{"id":194978,"date":"2025-02-25T10:34:10","date_gmt":"2025-02-25T10:34:10","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=194978"},"modified":"2025-02-25T10:34:13","modified_gmt":"2025-02-25T10:34:13","slug":"when-chlorine-gas-reacts-with-methane-the-product-formed","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/25\/when-chlorine-gas-reacts-with-methane-the-product-formed\/","title":{"rendered":"When chlorine gas reacts with methane, the product formed"},"content":{"rendered":"\n<p>When chlorine gas reacts with methane, the product formed is a) CHCl b) CH2Cl c) CH3Cl d) CH4Cl<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>The correct answer is <strong>(c) CH\u2083Cl (Methyl chloride)<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>When chlorine gas (<strong>Cl\u2082<\/strong>) reacts with methane (<strong>CH\u2084<\/strong>), a <strong>substitution reaction<\/strong> occurs. This reaction is an example of a <strong>free radical substitution reaction<\/strong>, which takes place in the presence of <strong>ultraviolet (UV) light<\/strong> or high temperatures.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Stepwise Reaction Mechanism:<\/strong><\/h4>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Initiation (Formation of Free Radicals):<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Under UV light, chlorine molecules (<strong>Cl\u2082<\/strong>) undergo <strong>homolytic fission<\/strong>, breaking into two chlorine radicals (<strong>Cl\u2022<\/strong>):<br>[<br>Cl_2 \\xrightarrow{UV} 2Cl\u2022<br>]<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Propagation (Radical Chain Reaction):<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>A chlorine radical reacts with methane, abstracting a hydrogen atom and forming a methyl radical (<strong>CH\u2083\u2022<\/strong>):<br>[<br>CH_4 + Cl\u2022 \\rightarrow CH_3\u2022 + HCl<br>]<\/li>\n\n\n\n<li>The methyl radical then reacts with another chlorine molecule, forming methyl chloride (<strong>CH\u2083Cl<\/strong>) and generating another chlorine radical:<br>[<br>CH_3\u2022 + Cl_2 \\rightarrow CH_3Cl + Cl\u2022<br>]<\/li>\n\n\n\n<li>This newly formed <strong>Cl\u2022<\/strong> continues the chain reaction, leading to further substitution if excess chlorine is present.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Termination (Stopping the Chain Reaction):<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The reaction stops when two free radicals combine to form a stable molecule:<br>[<br>Cl\u2022 + Cl\u2022 \\rightarrow Cl_2<br>]<br>[<br>CH_3\u2022 + Cl\u2022 \\rightarrow CH_3Cl<br>]<br>[<br>CH_3\u2022 + CH_3\u2022 \\rightarrow C_2H_6 (ethane)<br>]<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Final Product:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The primary product is <strong>methyl chloride (CH\u2083Cl)<\/strong>.<\/li>\n\n\n\n<li>If excess chlorine is present, further chlorination can lead to <strong>dichloromethane (CH\u2082Cl\u2082), chloroform (CHCl\u2083), and carbon tetrachloride (CCl\u2084)<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p>Thus, the correct answer is <strong>CH\u2083Cl<\/strong>.<\/p>\n\n\n\n<p>Now, I will generate an image representing this reaction.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/02\/image-1496.png\" alt=\"\" class=\"wp-image-194979\"\/><\/figure>\n\n\n\n<p>Here is the generated image illustrating the chlorination of methane, showing the reaction mechanism with labeled molecular structures. Let me know if you need any modifications or further explanations!<\/p>\n","protected":false},"excerpt":{"rendered":"<p>When chlorine gas reacts with methane, the product formed is a) CHCl b) CH2Cl c) CH3Cl d) CH4Cl The Correct Answer and Explanation is : The correct answer is (c) CH\u2083Cl (Methyl chloride). Explanation: When chlorine gas (Cl\u2082) reacts with methane (CH\u2084), a substitution reaction occurs. This reaction is an example of a free radical [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-194978","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/194978","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=194978"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/194978\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=194978"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=194978"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=194978"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}