{"id":194578,"date":"2025-02-24T09:28:16","date_gmt":"2025-02-24T09:28:16","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=194578"},"modified":"2025-02-24T09:28:18","modified_gmt":"2025-02-24T09:28:18","slug":"complete-an-orbital-diagram-for-boron","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/24\/complete-an-orbital-diagram-for-boron\/","title":{"rendered":"Complete an orbital diagram for boron"},"content":{"rendered":"\n<p>Complete an orbital diagram for boron.<br>Drag the appropriate labels to their respective targets. Labels can be used once, more than once, or not at all.<br>14 1<br>15<br>2s<br>2p<br>35<br>3p<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Orbital Diagram for Boron (B)<\/strong><\/h3>\n\n\n\n<p>Boron has an atomic number of <strong>5<\/strong>, meaning it has <strong>5 electrons<\/strong>. The electron configuration for boron is:<\/p>\n\n\n\n<p>[<br>1s^2 2s^2 2p^1<br>]<\/p>\n\n\n\n<p>This means the electrons are arranged in the following orbitals:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>1s<\/strong>: 2 electrons (full)<\/li>\n\n\n\n<li><strong>2s<\/strong>: 2 electrons (full)<\/li>\n\n\n\n<li><strong>2p<\/strong>: 1 electron (partially filled)<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Orbital Diagram Representation<\/strong><\/h3>\n\n\n\n<p>The orbital diagram visually represents electron configurations using <strong>boxes<\/strong> (or lines) for orbitals and <strong>arrows<\/strong> for electrons. Each orbital can hold up to <strong>two electrons<\/strong> with opposite spins.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>1s Orbital<\/strong> \u2192 Filled with <strong>two electrons<\/strong> (\u2191\u2193)<\/li>\n\n\n\n<li><strong>2s Orbital<\/strong> \u2192 Filled with <strong>two electrons<\/strong> (\u2191\u2193)<\/li>\n\n\n\n<li><strong>2p Orbital<\/strong> \u2192 Has <strong>one electron<\/strong> (\u2191)<\/li>\n<\/ol>\n\n\n\n<p>Using Hund\u2019s rule, which states that electrons will occupy degenerate orbitals singly before pairing, the single electron in the <strong>2p<\/strong> orbital will occupy one of the three available p orbitals.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Labels to be Placed Correctly:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>1s<\/strong> \u2192 Fully filled with 2 electrons <strong>(\u2191\u2193)<\/strong><\/li>\n\n\n\n<li><strong>2s<\/strong> \u2192 Fully filled with 2 electrons <strong>(\u2191\u2193)<\/strong><\/li>\n\n\n\n<li><strong>2p<\/strong> \u2192 One electron <strong>(\u2191)<\/strong><\/li>\n\n\n\n<li><strong>3s and 3p<\/strong> \u2192 Not used (since boron only has 5 electrons)<\/li>\n<\/ul>\n\n\n\n<p>Now, I will generate an image of the correct orbital diagram.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/02\/image-1372.png\" alt=\"\" class=\"wp-image-194579\"\/><\/figure>\n\n\n\n<p>Here is the orbital diagram for boron. It correctly represents the electron configuration with electrons placed in the <strong>1s, 2s, and 2p orbitals<\/strong> following Hund\u2019s rule. Let me know if you need any modifications!<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Complete an orbital diagram for boron.Drag the appropriate labels to their respective targets. Labels can be used once, more than once, or not at all.14 1152s2p353p The Correct Answer and Explanation is : Orbital Diagram for Boron (B) Boron has an atomic number of 5, meaning it has 5 electrons. The electron configuration for boron [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-194578","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/194578","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=194578"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/194578\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=194578"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=194578"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=194578"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}