Let’s break down each alcohol based on the provided clues:<\/p>\n\n\n\n
Alcohol A:<\/h3>\n\n\n\n\n- Alcohol A has a branched carbon chain, and it can be oxidized to an aldehyde. This suggests that alcohol A is a secondary alcohol<\/strong> where the hydroxyl group (-OH) is attached to a carbon that is connected to two other carbon atoms.<\/li>\n\n\n\n
- The structure of alcohol A would be 2-methylpropan-2-ol<\/strong>. In this case, the central carbon is attached to two methyl groups (-CH3) and one -OH group. When oxidized, it forms acetaldehyde (ethanal)<\/strong>, an aldehyde.<\/li>\n<\/ul>\n\n\n\n
Alcohol B:<\/h3>\n\n\n\n\n- Alcohol B has a linear carbon chain and can be oxidized to a ketone. This suggests that alcohol B is a secondary alcohol<\/strong> with a linear structure. It will likely be butan-2-ol<\/strong>.<\/li>\n\n\n\n
- The central carbon in butan-2-ol is attached to a hydroxyl group (-OH) and two other carbons. When oxidized, it forms butanone (methyl ethyl ketone)<\/strong>, a ketone.<\/li>\n<\/ul>\n\n\n\n
Alcohol C:<\/h3>\n\n\n\n\n- Alcohol C cannot be oxidized to an aldehyde or a ketone. This suggests that it is a primary alcohol<\/strong> with a hydroxyl group attached to a carbon atom at the end of the chain. The oxidation of primary alcohols usually results in the formation of aldehydes or carboxylic acids, so alcohol C must be 1-butanol<\/strong>.<\/li>\n\n\n\n
- In this case, the alcohol group is on the terminal carbon, and oxidation would lead to the formation of butanal (an aldehyde)<\/strong>, but this alcohol is stated to not be oxidized, meaning it remains in its alcohol form.<\/li>\n<\/ul>\n\n\n\n
Structures and Explanation:<\/h3>\n\n\n\n\n- Alcohol A (2-methylpropan-2-ol):<\/strong><\/li>\n<\/ol>\n\n\n\n
\n- Branched chain with a central -OH group attached to a secondary carbon.<\/li>\n<\/ul>\n\n\n\n
\n- Alcohol B (butan-2-ol):<\/strong><\/li>\n<\/ol>\n\n\n\n
\n- Linear chain with a central -OH group attached to a secondary carbon.<\/li>\n<\/ul>\n\n\n\n
\n- Alcohol C (1-butanol):<\/strong><\/li>\n<\/ol>\n\n\n\n
\n- Linear chain with a primary -OH group at the end.<\/li>\n<\/ul>\n\n\n\n
Now, I\u2019ll generate an image with the Lewis structures for each of these alcohols.<\/p>\n\n\n\n
Here are the Lewis structures for the three alcohols:<\/p>\n\n\n\n
\n- 2-methylpropan-2-ol (Alcohol A)<\/strong>: This structure shows a branched chain with the hydroxyl group attached to a secondary carbon.<\/li>\n\n\n\n
- Butan-2-ol (Alcohol B)<\/strong>: This structure is a linear chain with the hydroxyl group attached to a secondary carbon.<\/li>\n\n\n\n
- 1-butanol (Alcohol C)<\/strong>: This structure is a linear chain with the hydroxyl group attached to a primary carbon at the end of the chain.<\/li>\n<\/ol>\n\n\n\n
Let me know if you need any further clarification!<\/p>\n\n\n\n![\"\"](\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/02\/image-974.png\")
<\/figure>\n","protected":false},"excerpt":{"rendered":"Alcohols A, B, and C all have the composition C4H10O. Molecules of alcohol A contain a branched carbon chain and can be oxidized to an aldehyde; molecules of alcohol B contain a linear carbon chain and can be oxidized to a ketone; and molecules of alcohol C can be oxidized to neither an aldehyde nor […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-193252","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/193252","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=193252"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/193252\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=193252"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=193252"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=193252"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
Alcohol B:<\/h3>\n\n\n\n\n- Alcohol B has a linear carbon chain and can be oxidized to a ketone. This suggests that alcohol B is a secondary alcohol<\/strong> with a linear structure. It will likely be butan-2-ol<\/strong>.<\/li>\n\n\n\n
- The central carbon in butan-2-ol is attached to a hydroxyl group (-OH) and two other carbons. When oxidized, it forms butanone (methyl ethyl ketone)<\/strong>, a ketone.<\/li>\n<\/ul>\n\n\n\n
Alcohol C:<\/h3>\n\n\n\n\n- Alcohol C cannot be oxidized to an aldehyde or a ketone. This suggests that it is a primary alcohol<\/strong> with a hydroxyl group attached to a carbon atom at the end of the chain. The oxidation of primary alcohols usually results in the formation of aldehydes or carboxylic acids, so alcohol C must be 1-butanol<\/strong>.<\/li>\n\n\n\n
