{"id":194508,"date":"2025-02-24T08:20:12","date_gmt":"2025-02-24T08:20:12","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=194508"},"modified":"2025-02-24T08:20:15","modified_gmt":"2025-02-24T08:20:15","slug":"complete-the-equation-for-the-dissociation-of-the-electrolyte-agno-aq","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/24\/complete-the-equation-for-the-dissociation-of-the-electrolyte-agno-aq\/","title":{"rendered":"Complete the equation for the dissociation of the electrolyte AgNO, (aq)"},"content":{"rendered":"\n

1. Complete the equation for the dissociation of the electrolyte AgNO, (aq). Omit water from the equation because it is understood to be present. equation: AgNO, (aq) — I<\/p>\n\n\n\n

2. Convert 13.6 g\/cm3 <\/sup>to kg\/m3<\/sup><\/p>\n\n\n\n

The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n

1. Complete the Equation for the Dissociation of AgNO\u2083 in Water:<\/h3>\n\n\n\n

Silver nitrate (AgNO\u2083) is a strong electrolyte, meaning it completely dissociates in water into its constituent ions:<\/p>\n\n\n\n

[
\\text{AgNO}_3 (aq) \\rightarrow \\text{Ag}^+ (aq) + \\text{NO}_3^- (aq)
]<\/p>\n\n\n\n

2. Convert 13.6 g\/cm\u00b3 to kg\/m\u00b3:<\/h3>\n\n\n\n

We use the following unit conversions:<\/p>\n\n\n\n

    \n
  • (1 \\text{ g} = 10^{-3} \\text{ kg})<\/li>\n\n\n\n
  • (1 \\text{ cm}^3 = 10^{-6} \\text{ m}^3)<\/li>\n<\/ul>\n\n\n\n

    Now, applying these conversions:<\/p>\n\n\n\n

    [
    13.6 \\frac{g}{cm^3} \\times \\frac{10^{-3} \\text{ kg}}{1 \\text{ g}} \\times \\frac{10^6 \\text{ cm}^3}{1 \\text{ m}^3}
    ]<\/p>\n\n\n\n

    [
    = 13.6 \\times 10^3 \\frac{kg}{m^3}
    ]<\/p>\n\n\n\n

    [
    = 13,600 \\frac{kg}{m^3}
    ]<\/p>\n\n\n\n

    Thus, 13.6 g\/cm\u00b3 = 13,600 kg\/m\u00b3<\/strong>.<\/p>\n\n\n\n

    \n\n\n\n

    Explanation:<\/h3>\n\n\n\n

    Density is defined as mass per unit volume. The given density is in grams per cubic centimeter (g\/cm\u00b3)<\/strong>, but we need to convert it to kilograms per cubic meter (kg\/m\u00b3)<\/strong>.<\/p>\n\n\n\n

      \n
    1. Understanding the Conversion Factors<\/strong><\/li>\n<\/ol>\n\n\n\n
        \n
      • 1 gram (g) = 0.001 kilograms (kg)<\/li>\n\n\n\n
      • 1 cubic centimeter (cm\u00b3) = (10^{-6}) cubic meters (m\u00b3)<\/li>\n<\/ul>\n\n\n\n
          \n
        1. Conversion from g\/cm\u00b3 to kg\/m\u00b3<\/strong><\/li>\n<\/ol>\n\n\n\n
            \n
          • Since there are 1,000 grams in a kilogram<\/strong>, converting from grams to kilograms requires multiplying by (10^{-3}).<\/li>\n\n\n\n
          • Since there are 1,000,000 cm\u00b3 in a cubic meter<\/strong>, converting cm\u00b3 to m\u00b3 requires multiplying by (10^6).<\/li>\n<\/ul>\n\n\n\n
              \n
            1. Applying the Calculation<\/strong><\/li>\n<\/ol>\n\n\n\n
                \n
              • First, convert grams to kilograms:
                (13.6 \\text{ g} = 13.6 \\times 10^{-3} \\text{ kg})<\/li>\n\n\n\n
              • Next, convert cm\u00b3 to m\u00b3:
                (1 \\text{ cm}^3 = 10^{-6} \\text{ m}^3)<\/li>\n\n\n\n
              • Combining both, we get:
                ( \\frac{13.6 \\times 10^{-3} \\text{ kg}}{10^{-6} \\text{ m}^3} = 13.6 \\times 10^3 \\text{ kg\/m}^3 )<\/li>\n\n\n\n
              • This simplifies to 13,600 kg\/m\u00b3<\/strong>.<\/li>\n<\/ul>\n\n\n\n

                This conversion is often used in physics and engineering, especially for materials like mercury, which has a high density of 13.6 g\/cm\u00b3 (or 13,600 kg\/m\u00b3). The ability to convert between units is crucial for practical applications, including fluid mechanics, material science, and chemistry.<\/p>\n\n\n\n

                \n\n\n\n

                Now, I’ll generate an image related to this conversion.<\/p>\n\n\n\n

                Here is the educational infographic illustrating the conversion of density from g\/cm\u00b3 to kg\/m\u00b3, including a step-by-step breakdown of the calculation. Let me know if you need any modifications or additional explanations!<\/p>\n\n\n\n

                \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

                1. Complete the equation for the dissociation of the electrolyte AgNO, (aq). Omit water from the equation because it is understood to be present. equation: AgNO, (aq) — I 2. Convert 13.6 g\/cm3 to kg\/m3 The Correct Answer and Explanation is : 1. Complete the Equation for the Dissociation of AgNO\u2083 in Water: Silver nitrate (AgNO\u2083) […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-194508","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/194508","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=194508"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/194508\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=194508"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=194508"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=194508"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}