{"id":195027,"date":"2025-02-25T11:30:20","date_gmt":"2025-02-25T11:30:20","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=195027"},"modified":"2025-02-25T11:30:24","modified_gmt":"2025-02-25T11:30:24","slug":"write-the-electron-configuration-for-a-neutral-atom-of-tin","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/25\/write-the-electron-configuration-for-a-neutral-atom-of-tin\/","title":{"rendered":"Write the electron configuration for a neutral atom of tin"},"content":{"rendered":"\n<p>Write the electron configuration for a neutral atom of tin<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Electron Configuration of a Neutral Tin Atom<\/strong><\/h3>\n\n\n\n<p>The atomic number of tin (Sn) is <strong>50<\/strong>, meaning a neutral tin atom has <strong>50 electrons<\/strong>. The electron configuration follows the Aufbau principle, Hund&#8217;s rule, and the Pauli exclusion principle to fill orbitals in increasing energy levels.<\/p>\n\n\n\n<p>The correct electron configuration for tin is:<br><strong>1s\u00b2 2s\u00b2 2p\u2076 3s\u00b2 3p\u2076 3d\u00b9\u2070 4s\u00b2 4p\u2076 4d\u00b9\u2070 5s\u00b2 5p\u00b2<\/strong><\/p>\n\n\n\n<p>Alternatively, using the noble gas shorthand notation, we use <strong>krypton (Kr, Z=36)<\/strong> as the core:<br><strong>[Kr] 4d\u00b9\u2070 5s\u00b2 5p\u00b2<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation<\/strong><\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Understanding Electron Configuration Rules<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Electrons fill orbitals <strong>from lower to higher energy levels<\/strong> (Aufbau principle).<\/li>\n\n\n\n<li><strong>Each orbital holds two electrons<\/strong> with opposite spins (Pauli exclusion principle).<\/li>\n\n\n\n<li><strong>Orbitals of equal energy fill singly first<\/strong>, then pair up (Hund\u2019s rule).<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Breaking Down Tin\u2019s Configuration<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>First shell (n=1)<\/strong>: 1s\u00b2 \u2192 <strong>2 electrons<\/strong><\/li>\n\n\n\n<li><strong>Second shell (n=2)<\/strong>: 2s\u00b2 2p\u2076 \u2192 <strong>8 electrons<\/strong><\/li>\n\n\n\n<li><strong>Third shell (n=3)<\/strong>: 3s\u00b2 3p\u2076 3d\u00b9\u2070 \u2192 <strong>18 electrons<\/strong><\/li>\n\n\n\n<li><strong>Fourth shell (n=4)<\/strong>: 4s\u00b2 4p\u2076 4d\u00b9\u2070 \u2192 <strong>18 electrons<\/strong><\/li>\n\n\n\n<li><strong>Fifth shell (n=5)<\/strong>: 5s\u00b2 5p\u00b2 \u2192 <strong>4 electrons<\/strong><\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Why Tin Has 5s\u00b2 5p\u00b2 in the Outer Shell<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Tin is in <strong>Group 14<\/strong> of the periodic table, meaning it has <strong>4 valence electrons<\/strong> in the outermost shell (5s\u00b2 5p\u00b2).<\/li>\n\n\n\n<li>These valence electrons determine tin\u2019s <strong>chemical reactivity<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p>Now, I&#8217;ll generate an image representing the electron configuration.<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/02\/image-1512-1024x705.png\" alt=\"\" class=\"wp-image-195028\"\/><\/figure>\n\n\n\n<p>Here is a visual representation of the electron configuration of tin (Sn). The bar chart shows how electrons are distributed across different atomic orbitals, highlighting the filling order of the shells. Let me know if you need any modifications or further explanations!<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Write the electron configuration for a neutral atom of tin The Correct Answer and Explanation is : Electron Configuration of a Neutral Tin Atom The atomic number of tin (Sn) is 50, meaning a neutral tin atom has 50 electrons. The electron configuration follows the Aufbau principle, Hund&#8217;s rule, and the Pauli exclusion principle to [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-195027","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/195027","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=195027"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/195027\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=195027"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=195027"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=195027"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}