- In this case, the alcohol group is on the terminal carbon, and oxidation would lead to the formation of butanal (an aldehyde)<\/strong>, but this alcohol is stated to not be oxidized, meaning it remains in its alcohol form.<\/li>\n<\/ul>\n\n\n\n
Structures and Explanation:<\/h3>\n\n\n\n\n- Alcohol A (2-methylpropan-2-ol):<\/strong><\/li>\n<\/ol>\n\n\n\n
\n- Branched chain with a central -OH group attached to a secondary carbon.<\/li>\n<\/ul>\n\n\n\n
\n- Alcohol B (butan-2-ol):<\/strong><\/li>\n<\/ol>\n\n\n\n
\n- Linear chain with a central -OH group attached to a secondary carbon.<\/li>\n<\/ul>\n\n\n\n
\n- Alcohol C (1-butanol):<\/strong><\/li>\n<\/ol>\n\n\n\n
\n- Linear chain with a primary -OH group at the end.<\/li>\n<\/ul>\n\n\n\n
Now, I\u2019ll generate an image with the Lewis structures for each of these alcohols.<\/p>\n\n\n\n
Here are the Lewis structures for the three alcohols:<\/p>\n\n\n\n
\n- 2-methylpropan-2-ol (Alcohol A)<\/strong>: This structure shows a branched chain with the hydroxyl group attached to a secondary carbon.<\/li>\n\n\n\n
- Butan-2-ol (Alcohol B)<\/strong>: This structure is a linear chain with the hydroxyl group attached to a secondary carbon.<\/li>\n\n\n\n
- 1-butanol (Alcohol C)<\/strong>: This structure is a linear chain with the hydroxyl group attached to a primary carbon at the end of the chain.<\/li>\n<\/ol>\n\n\n\n
Let me know if you need any further clarification!<\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Alcohols A, B, and C all have the composition C4H10O. Molecules of alcohol A contain a branched carbon chain and can be oxidized to an aldehyde; molecules of alcohol B contain a linear carbon chain and can be oxidized to a ketone; and molecules of alcohol C can be oxidized to neither an aldehyde nor […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-193252","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/193252","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=193252"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/193252\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=193252"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=193252"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=193252"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
Alcohol C:<\/h3>\n\n\n\n\n- Alcohol C cannot be oxidized to an aldehyde or a ketone. This suggests that it is a primary alcohol<\/strong> with a hydroxyl group attached to a carbon atom at the end of the chain. The oxidation of primary alcohols usually results in the formation of aldehydes or carboxylic acids, so alcohol C must be 1-butanol<\/strong>.<\/li>\n\n\n\n
- In this case, the alcohol group is on the terminal carbon, and oxidation would lead to the formation of butanal (an aldehyde)<\/strong>, but this alcohol is stated to not be oxidized, meaning it remains in its alcohol form.<\/li>\n<\/ul>\n\n\n\n
Structures and Explanation:<\/h3>\n\n\n\n\n- Alcohol A (2-methylpropan-2-ol):<\/strong><\/li>\n<\/ol>\n\n\n\n
\n- Branched chain with a central -OH group attached to a secondary carbon.<\/li>\n<\/ul>\n\n\n\n
\n- Alcohol B (butan-2-ol):<\/strong><\/li>\n<\/ol>\n\n\n\n
\n- Linear chain with a central -OH group attached to a secondary carbon.<\/li>\n<\/ul>\n\n\n\n
\n- Alcohol C (1-butanol):<\/strong><\/li>\n<\/ol>\n\n\n\n
\n- Linear chain with a primary -OH group at the end.<\/li>\n<\/ul>\n\n\n\n
Now, I\u2019ll generate an image with the Lewis structures for each of these alcohols.<\/p>\n\n\n\n
Here are the Lewis structures for the three alcohols:<\/p>\n\n\n\n
\n- 2-methylpropan-2-ol (Alcohol A)<\/strong>: This structure shows a branched chain with the hydroxyl group attached to a secondary carbon.<\/li>\n\n\n\n
- Butan-2-ol (Alcohol B)<\/strong>: This structure is a linear chain with the hydroxyl group attached to a secondary carbon.<\/li>\n\n\n\n
- 1-butanol (Alcohol C)<\/strong>: This structure is a linear chain with the hydroxyl group attached to a primary carbon at the end of the chain.<\/li>\n<\/ol>\n\n\n\n
Let me know if you need any further clarification!<\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Alcohols A, B, and C all have the composition C4H10O. Molecules of alcohol A contain a branched carbon chain and can be oxidized to an aldehyde; molecules of alcohol B contain a linear carbon chain and can be oxidized to a ketone; and molecules of alcohol C can be oxidized to neither an aldehyde nor […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-193252","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/193252","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=193252"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/193252\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=193252"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=193252"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=193252"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
