enantiomer<\/strong>: An enantiomer of this molecule would differ in the configuration of the chiral center. If the original configuration is R, the enantiomer would have the S configuration (or vice versa), meaning the arrangement of the groups around the chiral center would be reversed.<\/li>\n<\/ul>\n\n\n\n
          \n
        1. Molecule with Br, Br, NH2, OH groups<\/strong>:<\/li>\n<\/ol>\n\n\n\n
            \n
          • If this molecule has two identical groups (Br and Br), it cannot be chiral<\/strong>, since having two identical groups would lead to a plane of symmetry, making it achiral.<\/li>\n\n\n\n
          • Diastereomer<\/strong>: A diastereomer of this molecule would have a different spatial arrangement of the groups, but not be a mirror image. For example, one diastereomer could have one hydroxyl group at a different position, or the NH2 group may be located differently on the molecule.<\/li>\n<\/ul>\n\n\n\n
              \n
            1. Molecule with OH, NH2, OH groups<\/strong>:<\/li>\n<\/ol>\n\n\n\n
                \n
              • If this molecule has a carbon with a similar substitution pattern (e.g., OH, NH2, OH), it may also be achiral<\/strong>, as this could lead to symmetry. There might not be any chiral centers if the molecule has symmetry.<\/li>\n\n\n\n
              • Diastereomer<\/strong>: A diastereomer would again be a molecule with the same formula but with a different spatial arrangement of the functional groups. For example, the OH and NH2 groups could be in different positions relative to each other.<\/li>\n<\/ul>\n\n\n\n

                To summarize:<\/p>\n\n\n\n

                  \n
                • Chiral molecules have no symmetry and usually have a single chiral center.<\/li>\n\n\n\n
                • Achiral molecules have symmetry and cannot be chiral (e.g., molecules with identical substituents like two bromines).<\/li>\n\n\n\n
                • Enantiomers are non-superimposable mirror images, while diastereomers differ in their spatial arrangement but are not mirror images.<\/li>\n<\/ul>\n\n\n\n

                  Without the exact structures, this explanation focuses on the general concepts of chirality and stereoisomerism, which are essential for classification.<\/p>\n","protected":false},"excerpt":{"rendered":"

                  Classify the following molecules into chiral o achiral OH 9. Draw an enantiomer of each of the following molecule: ?? SH H H2N 10. Draw a diastereomer of each of the following molecule: Br Br ? NH2 OH OH Br OH NH2 OH OH OH OH OH ???? OH NH2 The Correct Answer and Explanation […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-191154","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/191154","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=191154"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/191154\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=191154"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=191154"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=191154"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}