Potassium hydroxide (KOH) is a strong base. Dissociation of potassium hydroxide follows the reaction equation given. KOH(s) –H20–> K+(aq) OH-(aq) \u00c3\u201a\u00c2 a) Write down the reaction equation for a neutralization reaction where potassium hydroxide (KOH) reacts with sulphuric acid (H2SO4) producing potassium sulphate (K2SO4) and water (H2O). Balance if needed! b) Calculate pH for the solution where 0,2 mol of KOH\u00c3\u201a\u00c2 is dissolved into water so that the total volume of the solution is 0,5 L.\u00c3\u201a\u00c2
Potassium hydroxide (KOH) is a strong base. Dissociation of potassium hydroxide follows the reaction equation given. KOH(s) –H20–> K+(aq) OH-(aq)<\/p>\n\n\n\n
\u00c3\u201a\u00c2<\/p>\n\n\n\n
a) Write down the reaction equation for a neutralization reaction where potassium hydroxide (KOH) reacts with sulphuric acid (H2SO4) producing potassium sulphate (K2SO4) and water (H2O). Balance if needed!<\/p>\n\n\n\n
b) Calculate pH for the solution where 0,2 mol of KOH\u00c3\u201a\u00c2 is dissolved into water so that the total volume of the solution is 0,5 L.\u00c3\u201a\u00c2<\/p>\n\n\n\n
The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n a) Reaction equation for the neutralization between KOH and H\u2082SO\u2084:<\/strong><\/p>\n\n\n\n The neutralization reaction between potassium hydroxide (KOH) and sulfuric acid (H\u2082SO\u2084) forms potassium sulfate (K\u2082SO\u2084) and water (H\u2082O). The balanced reaction is:<\/p>\n\n\n\n [ This balanced equation shows that two moles of KOH react with one mole of H\u2082SO\u2084 to form one mole of potassium sulfate and two moles of water.<\/p>\n\n\n\n b) pH Calculation for KOH Solution:<\/strong><\/p>\n\n\n\n To calculate the pH of a solution where 0.2 mol of KOH is dissolved in 0.5 L of water, follow these steps:<\/p>\n\n\n\n Since KOH is a strong base, it dissociates completely in water:<\/p>\n\n\n\n [ The concentration of OH\u207b ions will be the same as the concentration of KOH, which is:<\/p>\n\n\n\n [ The pOH is calculated using the formula:<\/p>\n\n\n\n [ Substituting the concentration of OH\u207b:<\/p>\n\n\n\n [ The relationship between pH and pOH is given by:<\/p>\n\n\n\n [ Thus:<\/p>\n\n\n\n [ Final answer:<\/strong><\/p>\n\n\n\n The pH of the solution is approximately 13.6<\/strong>. This indicates a strongly basic solution, as expected for a strong base like KOH.<\/p>\n\n\n\n Would you like an illustration for this process?<\/p>\n","protected":false},"excerpt":{"rendered":" Potassium hydroxide (KOH) is a strong base. Dissociation of potassium hydroxide follows the reaction equation given. KOH(s) –H20–> K+(aq) OH-(aq) \u00c3\u201a\u00c2 a) Write down the reaction equation for a neutralization reaction where potassium hydroxide (KOH) reacts with sulphuric acid (H2SO4) producing potassium sulphate (K2SO4) and water (H2O). Balance if needed! b) Calculate pH for the […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-192002","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/192002","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=192002"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/192002\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=192002"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=192002"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=192002"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
2 \\, \\text{KOH}(aq) + \\text{H}_2\\text{SO}_4(aq) \\rightarrow \\text{K}_2\\text{SO}_4(aq) + 2 \\, \\text{H}_2\\text{O}(l)
]<\/p>\n\n\n\n\n
\\text{KOH} \\rightarrow \\text{K}^+ + \\text{OH}^-
]<\/p>\n\n\n\n
[\\text{OH}^-] = \\frac{0.2 \\, \\text{mol}}{0.5 \\, \\text{L}} = 0.4 \\, \\text{M}
]<\/p>\n\n\n\n\n
\\text{pOH} = -\\log[\\text{OH}^-]
]<\/p>\n\n\n\n
\\text{pOH} = -\\log(0.4) \\approx 0.398
]<\/p>\n\n\n\n\n
\\text{pH} + \\text{pOH} = 14
]<\/p>\n\n\n\n
\\text{pH} = 14 – \\text{pOH} = 14 – 0.398 = 13.602
]<\/p>\n\n\n\n