{"id":193939,"date":"2025-02-22T05:47:20","date_gmt":"2025-02-22T05:47:20","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=193939"},"modified":"2025-02-22T05:47:22","modified_gmt":"2025-02-22T05:47:22","slug":"consider-a-mixture-of-three-different-gases-1-40-g-of-argon-molecular-mass-39-948-g-mol","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/22\/consider-a-mixture-of-three-different-gases-1-40-g-of-argon-molecular-mass-39-948-g-mol\/","title":{"rendered":"Consider a mixture of three different gases: 1.40 g of argon (molecular mass = 39.948 g\/mol)"},"content":{"rendered":"\n<p>Consider a mixture of three different gases: 1.40 g of argon (molecular mass = 39.948 g\/mol), 2.70 g of neon (molecular mass = 20.180 g\/mol), and 3.50 g of helium (molecular mass = 4.0026 g\/mol). For this mixture, determine the percentage of the total number of atoms that corresponds to each of the components.<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>The percentage of the total number of atoms corresponding to each component in the mixture is:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Argon:<\/strong> 3.36%<\/li>\n\n\n\n<li><strong>Neon:<\/strong> 12.82%<\/li>\n\n\n\n<li><strong>Helium:<\/strong> 83.82%<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>We are given a mixture of three gases: argon, neon, and helium. To determine the percentage of each component in terms of the number of atoms, we follow these steps:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Calculate the number of moles of each gas<\/strong><br>Using the formula:<br>[<br>\\text{Moles} = \\frac{\\text{Mass}}{\\text{Molar Mass}}<br>]<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Argon:<\/strong><br>[<br>\\frac{1.40 \\text{ g}}{39.948 \\text{ g\/mol}} = 0.03504 \\text{ moles}<br>]<\/li>\n\n\n\n<li><strong>Neon:<\/strong><br>[<br>\\frac{2.70 \\text{ g}}{20.180 \\text{ g\/mol}} = 0.1338 \\text{ moles}<br>]<\/li>\n\n\n\n<li><strong>Helium:<\/strong><br>[<br>\\frac{3.50 \\text{ g}}{4.0026 \\text{ g\/mol}} = 0.8744 \\text{ moles}<br>]<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Calculate the total number of moles<\/strong><br>[<br>0.03504 + 0.1338 + 0.8744 = 1.0432 \\text{ moles}<br>]<\/li>\n\n\n\n<li><strong>Find the percentage of each gas in terms of moles (which corresponds to the number of atoms)<\/strong><br>[<br>\\text{Percentage} = \\left( \\frac{\\text{Moles of gas}}{\\text{Total moles}} \\right) \\times 100<br>]<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Argon:<br>[<br>\\left( \\frac{0.03504}{1.0432} \\right) \\times 100 = 3.36\\%<br>]<\/li>\n\n\n\n<li>Neon:<br>[<br>\\left( \\frac{0.1338}{1.0432} \\right) \\times 100 = 12.82\\%<br>]<\/li>\n\n\n\n<li>Helium:<br>[<br>\\left( \\frac{0.8744}{1.0432} \\right) \\times 100 = 83.82\\%<br>]<\/li>\n<\/ul>\n\n\n\n<p>Since all gases are monatomic, the percentage of moles directly translates to the percentage of atoms.<\/p>\n\n\n\n<p>I will now generate an image representing these percentages.<\/p>\n\n\n\n<p>Here is a pie chart illustrating the percentage of total atoms contributed by each gas in the mixture. As seen, helium has the largest proportion (83.82%), followed by neon (12.82%) and argon (3.36%). This dominance is due to helium\u2019s significantly lower molar mass, which results in a higher number of moles (and thus atoms) compared to the other gases.<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/02\/image-1172-1024x803.png\" alt=\"\" class=\"wp-image-193940\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Consider a mixture of three different gases: 1.40 g of argon (molecular mass = 39.948 g\/mol), 2.70 g of neon (molecular mass = 20.180 g\/mol), and 3.50 g of helium (molecular mass = 4.0026 g\/mol). For this mixture, determine the percentage of the total number of atoms that corresponds to each of the components. The [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-193939","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/193939","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=193939"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/193939\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=193939"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=193939"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=193939"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}