{"id":193249,"date":"2025-02-19T08:59:11","date_gmt":"2025-02-19T08:59:11","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=193249"},"modified":"2025-02-19T08:59:13","modified_gmt":"2025-02-19T08:59:13","slug":"draw-lewis-structures-and-condensed-structural-formulas-for-the-four-alcohols-with-the-molecular-formula-c4h10o","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/19\/draw-lewis-structures-and-condensed-structural-formulas-for-the-four-alcohols-with-the-molecular-formula-c4h10o\/","title":{"rendered":"Draw Lewis structures and condensed structural formulas for the four alcohols with the molecular formula C4H10O"},"content":{"rendered":"\n<p>Draw Lewis structures and condensed structural formulas for the four alcohols with the molecular formula C4H10O. Classify each alcohol as primary, secondary, or tertiary. (Hint: First consider the connectivity of the four carbon atoms; they can be bonded either four in a chain or three in a chain with the fourth carbon as a branch on the middle carbon. Then consider the points at which the iOH group can be bonded to each carbon chain.)<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>The molecular formula C4H10O corresponds to four possible alcohols. These alcohols differ based on the arrangement of the carbon atoms and the location of the hydroxyl group (-OH). Here\u2019s how we can break it down:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">1. <strong>Butan-1-ol (1-Butanol)<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Lewis structure<\/strong>: The hydroxyl group (-OH) is attached to the first carbon atom in a straight chain. The other carbon atoms are bonded to hydrogens to satisfy the valency of carbon (4 bonds per carbon).<\/li>\n\n\n\n<li><strong>Condensed formula<\/strong>: CH\u2083CH\u2082CH\u2082OH<\/li>\n\n\n\n<li><strong>Classification<\/strong>: <strong>Primary alcohol<\/strong> (The -OH group is attached to a primary carbon, which is bonded to one other carbon atom).<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">2. <strong>Butan-2-ol (2-Butanol)<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Lewis structure<\/strong>: The hydroxyl group is attached to the second carbon in a straight chain, and the other carbons are bonded to hydrogens.<\/li>\n\n\n\n<li><strong>Condensed formula<\/strong>: CH\u2083CH(OH)CH\u2082CH\u2083<\/li>\n\n\n\n<li><strong>Classification<\/strong>: <strong>Secondary alcohol<\/strong> (The -OH group is attached to a secondary carbon, which is bonded to two other carbon atoms).<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">3. <strong>2-Methylpropan-1-ol (Isobutanol)<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Lewis structure<\/strong>: The structure features a branched chain with a -OH group attached to the first carbon in the chain. The second and third carbons are attached as branches.<\/li>\n\n\n\n<li><strong>Condensed formula<\/strong>: (CH\u2083)\u2082CHCH\u2082OH<\/li>\n\n\n\n<li><strong>Classification<\/strong>: <strong>Primary alcohol<\/strong> (The -OH group is attached to a primary carbon).<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">4. <strong>2-Methylpropan-2-ol (tert-Butanol)<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Lewis structure<\/strong>: The -OH group is attached to the second carbon of a branched chain, which is also bonded to three other carbons.<\/li>\n\n\n\n<li><strong>Condensed formula<\/strong>: (CH\u2083)\u2083COH<\/li>\n\n\n\n<li><strong>Classification<\/strong>: <strong>Tertiary alcohol<\/strong> (The -OH group is attached to a tertiary carbon, which is bonded to three other carbon atoms).<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Butan-1-ol<\/strong> and <strong>Isobutanol<\/strong> are classified as primary alcohols because the -OH group is attached to a carbon atom that is only bonded to one other carbon.<\/li>\n\n\n\n<li><strong>Butan-2-ol<\/strong> is a secondary alcohol because the -OH group is attached to a carbon bonded to two other carbon atoms.<\/li>\n\n\n\n<li><strong>Tert-Butanol<\/strong> is a tertiary alcohol because the -OH group is attached to a carbon that is bonded to three other carbon atoms.<\/li>\n<\/ul>\n\n\n\n<p>I will now generate the Lewis structures and condensed structural formulas for you.<\/p>\n\n\n\n<p>Here are the Lewis structures and condensed formulas for the four alcohols with the molecular formula C4H10O:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Butan-1-ol (1-Butanol)<\/strong>: Primary alcohol with the hydroxyl group attached to the first carbon.<\/li>\n\n\n\n<li><strong>Butan-2-ol (2-Butanol)<\/strong>: Secondary alcohol with the hydroxyl group attached to the second carbon.<\/li>\n\n\n\n<li><strong>2-Methylpropan-1-ol (Isobutanol)<\/strong>: Primary alcohol with the hydroxyl group attached to the first carbon of a branched chain.<\/li>\n\n\n\n<li><strong>2-Methylpropan-2-ol (tert-Butanol)<\/strong>: Tertiary alcohol with the hydroxyl group attached to the second carbon in a branched chain.<\/li>\n<\/ol>\n\n\n\n<p>Let me know if you&#8217;d like more details or further clarification!<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/02\/image-973.png\" alt=\"\" class=\"wp-image-193250\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Draw Lewis structures and condensed structural formulas for the four alcohols with the molecular formula C4H10O. Classify each alcohol as primary, secondary, or tertiary. (Hint: First consider the connectivity of the four carbon atoms; they can be bonded either four in a chain or three in a chain with the fourth carbon as a branch [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-193249","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/193249","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=193249"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/193249\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=193249"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=193249"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=193249"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}