{"id":192862,"date":"2025-02-18T09:42:39","date_gmt":"2025-02-18T09:42:39","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=192862"},"modified":"2025-02-18T09:42:41","modified_gmt":"2025-02-18T09:42:41","slug":"which-one-of-the-following-is-a-conjugate-acid-base-pa","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/18\/which-one-of-the-following-is-a-conjugate-acid-base-pa\/","title":{"rendered":"Which one of the following is a conjugate acid base pa"},"content":{"rendered":"\n<p>Which one of the following is a conjugate acid base pair?<\/p>\n\n\n\n<p>NaF &amp; F-<br>NH4+ &amp; NH2-<br>HNO3 &amp; HNO2<br>H2O &amp; H2O2<br>HI &amp; I-<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>The correct conjugate acid-base pair from the given options is <strong>NH4+ &amp; NH3-<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>In acid-base chemistry, a <strong>conjugate acid-base pair<\/strong> refers to two substances related by the loss or gain of a proton (H+). When an acid donates a proton, the substance that remains is its conjugate base. Conversely, when a base accepts a proton, the resulting substance is its conjugate acid.<\/p>\n\n\n\n<p>Let&#8217;s examine the pairs:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>NaF &amp; F-<\/strong>:<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>NaF is a salt, and F- is the fluoride ion. The fluoride ion, F-, is the conjugate base of HF (hydrofluoric acid). However, NaF is not an acid, so this is not a conjugate acid-base pair.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>NH4+ &amp; NH3-<\/strong>:<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>NH4+ (ammonium ion) is the conjugate acid of NH3 (ammonia). NH3 is a base because it can accept a proton, while NH4+ is an acid because it can donate a proton to form NH3. This is a correct conjugate acid-base pair.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>HNO3 &amp; HNO2<\/strong>:<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>HNO3 (nitric acid) and HNO2 (nitrous acid) are both acids but are not conjugate acid-base pairs because they are different acids, and neither can convert into the other through the simple gain or loss of a proton.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>H2O &amp; H2O2<\/strong>:<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>H2O (water) and H2O2 (hydrogen peroxide) are not a conjugate acid-base pair. H2O is neutral, and H2O2 is an oxidizing agent, but they don\u2019t interconvert through proton transfer.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>HI &amp; I-<\/strong>:<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>HI (hydroiodic acid) and I- (iodide ion) are a conjugate acid-base pair. HI is a strong acid, and I- is the conjugate base of HI. This is a valid conjugate acid-base pair.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Conclusion:<\/h3>\n\n\n\n<p>The correct conjugate acid-base pair from the provided options is <strong>NH4+ &amp; NH3-<\/strong>. This pair demonstrates the typical behavior of an acid donating a proton to become a base.<\/p>\n\n\n\n<p>Let me generate an image of this concept.<\/p>\n\n\n\n<p>Here is an illustration of a conjugate acid-base pair, showing the transfer of a proton from NH4+ (ammonium) to form NH3 (ammonia). This demonstrates the relationship between the acid and its conjugate base. Let me know if you&#8217;d like any more details or another visual!<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/02\/image-938.png\" alt=\"\" class=\"wp-image-192863\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Which one of the following is a conjugate acid base pair? NaF &amp; F-NH4+ &amp; NH2-HNO3 &amp; HNO2H2O &amp; H2O2HI &amp; I- The Correct Answer and Explanation is : The correct conjugate acid-base pair from the given options is NH4+ &amp; NH3-. Explanation: In acid-base chemistry, a conjugate acid-base pair refers to two substances related [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-192862","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/192862","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=192862"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/192862\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=192862"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=192862"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=192862"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}