{"id":192665,"date":"2025-02-18T05:57:45","date_gmt":"2025-02-18T05:57:45","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=192665"},"modified":"2025-02-18T05:57:47","modified_gmt":"2025-02-18T05:57:47","slug":"write-the-equation-for-the-reaction-of-1-mol-of-sulfurous-acid-h2so3-with-1-mol-of-beryllium-hydroxide","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/18\/write-the-equation-for-the-reaction-of-1-mol-of-sulfurous-acid-h2so3-with-1-mol-of-beryllium-hydroxide\/","title":{"rendered":"Write the equation for the reaction of 1 mol of sulfurous acid (H2SO3) with 1 mol of beryllium hydroxide"},"content":{"rendered":"\n
    \n
  1. Write the equation for the reaction of 1 mol of sulfurous acid (H2SO3) with 1 mol of beryllium hydroxide.<\/li>\n\n\n\n
  2. Write the equation for the reaction of 1 mol of phosphoric acid with 1 mol of gallium hydroxide<\/li>\n<\/ol>\n\n\n\n

    The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n

    1. Reaction of sulfurous acid (H\u2082SO\u2083) with beryllium hydroxide (Be(OH)\u2082):<\/h3>\n\n\n\n

    The reaction between sulfurous acid (H\u2082SO\u2083) and beryllium hydroxide (Be(OH)\u2082) is an acid-base reaction where the acid reacts with the base to form water and a salt. The equation is:<\/p>\n\n\n\n

    [
    H_2SO_3 + Be(OH)_2 \\rightarrow BeSO_3 + 2H_2O
    ]<\/p>\n\n\n\n

    In this reaction:<\/p>\n\n\n\n

      \n
    • Sulfurous acid (H\u2082SO\u2083)<\/strong> is a weak acid that reacts with beryllium hydroxide (Be(OH)\u2082)<\/strong>, a base.<\/li>\n\n\n\n
    • The product is beryllium sulfite (BeSO\u2083)<\/strong>, a salt, and water (H\u2082O)<\/strong>.<\/li>\n<\/ul>\n\n\n\n

      2. Reaction of phosphoric acid (H\u2083PO\u2084) with gallium hydroxide (Ga(OH)\u2083):<\/h3>\n\n\n\n

      Phosphoric acid (H\u2083PO\u2084) reacts with gallium hydroxide (Ga(OH)\u2083) in an acid-base reaction, producing water and a salt. The balanced equation for this reaction is:<\/p>\n\n\n\n

      [
      H_3PO_4 + Ga(OH)_3 \\rightarrow GaPO_4 + 3H_2O
      ]<\/p>\n\n\n\n

      In this reaction:<\/p>\n\n\n\n

        \n
      • Phosphoric acid (H\u2083PO\u2084)<\/strong>, a triprotic acid, donates three protons (H\u207a ions) in the reaction.<\/li>\n\n\n\n
      • Gallium hydroxide (Ga(OH)\u2083)<\/strong>, a base, reacts with the three protons to form gallium phosphate (GaPO\u2084)<\/strong>, a salt, and water (H\u2082O)<\/strong>.<\/li>\n<\/ul>\n\n\n\n

        Explanation:<\/h4>\n\n\n\n

        Both of these reactions are acid-base neutralization reactions, where the acid (H\u2082SO\u2083 or H\u2083PO\u2084) donates protons (H\u207a) to the base (Be(OH)\u2082 or Ga(OH)\u2083), forming a salt and water. The salts formed, beryllium sulfite (BeSO\u2083)<\/strong> and gallium phosphate (GaPO\u2084)<\/strong>, are typically insoluble in water, which is why they precipitate out in the reaction.<\/p>\n\n\n\n

          \n
        • In the H\u2082SO\u2083 and Be(OH)\u2082 reaction<\/strong>, the acid donates two protons (since H\u2082SO\u2083 has two replaceable hydrogen atoms), and the base provides two hydroxide ions.<\/li>\n\n\n\n
        • In the H\u2083PO\u2084 and Ga(OH)\u2083 reaction<\/strong>, phosphoric acid donates three protons (since H\u2083PO\u2084 has three replaceable hydrogen atoms), and gallium hydroxide provides three hydroxide ions.<\/li>\n<\/ul>\n\n\n\n

          The resulting salts are formed through the ionic bonding between the cations (Be\u00b2\u207a or Ga\u00b3\u207a) and the anions (SO\u2083\u00b2\u207b or PO\u2084\u00b3\u207b), and water is a byproduct due to the neutralization of the H\u207a and OH\u207b ions.<\/p>\n\n\n\n

          I will now generate an image showing both reactions.<\/p>\n\n\n\n

          Here is the image showing both reactions: sulfurous acid with beryllium hydroxide and phosphoric acid with gallium hydroxide. You can see the molecular structures and arrows indicating the direction of the reactions. Let me know if you’d like any further clarification!<\/p>\n\n\n\n

          \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

          The Correct Answer and Explanation is : 1. Reaction of sulfurous acid (H\u2082SO\u2083) with beryllium hydroxide (Be(OH)\u2082): The reaction between sulfurous acid (H\u2082SO\u2083) and beryllium hydroxide (Be(OH)\u2082) is an acid-base reaction where the acid reacts with the base to form water and a salt. The equation is: [H_2SO_3 + Be(OH)_2 \\rightarrow BeSO_3 + 2H_2O] In […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-192665","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/192665","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=192665"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/192665\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=192665"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=192665"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=192665"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}