{"id":192342,"date":"2025-02-17T17:30:06","date_gmt":"2025-02-17T17:30:06","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=192342"},"modified":"2025-02-17T17:30:08","modified_gmt":"2025-02-17T17:30:08","slug":"determine-the-molar-mass-of-mnclo33","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/17\/determine-the-molar-mass-of-mnclo33\/","title":{"rendered":"Determine the molar mass of Mn(ClO3)3"},"content":{"rendered":"\n<p>Determine the molar mass of Mn(ClO3)3.<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>To determine the molar mass of manganese(III) chlorate, Mn(ClO\u2083)\u2083, we need to calculate the mass contribution of each element present in the compound.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Manganese (Mn)<\/strong>: The atomic mass of manganese is approximately 54.94 g\/mol. There is one manganese atom in the formula.<\/li>\n\n\n\n<li><strong>Chlorate (ClO\u2083)<\/strong>: The chlorate ion is made up of one chlorine (Cl) atom and three oxygen (O) atoms.<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The atomic mass of chlorine (Cl) is 35.45 g\/mol.<\/li>\n\n\n\n<li>The atomic mass of oxygen (O) is 16.00 g\/mol, and since there are three oxygen atoms in the chlorate ion, the total mass for oxygen is 3 \u00d7 16.00 = 48.00 g\/mol.<\/li>\n<\/ul>\n\n\n\n<p>Now, we can calculate the molar mass of Mn(ClO\u2083)\u2083 by adding up the contributions:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Manganese (Mn): 54.94 g\/mol \u00d7 1 = 54.94 g\/mol<\/li>\n\n\n\n<li>Chlorine (Cl): 35.45 g\/mol \u00d7 3 = 106.35 g\/mol<\/li>\n\n\n\n<li>Oxygen (O): 16.00 g\/mol \u00d7 9 = 144.00 g\/mol (since there are 3 oxygen atoms per chlorate ion, and there are three chlorate ions)<\/li>\n<\/ul>\n\n\n\n<p><strong>Total molar mass of Mn(ClO\u2083)\u2083<\/strong> = 54.94 g\/mol (Mn) + 106.35 g\/mol (Cl) + 144.00 g\/mol (O) = 305.29 g\/mol<\/p>\n\n\n\n<p>Thus, the molar mass of Mn(ClO\u2083)\u2083 is <strong>305.29 g\/mol<\/strong>.<\/p>\n\n\n\n<p>This calculation involves adding the atomic masses of each element, considering the number of atoms for each element in the compound. This is a fundamental process in chemistry to determine the molar mass of a compound, which is essential for various calculations in stoichiometry, such as determining the amount of a substance required for a reaction.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Determine the molar mass of Mn(ClO3)3. The Correct Answer and Explanation is : To determine the molar mass of manganese(III) chlorate, Mn(ClO\u2083)\u2083, we need to calculate the mass contribution of each element present in the compound. Now, we can calculate the molar mass of Mn(ClO\u2083)\u2083 by adding up the contributions: Total molar mass of Mn(ClO\u2083)\u2083 [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-192342","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/192342","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=192342"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/192342\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=192342"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=192342"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=192342"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}