Structures and Explanation:<\/h3>\n\n\n\n\n- Alcohol A (2-methylpropan-2-ol):<\/strong><\/li>\n<\/ol>\n\n\n\n
\n- Branched chain with a central -OH group attached to a secondary carbon.<\/li>\n<\/ul>\n\n\n\n
\n- Alcohol B (butan-2-ol):<\/strong><\/li>\n<\/ol>\n\n\n\n
\n- Linear chain with a central -OH group attached to a secondary carbon.<\/li>\n<\/ul>\n\n\n\n
\n- Alcohol C (1-butanol):<\/strong><\/li>\n<\/ol>\n\n\n\n
\n- Linear chain with a primary -OH group at the end.<\/li>\n<\/ul>\n\n\n\n
Now, I\u2019ll generate an image with the Lewis structures for each of these alcohols.<\/p>\n\n\n\n
Here are the Lewis structures for the three alcohols:<\/p>\n\n\n\n
\n- 2-methylpropan-2-ol (Alcohol A)<\/strong>: This structure shows a branched chain with the hydroxyl group attached to a secondary carbon.<\/li>\n\n\n\n
- Butan-2-ol (Alcohol B)<\/strong>: This structure is a linear chain with the hydroxyl group attached to a secondary carbon.<\/li>\n\n\n\n
- 1-butanol (Alcohol C)<\/strong>: This structure is a linear chain with the hydroxyl group attached to a primary carbon at the end of the chain.<\/li>\n<\/ol>\n\n\n\n
Let me know if you need any further clarification!<\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"Alcohols A, B, and C all have the composition C4H10O. Molecules of alcohol A contain a branched carbon chain and can be oxidized to an aldehyde; molecules of alcohol B contain a linear carbon chain and can be oxidized to a ketone; and molecules of alcohol C can be oxidized to neither an aldehyde nor […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-193252","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/193252","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=193252"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/193252\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=193252"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=193252"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=193252"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
- \n
- Branched chain with a central -OH group attached to a secondary carbon.<\/li>\n<\/ul>\n\n\n\n
- \n
- Alcohol B (butan-2-ol):<\/strong><\/li>\n<\/ol>\n\n\n\n
- \n
- Linear chain with a central -OH group attached to a secondary carbon.<\/li>\n<\/ul>\n\n\n\n
- \n
- Alcohol C (1-butanol):<\/strong><\/li>\n<\/ol>\n\n\n\n
- \n
- Linear chain with a primary -OH group at the end.<\/li>\n<\/ul>\n\n\n\n
Now, I\u2019ll generate an image with the Lewis structures for each of these alcohols.<\/p>\n\n\n\n
Here are the Lewis structures for the three alcohols:<\/p>\n\n\n\n
- \n
- 2-methylpropan-2-ol (Alcohol A)<\/strong>: This structure shows a branched chain with the hydroxyl group attached to a secondary carbon.<\/li>\n\n\n\n
- Butan-2-ol (Alcohol B)<\/strong>: This structure is a linear chain with the hydroxyl group attached to a secondary carbon.<\/li>\n\n\n\n
- 1-butanol (Alcohol C)<\/strong>: This structure is a linear chain with the hydroxyl group attached to a primary carbon at the end of the chain.<\/li>\n<\/ol>\n\n\n\n
Let me know if you need any further clarification!<\/p>\n\n\n\n
<\/figure>\n","protected":false},"excerpt":{"rendered":"Alcohols A, B, and C all have the composition C4H10O. Molecules of alcohol A contain a branched carbon chain and can be oxidized to an aldehyde; molecules of alcohol B contain a linear carbon chain and can be oxidized to a ketone; and molecules of alcohol C can be oxidized to neither an aldehyde nor […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-193252","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/193252","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=193252"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/193252\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=193252"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=193252"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=193252"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
- Butan-2-ol (Alcohol B)<\/strong>: This structure is a linear chain with the hydroxyl group attached to a secondary carbon.<\/li>\n\n\n\n
- 2-methylpropan-2-ol (Alcohol A)<\/strong>: This structure shows a branched chain with the hydroxyl group attached to a secondary carbon.<\/li>\n\n\n\n
- Linear chain with a primary -OH group at the end.<\/li>\n<\/ul>\n\n\n\n
- Alcohol C (1-butanol):<\/strong><\/li>\n<\/ol>\n\n\n\n
- Linear chain with a central -OH group attached to a secondary carbon.<\/li>\n<\/ul>\n\n\n\n
- Alcohol B (butan-2-ol):<\/strong><\/li>\n<\/ol>\n\n\n\n