Identify this reaction NH3 + H2SO4 + (NH4)2SO4)<\/p>\n\n\n\n
a. double displacement<\/p>\n\n\n\n
b. synthesis<\/p>\n\n\n\n
c. single displacement<\/p>\n\n\n\n
d. decomposition<\/p>\n\n\n\n
The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n The reaction given is:<\/p>\n\n\n\n [ This is an example of a synthesis reaction<\/strong>. A synthesis reaction occurs when two or more reactants combine to form a single product. In this case, ammonia (NH\u2083) and sulfuric acid (H\u2082SO\u2084) combine to form ammonium sulfate ((NH\u2084)\u2082SO\u2084), a compound that contains both ammonium ions (NH\u2084\u207a) and sulfate ions (SO\u2084\u00b2\u207b).<\/p>\n\n\n\n Thus, the correct answer is: The unbalanced equation is:<\/p>\n\n\n\n [ Let’s balance this step-by-step:<\/p>\n\n\n\n There is 1 sulfur atom on the left-hand side (Sg), and 1 sulfur atom on the right-hand side (in SO\u2083). Therefore, sulfur is balanced.<\/p>\n\n\n\n On the right-hand side, there are 3 oxygen atoms in SO\u2083. On the left-hand side, O\u2082 contains 2 oxygen atoms per molecule. To balance the oxygen atoms, we need to adjust the number of O\u2082 molecules.<\/p>\n\n\n\n We need to have a total of 3 oxygen atoms on the left-hand side to balance the 3 oxygen atoms on the right-hand side. Therefore, we need 3\/2 molecules of O\u2082 on the left-hand side:<\/p>\n\n\n\n [ Multiplying by 2 will remove the fraction:<\/p>\n\n\n\n [ [ The process of balancing a chemical equation follows the law of conservation of mass, which states that atoms are neither created nor destroyed in a chemical reaction. Therefore, the number of atoms of each element must be the same on both sides of the equation.<\/p>\n\n\n\n In this case:<\/p>\n\n\n\n Identify this reaction NH3 + H2SO4 + (NH4)2SO4) a. double displacement b. synthesis c. single displacement d. decomposition The Correct Answer and Explanation is : 1. Identify the reaction: NH3 + H2SO4 \u2192 (NH4)2SO4 The reaction given is: [\\text{NH}_3 + \\text{H}_2\\text{SO}_4 \\rightarrow (\\text{NH}_4)_2\\text{SO}_4] This is an example of a synthesis reaction. A synthesis reaction occurs […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-193103","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/193103","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=193103"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/193103\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=193103"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=193103"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=193103"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}1. Identify the reaction: NH3 + H2SO4 \u2192 (NH4)2SO4<\/h3>\n\n\n\n
\\text{NH}_3 + \\text{H}_2\\text{SO}_4 \\rightarrow (\\text{NH}_4)_2\\text{SO}_4
]<\/p>\n\n\n\n
b. synthesis<\/strong><\/p>\n\n\n\n2. Balance the unbalanced chemical equation: Sg(g) + O\u2082(g) \u2192 SO\u2083(g)<\/h3>\n\n\n\n
\\text{Sg(g)} + \\text{O}_2(g) \\rightarrow \\text{SO}_3(g)
]<\/p>\n\n\n\nStep 1: Balance sulfur atoms.<\/h4>\n\n\n\n
Step 2: Balance oxygen atoms.<\/h4>\n\n\n\n
\\text{Sg(g)} + \\frac{3}{2} \\text{O}_2(g) \\rightarrow \\text{SO}_3(g)
]<\/p>\n\n\n\nStep 3: Remove the fraction by multiplying the entire equation by 2.<\/h4>\n\n\n\n
2 \\text{Sg(g)} + 3 \\text{O}_2(g) \\rightarrow 2 \\text{SO}_3(g)
]<\/p>\n\n\n\nFinal Balanced Equation:<\/h4>\n\n\n\n
2 \\text{Sg(g)} + 3 \\text{O}_2(g) \\rightarrow 2 \\text{SO}_3(g)
]<\/p>\n\n\n\nExplanation:<\/h3>\n\n\n\n
\n