{"id":194305,"date":"2025-02-23T07:56:02","date_gmt":"2025-02-23T07:56:02","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=194305"},"modified":"2025-02-23T07:56:07","modified_gmt":"2025-02-23T07:56:07","slug":"calculate-the-average-atomic-mass-of-silver","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/23\/calculate-the-average-atomic-mass-of-silver\/","title":{"rendered":"Calculate the average atomic mass of silver"},"content":{"rendered":"\n<p> Calculate the average atomic mass of silver. The percentages denote the relative abundances. Isotope 109 Ag 47 107 amu Rel. Abundance Atomic Mass 48.16% 51.84% 108.905 amu 106.905 amu<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>To calculate the <strong>average atomic mass of silver (Ag)<\/strong>, we use the formula:<\/p>\n\n\n\n<p>[<br>\\text{Average Atomic Mass} = (\\text{mass of isotope}_1 \\times \\text{relative abundance}_1) + (\\text{mass of isotope}_2 \\times \\text{relative abundance}_2)<br>]<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Given Data:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Isotope 1:<\/strong> ( ^{107}Ag )<\/li>\n\n\n\n<li>Mass = <strong>106.905 amu<\/strong><\/li>\n\n\n\n<li>Relative Abundance = <strong>51.84% = 0.5184<\/strong><\/li>\n\n\n\n<li><strong>Isotope 2:<\/strong> ( ^{109}Ag )<\/li>\n\n\n\n<li>Mass = <strong>108.905 amu<\/strong><\/li>\n\n\n\n<li>Relative Abundance = <strong>48.16% = 0.4816<\/strong><\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Calculation:<\/h3>\n\n\n\n<p>[<br>\\text{Average Atomic Mass} = (106.905 \\times 0.5184) + (108.905 \\times 0.4816)<br>]<\/p>\n\n\n\n<p>[<br>= 55.456 \\, + \\, 52.434<br>]<\/p>\n\n\n\n<p>[<br>= 107.87 \\, \\text{amu}<br>]<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>The <strong>average atomic mass<\/strong> of an element is a <strong>weighted average<\/strong> of all its isotopes based on their natural abundances. Silver has <strong>two stable isotopes<\/strong>: (^{107}Ag) and (^{109}Ag), which occur in almost equal proportions.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Why use a weighted average?<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Elements exist as mixtures of isotopes in nature, and their atomic mass depends on the <strong>relative proportion of each isotope<\/strong>.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Importance of Relative Abundance<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>If an isotope is more abundant, it <strong>contributes more<\/strong> to the average atomic mass. In silver, <strong>(^{107}Ag)<\/strong> has a <strong>slightly higher abundance (51.84%)<\/strong>, so the average mass is <strong>closer to its atomic mass<\/strong> (106.905 amu).<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Final Value in Periodic Table<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The calculated <strong>107.87 amu<\/strong> matches the atomic mass of silver in the periodic table.<\/li>\n<\/ul>\n\n\n\n<p>Thus, the <strong>average atomic mass of silver is 107.87 amu<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p>Now, I will generate an image representing this calculation.<\/p>\n\n\n\n<p>Here is the image illustrating the calculation of the average atomic mass of silver. Let me know if you need any modifications or additional details!<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/02\/image-1286.png\" alt=\"\" class=\"wp-image-194306\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Calculate the average atomic mass of silver. The percentages denote the relative abundances. Isotope 109 Ag 47 107 amu Rel. Abundance Atomic Mass 48.16% 51.84% 108.905 amu 106.905 amu The Correct Answer and Explanation is : To calculate the average atomic mass of silver (Ag), we use the formula: [\\text{Average Atomic Mass} = (\\text{mass of [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-194305","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/194305","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=194305"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/194305\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=194305"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=194305"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=194305"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}