{"id":193797,"date":"2025-02-21T04:40:44","date_gmt":"2025-02-21T04:40:44","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=193797"},"modified":"2025-02-21T04:40:47","modified_gmt":"2025-02-21T04:40:47","slug":"what-best-describes-the-following","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/21\/what-best-describes-the-following\/","title":{"rendered":"What best describes the following"},"content":{"rendered":"\n

What best describes the following?<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

A)The Fischer projection of L-fructose and an anomer of D-fructose written in the Haworth projection<\/p>\n\n\n\n

B)The Haworth projection of D-fructose and both anomers of D-fructose written in the Fischer projection<\/p>\n\n\n\n

C)The Fischer projection of L-fructose and both anomers of L-fructose written in the Haworth projection<\/p>\n\n\n\n

D) The Fischer projection of D-glucose and both anomers of D-glucose written in the Haworth projection<\/p>\n\n\n\n

The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n

The correct answer is D) The Fischer projection of D-glucose and both anomers of D-glucose written in the Haworth projection.<\/strong><\/p>\n\n\n\n

Explanation:<\/h3>\n\n\n\n
    \n
  1. Fischer Projection<\/strong>:
    The Fischer projection, shown on the left side of the image, is a method of representing the three-dimensional structure of molecules in a two-dimensional plane. The Fischer projection in the provided image clearly depicts D-glucose due to the arrangement of hydroxyl groups (-OH) on the second, third, fourth, and fifth carbon atoms. For D-glucose, the -OH groups on the second, fourth, and fifth carbons are on the right, and the -OH on the third carbon is on the left, consistent with the D-configuration.<\/li>\n\n\n\n
  2. Haworth Projection<\/strong>:
    The two structures on the right side of the image are the Haworth projections of D-glucose. The Haworth projection is a simplified way to show the cyclic form of sugars. These structures represent the cyclic forms of glucose, namely the \u03b1 and \u03b2 anomers. The anomeric carbon (the former carbonyl carbon, carbon 1) in these cyclic forms can have the -OH group positioned either below the plane of the ring (\u03b1-anomer) or above the plane of the ring (\u03b2-anomer). The diagrams show one anomer with the -OH below (\u03b1-D-glucose) and the other with the -OH above (\u03b2-D-glucose).<\/li>\n\n\n\n
  3. Determining D vs. L and Anomers<\/strong>:
    The difference between D and L sugars in the Fischer projection is determined by the position of the -OH on the last chiral center (carbon 5 for glucose). Since it is on the right side, it indicates a D-sugar. The anomers are distinguished by the position of the -OH group at the anomeric carbon (carbon 1) after ring closure.<\/li>\n\n\n\n
  4. Elimination of Other Options<\/strong>:<\/li>\n<\/ol>\n\n\n\n
      \n
    • Option A is incorrect because L-fructose and D-fructose are not involved here.<\/li>\n\n\n\n
    • Option B incorrectly describes the molecules as fructose and inverts the naming of the Fischer and Haworth projections.<\/li>\n\n\n\n
    • Option C is incorrect because it mentions L-fructose, which is not represented in the image.<\/li>\n<\/ul>\n\n\n\n

      This explanation demonstrates that the structures depicted are related to D-glucose, not fructose, and certainly not the L-forms of any sugars. Thus, Option D is correct, indicating both the linear and cyclic forms of D-glucose.<\/p>\n","protected":false},"excerpt":{"rendered":"

      What best describes the following? A)The Fischer projection of L-fructose and an anomer of D-fructose written in the Haworth projection B)The Haworth projection of D-fructose and both anomers of D-fructose written in the Fischer projection C)The Fischer projection of L-fructose and both anomers of L-fructose written in the Haworth projection D) The Fischer projection of […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-193797","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/193797","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=193797"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/193797\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=193797"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=193797"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=193797"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}