{"id":194645,"date":"2025-02-24T10:34:44","date_gmt":"2025-02-24T10:34:44","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=194645"},"modified":"2025-02-24T10:34:47","modified_gmt":"2025-02-24T10:34:47","slug":"give-the-iupac-name-for-each-of-the-following","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/24\/give-the-iupac-name-for-each-of-the-following\/","title":{"rendered":"Give the IUPAC name for each of the following"},"content":{"rendered":"\n<p>Give the IUPAC name for each of the following: . CH3 -CH2-CH,-0-OH 0 Co-CH b. CH3-CH2-C-0-CH2-CH: 0 c. CH3-CH;-CH2-CH2-C-OH<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/02\/image-1397.png\" alt=\"\" class=\"wp-image-194646\"\/><\/figure>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>Let&#8217;s analyze each compound and determine its <strong>IUPAC name<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>1. CH\u2083-CH\u2082-CH\u2082-OH<\/strong><\/h3>\n\n\n\n<p>This compound consists of a three-carbon chain with a <strong>hydroxyl (-OH) functional group<\/strong> attached to the terminal carbon.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The longest carbon chain has <strong>three carbons<\/strong>, meaning the parent name is <strong>propane<\/strong>.<\/li>\n\n\n\n<li>The presence of the hydroxyl (-OH) group changes <strong>propane \u2192 propanol<\/strong>.<\/li>\n\n\n\n<li>Since the -OH group is on carbon <strong>1<\/strong>, the correct <strong>IUPAC name<\/strong> is <strong>propan-1-ol<\/strong>.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>2. CH\u2083-CH\u2082-C(=O)-CH\u2083<\/strong><\/h3>\n\n\n\n<p>This compound contains a <strong>ketone (-CO) functional group<\/strong>.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The longest chain has <strong>four carbons<\/strong>, meaning the parent name is <strong>butane<\/strong>.<\/li>\n\n\n\n<li>The <strong>ketone (-CO) group<\/strong> changes butane \u2192 <strong>butanone<\/strong>.<\/li>\n\n\n\n<li>The carbonyl (-CO) is on carbon <strong>2<\/strong> (since ketones are assigned the lowest number possible).<\/li>\n\n\n\n<li>Thus, the <strong>IUPAC name<\/strong> is <strong>butan-2-one<\/strong>.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>3. CH\u2083-CH\u2082-C(=O)-CH\u2082-CH\u2083<\/strong><\/h3>\n\n\n\n<p>This compound contains a <strong>ketone (-CO) functional group<\/strong> as well.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The longest chain consists of <strong>five carbons<\/strong> (pentane).<\/li>\n\n\n\n<li>The <strong>ketone (-CO) group<\/strong> changes pentane \u2192 <strong>pentanone<\/strong>.<\/li>\n\n\n\n<li>The carbonyl (-CO) is at <strong>carbon 2<\/strong>.<\/li>\n\n\n\n<li>Thus, the <strong>IUPAC name<\/strong> is <strong>pentan-2-one<\/strong>.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>4. CH\u2083-CH\u2082-CH\u2082-CH\u2082-C(=O)-OH<\/strong><\/h3>\n\n\n\n<p>This compound has a <strong>carboxyl (-COOH) functional group<\/strong>, making it a <strong>carboxylic acid<\/strong>.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The longest chain has <strong>five carbons<\/strong> (pentane).<\/li>\n\n\n\n<li>The <strong>carboxyl (-COOH) group<\/strong> changes pentane \u2192 <strong>pentanoic acid<\/strong>.<\/li>\n\n\n\n<li>The carboxyl (-COOH) is always assigned carbon <strong>1<\/strong>.<\/li>\n\n\n\n<li>The <strong>IUPAC name<\/strong> is <strong>pentanoic acid<\/strong>.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation (300 words)<\/strong><\/h3>\n\n\n\n<p>The <strong>IUPAC nomenclature system<\/strong> provides a standard method for naming organic compounds. The name of an organic molecule depends on:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>The longest carbon chain<\/strong> \u2013 Determines the parent name (e.g., methane, ethane, propane, etc.).<\/li>\n\n\n\n<li><strong>The functional group<\/strong> \u2013 Determines the suffix or priority.<\/li>\n\n\n\n<li><strong>The numbering of the chain<\/strong> \u2013 Assigns the lowest possible number to the functional group.<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Alcohols (-OH):<\/strong> Named with the <strong>-ol<\/strong> suffix (e.g., propan-1-ol).<\/li>\n\n\n\n<li><strong>Ketones (-CO-):<\/strong> Named with the <strong>-one<\/strong> suffix (e.g., butan-2-one).<\/li>\n\n\n\n<li><strong>Carboxylic acids (-COOH):<\/strong> Named with the <strong>-oic acid<\/strong> suffix (e.g., pentanoic acid).<\/li>\n<\/ul>\n\n\n\n<p>For alcohols, the position of the hydroxyl (-OH) is indicated with a number. For ketones, numbering ensures the <strong>carbonyl (-CO) group<\/strong> gets the lowest number. Carboxylic acids always have <strong>priority<\/strong> over other groups, and the -COOH group is always at carbon 1.<\/p>\n\n\n\n<p>Correct IUPAC names ensure clear communication and avoid ambiguity in chemical identification.<\/p>\n\n\n\n<p>Now, I will generate an <strong>image<\/strong> of the molecular structures.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/02\/image-1398.png\" alt=\"\" class=\"wp-image-194647\"\/><\/figure>\n\n\n\n<p>Here is the generated educational chemistry diagram showing the molecular structures of the given organic compounds with their IUPAC names and molecular formulas. Let me know if you need any modifications or further explanations!<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Give the IUPAC name for each of the following: . CH3 -CH2-CH,-0-OH 0 Co-CH b. CH3-CH2-C-0-CH2-CH: 0 c. CH3-CH;-CH2-CH2-C-OH The Correct Answer and Explanation is : Let&#8217;s analyze each compound and determine its IUPAC name. 1. CH\u2083-CH\u2082-CH\u2082-OH This compound consists of a three-carbon chain with a hydroxyl (-OH) functional group attached to the terminal carbon. [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-194645","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/194645","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=194645"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/194645\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=194645"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=194645"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=194645"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}