{"id":191647,"date":"2025-02-15T09:41:03","date_gmt":"2025-02-15T09:41:03","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=191647"},"modified":"2025-02-15T09:41:05","modified_gmt":"2025-02-15T09:41:05","slug":"which-compound-matches-the-ir-spectrum","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/15\/which-compound-matches-the-ir-spectrum\/","title":{"rendered":"Which compound matches the IR spectrum"},"content":{"rendered":"\n

Which compound matches the IR spectrum?<\/p>\n\n\n\n

cyclohexane
trans-4-octene
3-hexanol
Odipropyl ether
1-methylcyclopentene
1-hexen-3-ol
1,5-hexadiene<\/p>\n\n\n\n

The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n

To match an IR spectrum with a compound, key functional groups and bonds present in the compound need to be identified. Let’s break down each compound in the list and analyze what functional groups would show up in their respective IR spectra.<\/p>\n\n\n\n

    \n
  1. Cyclohexane<\/strong>: Cyclohexane is a simple saturated alkane, meaning its IR spectrum would show a characteristic C-H stretching band around 2850-2960 cm\u207b\u00b9<\/strong> (for C-H bonds) and C-H bending at around 1465 cm\u207b\u00b9<\/strong>. There would be no significant functional groups like C=C or O-H.<\/li>\n\n\n\n
  2. trans-4-octene<\/strong>: This compound is an alkene. The IR spectrum would show:<\/li>\n<\/ol>\n\n\n\n
      \n
    • C-H stretching<\/strong> around 2850-2960 cm\u207b\u00b9<\/strong>.<\/li>\n\n\n\n
    • C=C stretching<\/strong> around 1600 cm\u207b\u00b9<\/strong>.<\/li>\n\n\n\n
    • C-H bending<\/strong> around 900-1000 cm\u207b\u00b9<\/strong> for the trans-configuration.<\/li>\n<\/ul>\n\n\n\n
        \n
      1. 3-hexanol<\/strong>: This is an alcohol. Its IR spectrum would show:<\/li>\n<\/ol>\n\n\n\n
          \n
        • O-H stretching<\/strong> around 3200-3550 cm\u207b\u00b9<\/strong> (broad band).<\/li>\n\n\n\n
        • C-H stretching<\/strong> around 2850-2960 cm\u207b\u00b9<\/strong>.<\/li>\n\n\n\n
        • C-O stretching<\/strong> around 1050-1150 cm\u207b\u00b9<\/strong>.<\/li>\n<\/ul>\n\n\n\n
            \n
          1. Dipropyl ether<\/strong>: As an ether, dipropyl ether’s IR spectrum would show:<\/li>\n<\/ol>\n\n\n\n
              \n
            • C-H stretching<\/strong> around 2850-2960 cm\u207b\u00b9<\/strong>.<\/li>\n\n\n\n
            • C-O-C stretching<\/strong> around 1050-1150 cm\u207b\u00b9<\/strong>.<\/li>\n\n\n\n
            • No O-H stretch, since it’s not an alcohol.<\/li>\n<\/ul>\n\n\n\n
                \n
              1. 1-methylcyclopentene<\/strong>: This compound has an alkene group. The IR spectrum would show:<\/li>\n<\/ol>\n\n\n\n
                  \n
                • C-H stretching<\/strong> around 2850-2960 cm\u207b\u00b9<\/strong>.<\/li>\n\n\n\n
                • C=C stretching<\/strong> around 1600 cm\u207b\u00b9<\/strong>.<\/li>\n\n\n\n
                • C-H bending<\/strong> near 1000 cm\u207b\u00b9<\/strong> for the alkene group.<\/li>\n<\/ul>\n\n\n\n
                    \n
                  1. 1-hexen-3-ol<\/strong>: This compound has both an alcohol and an alkene. The IR spectrum would show:<\/li>\n<\/ol>\n\n\n\n
                      \n
                    • O-H stretching<\/strong> around 3200-3550 cm\u207b\u00b9<\/strong> (broad).<\/li>\n\n\n\n
                    • C-H stretching<\/strong> around 2850-2960 cm\u207b\u00b9<\/strong>.<\/li>\n\n\n\n
                    • C=C stretching<\/strong> around 1600 cm\u207b\u00b9<\/strong>.<\/li>\n\n\n\n
                    • C-O stretching<\/strong> around 1050-1150 cm\u207b\u00b9<\/strong>.<\/li>\n<\/ul>\n\n\n\n
                        \n
                      1. 1,5-hexadiene<\/strong>: This is a diene, and its IR spectrum would show:<\/li>\n<\/ol>\n\n\n\n
                          \n
                        • C-H stretching<\/strong> around 2850-2960 cm\u207b\u00b9<\/strong>.<\/li>\n\n\n\n
                        • C=C stretching<\/strong> around 1600 cm\u207b\u00b9<\/strong>.<\/li>\n\n\n\n
                        • C-H bending<\/strong> near 1000 cm\u207b\u00b9<\/strong>.<\/li>\n<\/ul>\n\n\n\n

                          Correct Answer: 3-hexanol<\/strong><\/h3>\n\n\n\n
                            \n
                          • The O-H stretching<\/strong> in the range of 3200-3550 cm\u207b\u00b9<\/strong> is a strong indicator of an alcohol.<\/li>\n\n\n\n
                          • C-H stretching<\/strong> and C-O stretching<\/strong> also appear in the expected regions.<\/li>\n<\/ul>\n\n\n\n

                            Let’s generate the IR spectrum image for 3-hexanol<\/strong>.<\/p>\n\n\n\n

                            Here is an illustration of the infrared (IR) spectrum for 3-hexanol. The key features, such as the broad O-H stretching around 3200-3550 cm\u207b\u00b9 and the C-O stretching around 1050-1150 cm\u207b\u00b9, are clearly visible.<\/p>\n\n\n\n

                            \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

                            Which compound matches the IR spectrum? cyclohexanetrans-4-octene3-hexanolOdipropyl ether1-methylcyclopentene1-hexen-3-ol1,5-hexadiene The Correct Answer and Explanation is : To match an IR spectrum with a compound, key functional groups and bonds present in the compound need to be identified. Let’s break down each compound in the list and analyze what functional groups would show up in their respective […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-191647","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/191647","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=191647"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/191647\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=191647"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=191647"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=191647"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}