{"id":192944,"date":"2025-02-18T12:59:12","date_gmt":"2025-02-18T12:59:12","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=192944"},"modified":"2025-02-18T12:59:14","modified_gmt":"2025-02-18T12:59:14","slug":"the-reaction-between-nitric-acid-and-sodium-hydroxide-is-shown-below","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/18\/the-reaction-between-nitric-acid-and-sodium-hydroxide-is-shown-below\/","title":{"rendered":"The reaction between nitric acid and sodium hydroxide is shown below"},"content":{"rendered":"\n<p>The reaction between nitric acid and sodium hydroxide is shown below. What is the concentration of HNO, if it takes 25.0 mL of 0.493 M NaOH to react with a 10.0 mL sample of HNO3? Write your answer to three significant figures, include units, and show your work for full credit (15 points)<\/p>\n\n\n\n<p>HNO3(aq) + NaOH(aq) \u2192 NaNO3(aq) + H2O(1)<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>To find the concentration of HNO\u2083, we can use the concept of stoichiometry based on the balanced chemical equation:<\/p>\n\n\n\n<p><strong>HNO\u2083(aq) + NaOH(aq) \u2192 NaNO\u2083(aq) + H\u2082O(l)<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Write down the known values:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Volume of NaOH (V_NaOH) = 25.0 mL = 0.0250 L<\/li>\n\n\n\n<li>Concentration of NaOH (C_NaOH) = 0.493 M<\/li>\n\n\n\n<li>Volume of HNO\u2083 (V_HNO3) = 10.0 mL = 0.0100 L<\/li>\n\n\n\n<li>We need to find the concentration of HNO\u2083 (C_HNO3).<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Calculate the moles of NaOH:<\/h3>\n\n\n\n<p>The number of moles of NaOH is calculated using the equation:<\/p>\n\n\n\n<p>[<br>\\text{moles of NaOH} = \\text{concentration of NaOH} \\times \\text{volume of NaOH}<br>]<\/p>\n\n\n\n<p>Substitute the known values:<\/p>\n\n\n\n<p>[<br>\\text{moles of NaOH} = 0.493 \\, \\text{M} \\times 0.0250 \\, \\text{L} = 0.012325 \\, \\text{moles}<br>]<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Use stoichiometry to find the moles of HNO\u2083:<\/h3>\n\n\n\n<p>From the balanced chemical equation, we can see that the mole ratio between NaOH and HNO\u2083 is 1:1. Therefore, the moles of HNO\u2083 will be the same as the moles of NaOH:<\/p>\n\n\n\n<p>[<br>\\text{moles of HNO\u2083} = 0.012325 \\, \\text{moles}<br>]<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 4: Calculate the concentration of HNO\u2083:<\/h3>\n\n\n\n<p>The concentration of HNO\u2083 can be calculated using the formula:<\/p>\n\n\n\n<p>[<br>\\text{concentration of HNO\u2083} = \\frac{\\text{moles of HNO\u2083}}{\\text{volume of HNO\u2083}}<br>]<\/p>\n\n\n\n<p>Substitute the values:<\/p>\n\n\n\n<p>[<br>\\text{concentration of HNO\u2083} = \\frac{0.012325 \\, \\text{moles}}{0.0100 \\, \\text{L}} = 1.2325 \\, \\text{M}<br>]<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 5: Round the answer:<\/h3>\n\n\n\n<p>Since we are asked to round the answer to three significant figures, the concentration of HNO\u2083 is:<\/p>\n\n\n\n<p>[<br>\\boxed{1.23 \\, \\text{M}}<br>]<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Conclusion:<\/h3>\n\n\n\n<p>The concentration of HNO\u2083 is <strong>1.23 M<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>The reaction between nitric acid and sodium hydroxide is shown below. What is the concentration of HNO, if it takes 25.0 mL of 0.493 M NaOH to react with a 10.0 mL sample of HNO3? Write your answer to three significant figures, include units, and show your work for full credit (15 points) HNO3(aq) + [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-192944","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/192944","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=192944"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/192944\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=192944"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=192944"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=192944"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}