{"id":193989,"date":"2025-02-22T06:34:12","date_gmt":"2025-02-22T06:34:12","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=193989"},"modified":"2025-02-22T06:34:15","modified_gmt":"2025-02-22T06:34:15","slug":"for-each-pair-of-reactants-will-there-be-a-reaction","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/22\/for-each-pair-of-reactants-will-there-be-a-reaction\/","title":{"rendered":"For each pair of reactants, will there be a reaction"},"content":{"rendered":"\n<p>For each pair of reactants, will there be a reaction?<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/02\/image-1190.png\" alt=\"\" class=\"wp-image-193990\"\/><\/figure>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Reaction Analysis for Given Reactant Pairs<\/strong><\/h3>\n\n\n\n<p>To determine whether a reaction will occur, we need to analyze the activity series of metals. A metal will replace another metal in a compound only if it is more reactive (i.e., higher in the activity series). The activity series ranks metals from most reactive to least reactive. Here\u2019s the assessment:<\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>1. Al(s) + Ba(NO\u2083)\u2082(aq) \u2192 No Reaction<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Explanation:<\/strong> Aluminum (Al) is lower than Barium (Ba) in the activity series, meaning Al is <strong>less reactive<\/strong> than Ba. Since Al cannot replace Ba in <strong>Ba(NO\u2083)\u2082<\/strong>, <strong>no reaction occurs<\/strong>.<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>2. Cr(s) + Co(NO\u2083)\u2082(aq) \u2192 Reaction Occurs<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Explanation:<\/strong> Chromium (Cr) is <strong>higher<\/strong> than Cobalt (Co) in the activity series. This means Cr is more reactive and can <strong>displace<\/strong> Co from <strong>Co(NO\u2083)\u2082<\/strong>, forming Cr(NO\u2083)\u2083 and solid Co.<\/li>\n\n\n\n<li><strong>Balanced Reaction:<\/strong><br>[<br>2Cr(s) + 3Co(NO\u2083)\u2082(aq) \u2192 2Cr(NO\u2083)\u2083(aq) + 3Co(s)<br>]<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>3. Zn(s) + HCl(aq) \u2192 Reaction Occurs<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Explanation:<\/strong> Zinc (Zn) is more reactive than Hydrogen (H\u2082). Zn will react with hydrochloric acid (HCl), replacing hydrogen and forming <strong>ZnCl\u2082<\/strong> and <strong>H\u2082 gas<\/strong>.<\/li>\n\n\n\n<li><strong>Balanced Reaction:<\/strong><br>[<br>Zn(s) + 2HCl(aq) \u2192 ZnCl\u2082(aq) + H\u2082(g)<br>]<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>4. Zn(s) + CuSO\u2084(aq) \u2192 Reaction Occurs<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Explanation:<\/strong> Zinc (Zn) is more reactive than Copper (Cu) and will replace Cu from CuSO\u2084, forming <strong>ZnSO\u2084<\/strong> and <strong>solid Cu<\/strong>.<\/li>\n\n\n\n<li><strong>Balanced Reaction:<\/strong><br>[<br>Zn(s) + CuSO\u2084(aq) \u2192 ZnSO\u2084(aq) + Cu(s)<br>]<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Conclusion<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>No reaction:<\/strong> Al(s) + Ba(NO\u2083)\u2082(aq)<\/li>\n\n\n\n<li><strong>Reaction occurs:<\/strong> Cr(s) + Co(NO\u2083)\u2082(aq)<\/li>\n\n\n\n<li><strong>Reaction occurs:<\/strong> Zn(s) + HCl(aq)<\/li>\n\n\n\n<li><strong>Reaction occurs:<\/strong> Zn(s) + CuSO\u2084(aq)<\/li>\n<\/ul>\n\n\n\n<p>Now, I will generate an image representing these reactions.<\/p>\n\n\n\n<p>The image visually represents the chemical reactions, showing which ones occur and which do not. Let me know if you need any modifications or further explanations!<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/02\/image-1191.png\" alt=\"\" class=\"wp-image-193991\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>For each pair of reactants, will there be a reaction? The Correct Answer and Explanation is : Reaction Analysis for Given Reactant Pairs To determine whether a reaction will occur, we need to analyze the activity series of metals. A metal will replace another metal in a compound only if it is more reactive (i.e., [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-193989","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/193989","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=193989"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/193989\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=193989"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=193989"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=193989"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}