{"id":195012,"date":"2025-02-25T11:14:28","date_gmt":"2025-02-25T11:14:28","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=195012"},"modified":"2025-02-25T11:14:30","modified_gmt":"2025-02-25T11:14:30","slug":"a-certain-radioactive-substance-decays-exponentially","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/25\/a-certain-radioactive-substance-decays-exponentially\/","title":{"rendered":"A certain radioactive substance decays exponentially"},"content":{"rendered":"\n<p>A certain radioactive substance decays exponentially. The percent, P, of the substance left after years is given by the function P() = 100(1.32). Determine the instantaneous rate of decay at the instant the half life of the substance is reached.<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>The given function appears to be incorrectly formatted. The correct general form for exponential decay should be:<\/p>\n\n\n\n<p>[<br>P(t) = 100 \\cdot e^{-kt}<br>]<\/p>\n\n\n\n<p>or<\/p>\n\n\n\n<p>[<br>P(t) = 100 \\cdot a^t<br>]<\/p>\n\n\n\n<p>However, based on your notation, it seems like the decay model is written as:<\/p>\n\n\n\n<p>[<br>P(t) = 100(1.32)^t<br>]<\/p>\n\n\n\n<p>This function represents exponential growth rather than decay since the base is greater than 1. Typically, radioactive decay follows the form:<\/p>\n\n\n\n<p>[<br>P(t) = 100(a)^t, \\quad 0 &lt; a &lt; 1<br>]<\/p>\n\n\n\n<p>To determine the instantaneous rate of decay at the half-life, let&#8217;s proceed step by step:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Find the Half-Life<\/h3>\n\n\n\n<p>The half-life ( t_{1\/2} ) is the time when the substance is reduced to 50% of its original amount. That means:<\/p>\n\n\n\n<p>[<br>50 = 100(1.32)^t<br>]<\/p>\n\n\n\n<p>Solving for ( t ):<\/p>\n\n\n\n<p>[<br>\\frac{50}{100} = (1.32)^t<br>]<\/p>\n\n\n\n<p>[<br>0.5 = (1.32)^t<br>]<\/p>\n\n\n\n<p>Taking the natural logarithm on both sides:<\/p>\n\n\n\n<p>[<br>\\ln(0.5) = t \\ln(1.32)<br>]<\/p>\n\n\n\n<p>[<br>t = \\frac{\\ln(0.5)}{\\ln(1.32)}<br>]<\/p>\n\n\n\n<p>We will compute this value.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Compute Instantaneous Rate of Change<\/h3>\n\n\n\n<p>The derivative of ( P(t) ) is:<\/p>\n\n\n\n<p>[<br>P'(t) = 100 \\cdot \\ln(1.32) \\cdot (1.32)^t<br>]<\/p>\n\n\n\n<p>We substitute ( t_{1\/2} ) to get the instantaneous rate of decay at that moment.<\/p>\n\n\n\n<p>I will now calculate these values and generate an image.<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/02\/image-1507-1024x694.png\" alt=\"\" class=\"wp-image-195013\"\/><\/figure>\n\n\n\n<p>The instantaneous rate of decay at the half-life is approximately <strong>-2.50<\/strong> (negative indicating decay), and the half-life of the substance is about <strong>13.88 years<\/strong>. The graph above illustrates the decay function, highlighting the half-life point where the rate of change was computed. Let me know if you need any further clarification!<\/p>\n","protected":false},"excerpt":{"rendered":"<p>A certain radioactive substance decays exponentially. The percent, P, of the substance left after years is given by the function P() = 100(1.32). Determine the instantaneous rate of decay at the instant the half life of the substance is reached. The Correct Answer and Explanation is : The given function appears to be incorrectly formatted. [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-195012","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/195012","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=195012"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/195012\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=195012"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=195012"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=195012"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}