The concentration of bromic acid (HBrO3) is approximately 1.10 M<\/strong>.<\/p>\n\n\n\n To calculate the concentration of bromic acid, we use the stoichiometry of the reaction between strontium hydroxide (Sr(OH)2) and bromic acid (HBrO3):<\/p>\n\n\n\n [ From the balanced equation, we know that 1 mole of Sr(OH)2 reacts with 2 moles of HBrO3. Using the volume and molarity of Sr(OH)2, we can calculate the moles of Sr(OH)2 that reacted.<\/p>\n\n\n\n Thus, the concentration of bromic acid is approximately 1.10 M.<\/p>\n\n\n\n Now, I will generate an image summarizing these steps.<\/p>\n\n\n\n Here is the step-by-step diagram for the calculation of the bromic acid concentration, showing the stoichiometric relationship and the calculations involved. I hope it helps clarify the process!<\/p>\n\n\n\n Consider the reaction between strontium hydroxide and bromic acid, HBrO3(aq):Sr(OH)2(aq) + 2 HBrO3(aq) \u21922 H2O (1) + Sr(BrO3)2(aq)Calculate the concentration of bromic acid if a 20.95mL sample of bromic acid required 30.07mL of 0.383M Sr(OH)2 for complete neutralization to a phenolphthaleinendpoint. The Correct Answer and Explanation is : The concentration of bromic acid (HBrO3) is […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-191610","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/191610","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=191610"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/191610\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=191610"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=191610"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=191610"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}Explanation:<\/h3>\n\n\n\n
\\text{Sr(OH)}_2(aq) + 2 \\text{HBrO}_3(aq) \\rightarrow 2 \\text{H}_2\\text{O}(l) + \\text{Sr(BrO}_3)_2(aq)
]<\/p>\n\n\n\n\n
Moles of Sr(OH)2 = Molarity \u00d7 Volume (in L)
[
= 0.383 \\, \\text{M} \\times \\frac{30.07 \\, \\text{mL}}{1000} = 0.01152 \\, \\text{moles}
]<\/li>\n\n\n\n
From the equation, 1 mole of Sr(OH)2 reacts with 2 moles of HBrO3. Therefore, the moles of HBrO3 required will be:
[
0.01152 \\, \\text{moles of Sr(OH)2} \\times 2 = 0.02304 \\, \\text{moles of HBrO3}
]<\/li>\n\n\n\n
Molarity of HBrO3 = Moles of HBrO3 \/ Volume of HBrO3 (in L)
[
= \\frac{0.02304 \\, \\text{moles}}{\\frac{20.95 \\, \\text{mL}}{1000}} = 1.10 \\, \\text{M}
]<\/li>\n<\/ol>\n\n\n\n![\"\"](\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/02\/image-603.png\")
<\/figure>\n","protected":false},"excerpt":{"rendered":"