{"id":194940,"date":"2025-02-25T09:46:16","date_gmt":"2025-02-25T09:46:16","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=194940"},"modified":"2025-02-25T09:46:19","modified_gmt":"2025-02-25T09:46:19","slug":"what-is-the-correct-iupac-name-for-cr2so43","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/25\/what-is-the-correct-iupac-name-for-cr2so43\/","title":{"rendered":"what is the correct IUPAC name for Cr2(SO4)3"},"content":{"rendered":"\n<p>what is the correct IUPAC name for Cr2(SO4)3<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Correct IUPAC Name for Cr\u2082(SO\u2084)\u2083<\/strong><\/h3>\n\n\n\n<p>The correct <strong>IUPAC name<\/strong> for <strong>Cr\u2082(SO\u2084)\u2083<\/strong> is <strong>Chromium(III) sulfate<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation:<\/strong><\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Understanding the Compound\u2019s Composition<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The given chemical formula <strong>Cr\u2082(SO\u2084)\u2083<\/strong> consists of two <strong>chromium (Cr) atoms<\/strong> and three <strong>sulfate (SO\u2084\u00b2\u207b) ions<\/strong>.<\/li>\n\n\n\n<li>Chromium is a <strong>transition metal<\/strong>, and sulfate is a polyatomic anion.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Determining the Oxidation State of Chromium<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The sulfate ion (SO\u2084\u00b2\u207b) has a charge of <strong>-2<\/strong>.<\/li>\n\n\n\n<li>Since there are <strong>three sulfate ions<\/strong>, the total negative charge is:<br>[<br>3 \\times (-2) = -6<br>]<\/li>\n\n\n\n<li>To balance this charge, the <strong>two chromium atoms<\/strong> must have a total positive charge of <strong>+6<\/strong>.<\/li>\n\n\n\n<li>Therefore, each <strong>chromium atom<\/strong> has an oxidation state of <strong>+3<\/strong>.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Naming the Compound<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>In IUPAC nomenclature, <strong>transition metals<\/strong> require <strong>Roman numerals<\/strong> to indicate their oxidation state.<\/li>\n\n\n\n<li>Since chromium has a <strong>+3 oxidation state<\/strong>, it is written as <strong>Chromium(III)<\/strong>.<\/li>\n\n\n\n<li>The polyatomic ion <strong>sulfate (SO\u2084\u00b2\u207b)<\/strong> retains its name.<\/li>\n\n\n\n<li>Combining these, the correct IUPAC name is:<br><strong>Chromium(III) sulfate<\/strong>.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Final Answer:<\/strong><\/h3>\n\n\n\n<p>The correct IUPAC name for <strong>Cr\u2082(SO\u2084)\u2083<\/strong> is <strong>Chromium(III) sulfate<\/strong>.<\/p>\n\n\n\n<p>Now, I will generate an image of <strong>Chromium(III) sulfate<\/strong>, showing its molecular structure.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/02\/image-1485.png\" alt=\"\" class=\"wp-image-194941\"\/><\/figure>\n\n\n\n<p>Here is the generated molecular structure of <strong>Chromium(III) sulfate (Cr\u2082(SO\u2084)\u2083)<\/strong>. It visually represents the chromium ions and sulfate groups in their correct ionic arrangement. Let me know if you need any modifications or further clarifications!<\/p>\n","protected":false},"excerpt":{"rendered":"<p>what is the correct IUPAC name for Cr2(SO4)3 The Correct Answer and Explanation is : Correct IUPAC Name for Cr\u2082(SO\u2084)\u2083 The correct IUPAC name for Cr\u2082(SO\u2084)\u2083 is Chromium(III) sulfate. Explanation: Final Answer: The correct IUPAC name for Cr\u2082(SO\u2084)\u2083 is Chromium(III) sulfate. Now, I will generate an image of Chromium(III) sulfate, showing its molecular structure. Here [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-194940","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/194940","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=194940"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/194940\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=194940"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=194940"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=194940"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}