{"id":193206,"date":"2025-02-19T07:28:11","date_gmt":"2025-02-19T07:28:11","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=193206"},"modified":"2025-02-19T07:28:14","modified_gmt":"2025-02-19T07:28:14","slug":"complete-and-balance-the-molecular-equation-for-the-reaction-of-aqueous-copperii-chloride","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/19\/complete-and-balance-the-molecular-equation-for-the-reaction-of-aqueous-copperii-chloride\/","title":{"rendered":"Complete and balance the molecular equation for the reaction of aqueous copper(II) chloride"},"content":{"rendered":"\n

Complete and balance the molecular equation for the reaction of aqueous copper(II) chloride, CuCl2, and aqueous potassium phosphate, K3PO4. Include physical states. CuCl2(aq)+K3PO499(aq)> Enter the balanced net ionic equation for this reaction. Include physical states. *> symbolizes an arrow*<\/p>\n\n\n\n

Complete and balance the molecular equation for the reaction of aqueous copper(II) chloride, CuCl2, and aqueous potassium phosphate, K3PO4. Include physical states.<\/p>\n\n\n\n

CuCl2(aq)+K3PO499(aq)><\/p>\n\n\n\n

Enter the balanced net ionic equation for this reaction. Include physical states.<\/p>\n\n\n\n

*> symbolizes an arrow*<\/p>\n\n\n\n

The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n

To complete and balance the molecular equation for the reaction of aqueous copper(II) chloride (CuCl\u2082) and aqueous potassium phosphate (K\u2083PO\u2084), let’s break it down step by step.<\/p>\n\n\n\n

Step 1: Writing the Molecular Equation<\/h3>\n\n\n\n

The molecular equation represents the complete formula of all compounds involved in the reaction. The reaction occurs between copper(II) chloride (CuCl\u2082) and potassium phosphate (K\u2083PO\u2084), resulting in the formation of copper(II) phosphate (Cu\u2083(PO\u2084)\u2082) and potassium chloride (KCl).<\/p>\n\n\n\n

The balanced molecular equation:<\/p>\n\n\n\n

[
3\\text{CuCl}_2(aq) + 2\\text{K}_3\\text{PO}_4(aq) \\rightarrow \\text{Cu}_3\\text{PO}_4(s) + 6\\text{KCl}(aq)
]<\/p>\n\n\n\n

Step 2: Net Ionic Equation<\/h3>\n\n\n\n

The net ionic equation only includes the species that undergo a change during the reaction. This means we will eliminate the spectator ions (ions that do not participate in the actual chemical change) from the equation.<\/p>\n\n\n\n

    \n
  • In the molecular equation, we can identify the spectator ions:\n
      \n
    • Potassium ions (K\u207a)<\/strong> from K\u2083PO\u2084 and chloride ions (Cl\u207b)<\/strong> from CuCl\u2082 are spectator ions.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n

      Therefore, the net ionic equation will focus only on the ions that form the solid product (Cu\u2083PO\u2084):<\/p>\n\n\n\n

      [
      3\\text{Cu}^{2+}(aq) + 2\\text{PO}_4^{3-}(aq) \\rightarrow \\text{Cu}_3\\text{PO}_4(s)
      ]<\/p>\n\n\n\n

      Explanation of the Reaction<\/h3>\n\n\n\n
        \n
      1. Ion Formation<\/strong>: Copper(II) chloride (CuCl\u2082) dissociates in water to form copper ions (Cu\u00b2\u207a) and chloride ions (Cl\u207b). Potassium phosphate (K\u2083PO\u2084) dissociates into potassium ions (K\u207a) and phosphate ions (PO\u2084\u00b3\u207b).<\/li>\n\n\n\n
      2. Reaction<\/strong>: The Cu\u00b2\u207a ions from CuCl\u2082 and the PO\u2084\u00b3\u207b ions from K\u2083PO\u2084 combine to form copper(II) phosphate, which is insoluble in water and precipitates out as a solid.<\/li>\n\n\n\n
      3. Spectator Ions<\/strong>: Potassium (K\u207a) and chloride (Cl\u207b) ions do not participate in the formation of the precipitate. These are spectator ions and are excluded from the net ionic equation.<\/li>\n<\/ol>\n\n\n\n

        Thus, the reaction illustrates a precipitation reaction<\/strong> where a solid (Cu\u2083PO\u2084) forms from the combination of ions in aqueous solution.<\/p>\n","protected":false},"excerpt":{"rendered":"

        Complete and balance the molecular equation for the reaction of aqueous copper(II) chloride, CuCl2, and aqueous potassium phosphate, K3PO4. Include physical states. CuCl2(aq)+K3PO499(aq)> Enter the balanced net ionic equation for this reaction. Include physical states. *> symbolizes an arrow* Complete and balance the molecular equation for the reaction of aqueous copper(II) chloride, CuCl2, and aqueous […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-193206","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/193206","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=193206"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/193206\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=193206"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=193206"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=193206"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}