{"id":192203,"date":"2025-02-17T11:25:26","date_gmt":"2025-02-17T11:25:26","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=192203"},"modified":"2025-02-17T11:25:29","modified_gmt":"2025-02-17T11:25:29","slug":"iron-forms-two-ions-fe2-and-fe3","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/17\/iron-forms-two-ions-fe2-and-fe3\/","title":{"rendered":"Iron forms two ions, Fe2+ and Fe3+"},"content":{"rendered":"\n<p>Iron forms two ions, Fe2+ and Fe3+.<\/p>\n\n\n\n<p>(a) What are the formulas for the compounds the two iron ions can form with oxide ion, O2-?<\/p>\n\n\n\n<p>Fe2+<\/p>\n\n\n\n<p>Fe3+<\/p>\n\n\n\n<p>(b) What are the formulas for the compounds the two iron ions can form with chloride ion,<\/p>\n\n\n\n<p>Cl-?<\/p>\n\n\n\n<p>Fe2+<\/p>\n\n\n\n<p>Fe<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">(a) Compounds with Oxide Ion (O\u00b2\u207b)<\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Fe\u00b2\u207a and Oxide Ion (O\u00b2\u207b):<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The formula for the compound formed between Fe\u00b2\u207a and O\u00b2\u207b is <strong>FeO<\/strong>.<\/li>\n\n\n\n<li>Fe\u00b2\u207a has a charge of +2, while O\u00b2\u207b has a charge of -2. To balance the charges, one Fe\u00b2\u207a ion pairs with one O\u00b2\u207b ion to form FeO.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Fe\u00b3\u207a and Oxide Ion (O\u00b2\u207b):<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The formula for the compound formed between Fe\u00b3\u207a and O\u00b2\u207b is <strong>Fe\u2082O\u2083<\/strong>.<\/li>\n\n\n\n<li>Fe\u00b3\u207a has a charge of +3, and O\u00b2\u207b has a charge of -2. To balance the charges, two Fe\u00b3\u207a ions (total charge of +6) combine with three O\u00b2\u207b ions (total charge of -6), resulting in Fe\u2082O\u2083.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">(b) Compounds with Chloride Ion (Cl\u207b)<\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Fe\u00b2\u207a and Chloride Ion (Cl\u207b):<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The formula for the compound formed between Fe\u00b2\u207a and Cl\u207b is <strong>FeCl\u2082<\/strong>.<\/li>\n\n\n\n<li>Fe\u00b2\u207a has a charge of +2, and Cl\u207b has a charge of -1. To balance the charges, one Fe\u00b2\u207a ion pairs with two Cl\u207b ions (total charge of -2), resulting in FeCl\u2082.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Fe\u00b3\u207a and Chloride Ion (Cl\u207b):<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The formula for the compound formed between Fe\u00b3\u207a and Cl\u207b is <strong>FeCl\u2083<\/strong>.<\/li>\n\n\n\n<li>Fe\u00b3\u207a has a charge of +3, and Cl\u207b has a charge of -1. To balance the charges, one Fe\u00b3\u207a ion pairs with three Cl\u207b ions (total charge of -3), resulting in FeCl\u2083.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>Iron (Fe) can form multiple ionic compounds, depending on the oxidation state of the iron ion. The two common oxidation states for iron are +2 (Fe\u00b2\u207a) and +3 (Fe\u00b3\u207a).<\/p>\n\n\n\n<p>When iron ions bond with anions, such as oxide (O\u00b2\u207b) or chloride (Cl\u207b), the resulting compound&#8217;s formula is determined by the need to balance the total charge of the ions involved. This balance ensures that the compound is electrically neutral. For oxide, the formula depends on the charge difference between iron ions and oxide ions. Similarly, when bonding with chloride, the number of chloride ions adjusts to neutralize the charge of the iron ions.<\/p>\n\n\n\n<p>Now, I will generate an image representing these compounds.<\/p>\n\n\n\n<p>Here is the illustration of the iron compounds (FeO, Fe\u2082O\u2083, FeCl\u2082, and FeCl\u2083) with oxide (O\u00b2\u207b) and chloride (Cl\u207b) ions. This image shows the interactions between the iron ions and the anions, helping visualize the charge balance and structure of each compound. Let me know if you need any more details!<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/02\/image-775.png\" alt=\"\" class=\"wp-image-192204\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Iron forms two ions, Fe2+ and Fe3+. (a) What are the formulas for the compounds the two iron ions can form with oxide ion, O2-? Fe2+ Fe3+ (b) What are the formulas for the compounds the two iron ions can form with chloride ion, Cl-? Fe2+ Fe The Correct Answer and Explanation is : (a) [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-192203","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/192203","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=192203"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/192203\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=192203"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=192203"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=192203"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}