{"id":194904,"date":"2025-02-25T09:13:09","date_gmt":"2025-02-25T09:13:09","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=194904"},"modified":"2025-02-25T09:13:13","modified_gmt":"2025-02-25T09:13:13","slug":"hydrochloric-acid-reacts-with-barium-hydroxide-according-to-the-equation-2hclaqbaoh2aq-bacl2aq2h2ol-deltah-118-kj","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/25\/hydrochloric-acid-reacts-with-barium-hydroxide-according-to-the-equation-2hclaqbaoh2aq-bacl2aq2h2ol-deltah-118-kj\/","title":{"rendered":"hydrochloric acid reacts with barium hydroxide according to the equation : 2HCl(aq)+Ba(OH)2(AQ)->BaCl2(aq)+2H2O(l) DeltaH= -118 kj"},"content":{"rendered":"\n

hydrochloric acid reacts with barium hydroxide according to the equation : 2HCl(aq)+Ba(OH)2(AQ)->BaCl2(aq)+2H2O(l) DeltaH= -118 kj Calculate the heat (in kj) associated with the complete reaction of 36.5 grams of HCl (aq)<\/p>\n\n\n\n

The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n

Explanation:<\/h3>\n\n\n\n

The balanced chemical equation for the reaction between hydrochloric acid (HCl) and barium hydroxide (Ba(OH)\u2082) is: 2HCl(aq)+Ba(OH)2(aq)\u2192BaCl2(aq)+2H2O(l)2HCl(aq) + Ba(OH)_2(aq) \\rightarrow BaCl_2(aq) + 2H_2O(l)<\/p>\n\n\n\n

The given enthalpy change (\u0394H\\Delta H) for this reaction is \u2212118-118 kJ, which means that when 2 moles<\/strong> of HCl react completely, 118 kJ of heat is released<\/strong>.<\/p>\n\n\n\n

Step 1: Determine the Moles of HCl<\/strong><\/h4>\n\n\n\n

We are given 36.5 grams of HCl. The molar mass of HCl is: Molar mass of HCl=1+35.5=36.5 g\/mol\\text{Molar mass of HCl} = 1 + 35.5 = 36.5 \\text{ g\/mol}<\/p>\n\n\n\n

Thus, the number of moles of HCl present in 36.5 g is: Moles of HCl=Mass of HClMolar mass of HCl=36.536.5=1 mole\\text{Moles of HCl} = \\frac{\\text{Mass of HCl}}{\\text{Molar mass of HCl}} = \\frac{36.5}{36.5} = 1 \\text{ mole}<\/p>\n\n\n\n

Step 2: Calculate the Heat Released<\/strong><\/h4>\n\n\n\n

From the equation, 2 moles of HCl<\/strong> release 118 kJ<\/strong> of heat. So, for 1 mole<\/strong> of HCl, the heat released is: Heat released=(12\u00d7(\u2212118))=\u221259.0 kJ\\text{Heat released} = \\left(\\frac{1}{2} \\times (-118)\\right) = -59.0 \\text{ kJ}<\/p>\n\n\n\n

Final Answer:<\/strong><\/h4>\n\n\n\n

The heat released when 36.5 g of HCl reacts completely<\/strong> is -59.0 kJ<\/strong> (negative sign indicates exothermic reaction).<\/p>\n\n\n\n

Now, I’ll generate an image illustrating this reaction and energy release.<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

Here is an illustration of the reaction between hydrochloric acid (HCl) and barium hydroxide (Ba(OH)\u2082), showing the mixing process, product formation, and heat release (-59.0 kJ). Let me know if you need any modifications!<\/p>\n","protected":false},"excerpt":{"rendered":"

hydrochloric acid reacts with barium hydroxide according to the equation : 2HCl(aq)+Ba(OH)2(AQ)->BaCl2(aq)+2H2O(l) DeltaH= -118 kj Calculate the heat (in kj) associated with the complete reaction of 36.5 grams of HCl (aq) The Correct Answer and Explanation is : Explanation: The balanced chemical equation for the reaction between hydrochloric acid (HCl) and barium hydroxide (Ba(OH)\u2082) is: […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-194904","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/194904","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=194904"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/194904\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=194904"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=194904"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=194904"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}