{"id":194564,"date":"2025-02-24T09:14:44","date_gmt":"2025-02-24T09:14:44","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=194564"},"modified":"2025-02-24T09:14:47","modified_gmt":"2025-02-24T09:14:47","slug":"the-electron-domain-and-molecular-geometry-of-bro2-is-2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/24\/the-electron-domain-and-molecular-geometry-of-bro2-is-2\/","title":{"rendered":"The electron domain and molecular geometry of BrO2- is"},"content":{"rendered":"\n

The electron domain and molecular geometry of BrO2- is
A tetrahedral, bent
B. trigonal pyramidal, seesaw
C. trigonal pyramidal, linear
D. tetrahedral, trigonal planar
E. trigonal planar, trigonal planar<\/p>\n\n\n\n

The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n

The correct answer is:<\/p>\n\n\n\n

A. Tetrahedral, Bent<\/strong><\/p>\n\n\n\n

Explanation:<\/h3>\n\n\n\n
    \n
  1. Lewis Structure of BrO\u2082\u207b<\/strong><\/li>\n<\/ol>\n\n\n\n
      \n
    • Bromine (Br) has 7 valence electrons<\/strong>.<\/li>\n\n\n\n
    • Oxygen (O) has 6 valence electrons<\/strong> (each).<\/li>\n\n\n\n
    • The negative charge (-1)<\/strong> adds one extra electron<\/strong>.<\/li>\n\n\n\n
    • Total valence electrons:
      [
      7 + (6 \\times 2) + 1 = 19
      ]<\/li>\n\n\n\n
    • Bromine is the central atom, bonded to two oxygens<\/strong> and has lone pairs<\/strong>.<\/li>\n<\/ul>\n\n\n\n
        \n
      1. Electron Domains (VSEPR Theory)<\/strong><\/li>\n<\/ol>\n\n\n\n
          \n
        • There are four electron domains<\/strong> around Br:\n
            \n
          • Two bonding pairs<\/strong> (Br\u2013O bonds)<\/li>\n\n\n\n
          • Two lone pairs<\/strong><\/li>\n<\/ul>\n<\/li>\n\n\n\n
          • This corresponds to a tetrahedral electron domain geometry<\/strong>.<\/li>\n<\/ul>\n\n\n\n
              \n
            1. Molecular Geometry<\/strong><\/li>\n<\/ol>\n\n\n\n
                \n
              • The molecular geometry<\/strong> is determined by the positions of atoms.<\/li>\n\n\n\n
              • The two lone pairs<\/strong> push the bonded oxygen atoms downward, creating a bent shape<\/strong>.<\/li>\n\n\n\n
              • This is similar to water (H\u2082O), which has a tetrahedral electron domain but a bent molecular shape.<\/li>\n<\/ul>\n\n\n\n
                  \n
                1. Bond Angles<\/strong><\/li>\n<\/ol>\n\n\n\n
                    \n
                  • A perfect tetrahedral shape has 109.5\u00b0<\/strong> angles.<\/li>\n\n\n\n
                  • However, lone pairs repel more strongly<\/strong>, slightly reducing the O\u2013Br\u2013O angle to less than 109.5\u00b0<\/strong>.<\/li>\n<\/ul>\n\n\n\n

                    Conclusion:<\/h3>\n\n\n\n
                      \n
                    • Electron Domain Geometry:<\/strong> Tetrahedral<\/strong><\/li>\n\n\n\n
                    • Molecular Geometry:<\/strong> Bent<\/strong><\/li>\n<\/ul>\n\n\n\n

                      Thus, the correct answer is A. Tetrahedral, Bent<\/strong>.<\/p>\n\n\n\n

                      Now, I’ll generate an image of the molecular structure of BrO\u2082\u207b.<\/p>\n\n\n\n

                      \"\"<\/figure>\n\n\n\n

                      Here is the 3D molecular structure of the bromite ion (BrO\u2082\u207b), showing its tetrahedral electron domain geometry and bent molecular shape. Let me know if you need any modifications or further explanations!<\/p>\n","protected":false},"excerpt":{"rendered":"

                      The electron domain and molecular geometry of BrO2- isA tetrahedral, bentB. trigonal pyramidal, seesawC. trigonal pyramidal, linearD. tetrahedral, trigonal planarE. trigonal planar, trigonal planar The Correct Answer and Explanation is : The correct answer is: A. Tetrahedral, Bent Explanation: Conclusion: Thus, the correct answer is A. Tetrahedral, Bent. Now, I’ll generate an image of the […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-194564","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/194564","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=194564"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/194564\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=194564"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=194564"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=194564"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}