{"id":194570,"date":"2025-02-24T09:23:13","date_gmt":"2025-02-24T09:23:13","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=194570"},"modified":"2025-02-24T09:23:17","modified_gmt":"2025-02-24T09:23:17","slug":"draw-the-addition-products-formed-when-one-equivalent-of-hbr-reacts-with-24-hexadiene","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/24\/draw-the-addition-products-formed-when-one-equivalent-of-hbr-reacts-with-24-hexadiene\/","title":{"rendered":"Draw the addition products formed when one equivalent of HBr reacts with 2,4-hexadiene"},"content":{"rendered":"\n

Draw the addition products formed when one equivalent of HBr reacts with 2,4-hexadiene. Draw a single product for each gnore stereochemical or chiral isomers<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n

When one equivalent of HBr reacts with 2,4-hexadiene<\/strong>, the major products form via electrophilic addition<\/strong>, following Markovnikov’s Rule<\/strong>. Let’s analyze the reaction step by step.<\/p>\n\n\n\n

Reaction Mechanism:<\/strong><\/h3>\n\n\n\n
    \n
  1. Protonation of the Diene:<\/strong><\/li>\n<\/ol>\n\n\n\n
      \n
    • HBr provides H\u207a<\/strong> (proton) and Br\u207b<\/strong> (bromide ion).<\/li>\n\n\n\n
    • The proton preferentially adds to the carbon of the double bond that already has more hydrogen atoms<\/strong> (Markovnikov’s Rule).<\/li>\n\n\n\n
    • This leads to the formation of a carbocation intermediate<\/strong>, with the positive charge on the more substituted carbon (more stable).<\/li>\n<\/ul>\n\n\n\n
        \n
      1. Carbocation Rearrangement and Bromide Attack:<\/strong><\/li>\n<\/ol>\n\n\n\n
          \n
        • The Br\u207b ion then attacks the carbocation<\/strong>, forming the final product.<\/li>\n\n\n\n
        • The reaction can occur at either C2=C3<\/strong> or C4=C5<\/strong> double bonds in 2,4-hexadiene<\/strong>, leading to two possible products.<\/li>\n<\/ul>\n\n\n\n

          Possible Products:<\/strong><\/h3>\n\n\n\n
            \n
          1. Addition at the C2=C3 Double Bond:<\/strong><\/li>\n<\/ol>\n\n\n\n
              \n
            • H\u207a adds to C2<\/strong>, forming a carbocation at C3<\/strong>.<\/li>\n\n\n\n
            • Br\u207b then attacks C3<\/strong>, leading to 3-Bromo-2-hexene<\/strong>.<\/li>\n<\/ul>\n\n\n\n
                \n
              1. Addition at the C4=C5 Double Bond:<\/strong><\/li>\n<\/ol>\n\n\n\n
                  \n
                • H\u207a adds to C4<\/strong>, forming a carbocation at C5<\/strong>.<\/li>\n\n\n\n
                • Br\u207b then attacks C5<\/strong>, leading to 5-Bromo-4-hexene<\/strong>.<\/li>\n<\/ul>\n\n\n\n

                  Since stereochemistry is ignored, we only consider regioisomers<\/strong> (positional isomers).<\/p>\n\n\n\n

                  Now, I’ll generate an image of the reaction products.<\/p>\n\n\n\n

                  \"\"<\/figure>\n\n\n\n

                  Here is the reaction diagram illustrating the electrophilic addition of HBr to 2,4-hexadiene, showing the formation of the two major products: 3-Bromo-2-hexene<\/strong> and 5-Bromo-4-hexene<\/strong>. Let me know if you need further clarification!<\/p>\n","protected":false},"excerpt":{"rendered":"

                  Draw the addition products formed when one equivalent of HBr reacts with 2,4-hexadiene. Draw a single product for each gnore stereochemical or chiral isomers The Correct Answer and Explanation is : When one equivalent of HBr reacts with 2,4-hexadiene, the major products form via electrophilic addition, following Markovnikov’s Rule. Let’s analyze the reaction step by […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-194570","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/194570","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=194570"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/194570\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=194570"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=194570"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=194570"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}