{"id":191540,"date":"2025-02-15T07:52:53","date_gmt":"2025-02-15T07:52:53","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=191540"},"modified":"2025-02-15T07:52:56","modified_gmt":"2025-02-15T07:52:56","slug":"from-the-ip-address-192-168-10-1-and-the-subnet-mask-255-255-255-192","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/15\/from-the-ip-address-192-168-10-1-and-the-subnet-mask-255-255-255-192\/","title":{"rendered":"From the IP address 192.168.10.1 and the subnet mask 255.255.255.192"},"content":{"rendered":"\n<p>From the IP address 192.168.10.1 and the subnet mask 255.255.255.192; Answer the Questions below:\u00c3\u201a\u00c2<\/p>\n\n\n\n<p>How many bits been borrowed from the last octet from the subnet mask? *<\/p>\n\n\n\n<p>Is this address 192.168.10.192, a network address? *<\/p>\n\n\n\n<p>How many sub networks it will be? * \u00c3\u201a\u00c2 Is this address 192.168.10.190, a broadcast address? *<\/p>\n\n\n\n<p>How many IP hosts addresses will be in each sub network? *<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Answers<\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>How many bits have been borrowed from the last octet from the subnet mask?<\/strong><\/li>\n<\/ol>\n\n\n\n<p>The subnet mask given is <strong>255.255.255.192<\/strong>. In binary form, this subnet mask is:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>255 = <code>11111111<\/code><\/li>\n\n\n\n<li>255 = <code>11111111<\/code><\/li>\n\n\n\n<li>255 = <code>11111111<\/code><\/li>\n\n\n\n<li>192 = <code>11000000<\/code><\/li>\n<\/ul>\n\n\n\n<p>In the last octet (<code>192<\/code>), we see that the first two bits are <code>1<\/code> and the remaining six bits are <code>0<\/code>. This means that <strong>2 bits have been borrowed<\/strong> from the last octet.<\/p>\n\n\n\n<ol start=\"2\" class=\"wp-block-list\">\n<li><strong>Is the address 192.168.10.192 a network address?<\/strong><\/li>\n<\/ol>\n\n\n\n<p>To determine if the address <code>192.168.10.192<\/code> is a network address, we need to check if the host portion is all zeroes. Based on the subnet mask <code>255.255.255.192<\/code>, we have:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Network portion: 192.168.10.192 (the first 26 bits are network bits)<\/li>\n\n\n\n<li>Host portion: The remaining 6 bits are used for host addresses.<\/li>\n<\/ul>\n\n\n\n<p>Since the address <code>192.168.10.192<\/code> has the last 6 bits set to <code>000000<\/code>, this is the <strong>network address<\/strong> for the subnet <code>192.168.10.192\/26<\/code>.<\/p>\n\n\n\n<ol start=\"3\" class=\"wp-block-list\">\n<li><strong>How many sub-networks will there be?<\/strong><\/li>\n<\/ol>\n\n\n\n<p>The subnet mask <code>255.255.255.192<\/code> indicates that <strong>2 bits have been borrowed<\/strong> from the last octet. The total number of sub-networks created by borrowing bits is calculated as:<\/p>\n\n\n\n<p>[<br>2^2 = 4 \\text{ sub-networks}<br>]<\/p>\n\n\n\n<p>So, there will be <strong>4 sub-networks<\/strong>.<\/p>\n\n\n\n<ol start=\"4\" class=\"wp-block-list\">\n<li><strong>Is the address 192.168.10.190 a broadcast address?<\/strong><\/li>\n<\/ol>\n\n\n\n<p>The broadcast address for a subnet is the address where the host portion is all <code>1s<\/code>. For the subnet <code>192.168.10.192\/26<\/code>, the broadcast address would be <code>192.168.10.255<\/code>. The address <code>192.168.10.190<\/code> is <strong>not<\/strong> the broadcast address.<\/p>\n\n\n\n<ol start=\"5\" class=\"wp-block-list\">\n<li><strong>How many IP host addresses will be in each sub-network?<\/strong><\/li>\n<\/ol>\n\n\n\n<p>Each subnet has <strong>6 bits for host addresses<\/strong>, as determined from the subnet mask <code>255.255.255.192<\/code>. The number of available host IP addresses is calculated as:<\/p>\n\n\n\n<p>[<br>2^6 &#8211; 2 = 62 \\text{ IP addresses}<br>]<\/p>\n\n\n\n<p>The subtraction of 2 accounts for the network address and the broadcast address, which cannot be assigned to hosts.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">300-Word Explanation<\/h3>\n\n\n\n<p>A <strong>subnet mask<\/strong> helps divide an IP address into the network portion and the host portion. In this case, the subnet mask <code>255.255.255.192<\/code> divides the address into 26 bits for the network and 6 bits for the host. The first 26 bits (<code>11111111.11111111.11111111.11000000<\/code>) are fixed for the network, while the remaining 6 bits (<code>000000<\/code>) are for the host addresses.<\/p>\n\n\n\n<p><strong>Borrowing bits<\/strong> from the host portion increases the number of subnets by reducing the number of available IPs for hosts. By borrowing 2 bits (from the 6 bits reserved for hosts), we increase the number of subnets by <code>2^2 = 4<\/code>. This means that, with this subnet mask, we can create 4 subnets in total.<\/p>\n\n\n\n<p>Each of these subnets can support up to 62 host addresses. The formula <code>2^n - 2<\/code> (where <code>n<\/code> is the number of host bits) gives the number of usable host addresses in a subnet. The two subtracted addresses are reserved for the <strong>network address<\/strong> (which identifies the subnet itself) and the <strong>broadcast address<\/strong> (which is used to communicate with all devices on the subnet).<\/p>\n\n\n\n<p>In conclusion, the subnet mask <code>255.255.255.192<\/code> creates 4 subnets, each with 62 usable IP addresses for hosts. The network and broadcast addresses for each subnet cannot be used for devices.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p>Let me generate the image for you!<\/p>\n\n\n\n<p>Here is the subnetting diagram based on your question! It visually explains how the IP address <code>192.168.10.1<\/code> is split using the subnet mask <code>255.255.255.192<\/code>, the borrowed bits, subnets, network and broadcast addresses, and available host IPs in each subnet. Let me know if you&#8217;d like further clarification!<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/02\/image-586.png\" alt=\"\" class=\"wp-image-191541\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>From the IP address 192.168.10.1 and the subnet mask 255.255.255.192; Answer the Questions below:\u00c3\u201a\u00c2 How many bits been borrowed from the last octet from the subnet mask? * Is this address 192.168.10.192, a network address? * How many sub networks it will be? * \u00c3\u201a\u00c2 Is this address 192.168.10.190, a broadcast address? * How many [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-191540","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/191540","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=191540"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/191540\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=191540"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=191540"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=191540"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}