{"id":195009,"date":"2025-02-25T11:12:17","date_gmt":"2025-02-25T11:12:17","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=195009"},"modified":"2025-02-25T11:12:19","modified_gmt":"2025-02-25T11:12:19","slug":"in-a-neutralization-reaction-between-acetic-acid-and-barium-hydroxide-13-25-ml-of-a-0-125m-baoh_2-solution-was-required-to-neutralize-10-35-ml-of-an-acetic-acid-solution","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/25\/in-a-neutralization-reaction-between-acetic-acid-and-barium-hydroxide-13-25-ml-of-a-0-125m-baoh_2-solution-was-required-to-neutralize-10-35-ml-of-an-acetic-acid-solution\/","title":{"rendered":"In a neutralization reaction between acetic acid and barium hydroxide, 13.25 mL of a 0.125M Ba(OH)_2 solution was required to neutralize 10.35 mL of an acetic acid solution"},"content":{"rendered":"\n<p>In a neutralization reaction between acetic acid and barium hydroxide, 13.25 mL of a 0.125M Ba(OH)_2 solution was required to neutralize 10.35 mL of an acetic acid solution. What is the molarity of the acetic acid solution? You will need to write and balance the equation for the neutralization reaction first.<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Write and Balance the Chemical Equation<\/h3>\n\n\n\n<p>The neutralization reaction between <strong>acetic acid<\/strong> (CH\u2083COOH) and <strong>barium hydroxide<\/strong> (Ba(OH)\u2082) follows this balanced equation:<\/p>\n\n\n\n<p>[<br>2CH_3COOH + Ba(OH)_2 \\rightarrow Ba(CH_3COO)_2 + 2H_2O<br>]<\/p>\n\n\n\n<p>This equation shows that <strong>2 moles of acetic acid<\/strong> react with <strong>1 mole of barium hydroxide<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Find the Moles of Ba(OH)\u2082 Used<\/h3>\n\n\n\n<p>We are given:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Volume of <strong>Ba(OH)\u2082 solution<\/strong> = <strong>13.25 mL<\/strong> = <strong>0.01325 L<\/strong><\/li>\n\n\n\n<li>Molarity of <strong>Ba(OH)\u2082 solution<\/strong> = <strong>0.125 M<\/strong><\/li>\n<\/ul>\n\n\n\n<p>Using the formula:<\/p>\n\n\n\n<p>[<br>\\text{moles} = \\text{Molarity} \\times \\text{Volume}<br>]<\/p>\n\n\n\n<p>[<br>\\text{moles of } Ba(OH)_2 = (0.125 \\,M) \\times (0.01325 \\,L)<br>]<\/p>\n\n\n\n<p>[<br>= 0.00165625 \\text{ moles Ba(OH)\u2082}<br>]<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Use Stoichiometry to Find Moles of Acetic Acid<\/h3>\n\n\n\n<p>From the balanced equation, <strong>1 mole of Ba(OH)\u2082<\/strong> reacts with <strong>2 moles of CH\u2083COOH<\/strong>.<br>Thus, the moles of acetic acid:<\/p>\n\n\n\n<p>[<br>\\text{moles of CH}_3\\text{COOH} = 2 \\times 0.00165625<br>]<\/p>\n\n\n\n<p>[<br>= 0.0033125 \\text{ moles CH}_3\\text{COOH}<br>]<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 4: Find the Molarity of Acetic Acid<\/h3>\n\n\n\n<p>We are given:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Volume of <strong>CH\u2083COOH solution<\/strong> = <strong>10.35 mL<\/strong> = <strong>0.01035 L<\/strong><\/li>\n<\/ul>\n\n\n\n<p>Using:<\/p>\n\n\n\n<p>[<br>\\text{Molarity} = \\frac{\\text{Moles}}{\\text{Volume (L)}}<br>]<\/p>\n\n\n\n<p>[<br>M = \\frac{0.0033125}{0.01035}<br>]<\/p>\n\n\n\n<p>[<br>M = 0.320 M<br>]<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Final Answer:<\/h3>\n\n\n\n<p><strong>The molarity of the acetic acid solution is<\/strong> <strong>0.320 M<\/strong>. \u2705<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>This problem required a step-by-step approach using stoichiometry and molarity concepts. We first balanced the chemical equation, identified the mole ratio, and used it to find the moles of acetic acid. Finally, using the definition of molarity, we determined the acetic acid concentration.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p>Now, I&#8217;ll generate an image illustrating the neutralization reaction.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/02\/image-1506.png\" alt=\"\" class=\"wp-image-195010\"\/><\/figure>\n\n\n\n<p>Here is the scientific illustration depicting the neutralization reaction between acetic acid (CH\u2083COOH) and barium hydroxide (Ba(OH)\u2082). It visually represents the molecular structures and reaction process in an educational format. Let me know if you need any modifications!<\/p>\n","protected":false},"excerpt":{"rendered":"<p>In a neutralization reaction between acetic acid and barium hydroxide, 13.25 mL of a 0.125M Ba(OH)_2 solution was required to neutralize 10.35 mL of an acetic acid solution. What is the molarity of the acetic acid solution? You will need to write and balance the equation for the neutralization reaction first. The Correct Answer and [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-195009","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/195009","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=195009"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/195009\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=195009"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=195009"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=195009"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}