{"id":195324,"date":"2025-02-28T07:08:50","date_gmt":"2025-02-28T07:08:50","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=195324"},"modified":"2025-02-28T07:08:53","modified_gmt":"2025-02-28T07:08:53","slug":"draw-the-lewis-structure-for-hccn","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/28\/draw-the-lewis-structure-for-hccn\/","title":{"rendered":"Draw the Lewis structure for HCCN"},"content":{"rendered":"\n<p>Draw the Lewis structure for HCCN. Which answer below represents its VSEPR and molecular shape for the carbon in the structure that is underlined?<br>V trigonal planar<br>M: trigonal planar<br>V linear<br>Me trigonal planar<br>V: linear<br>M linear<br>V: tetrahedral<br>M: tetrahedral<br>V trigonal planar<br>M: bent<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>The correct answer is:<\/p>\n\n\n\n<p><strong>V: linear<\/strong><br><strong>M: linear<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation:<\/strong><\/h3>\n\n\n\n<p>The Lewis structure of <strong>HCCN<\/strong> consists of <strong>hydrogen (H), two carbon (C) atoms, and nitrogen (N)<\/strong>. To determine its shape and molecular geometry using <strong>VSEPR (Valence Shell Electron Pair Repulsion) theory<\/strong>, we follow these steps:<\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>1. Draw the Lewis Structure<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Hydrogen (H)<\/strong> has <strong>one valence electron<\/strong>.<\/li>\n\n\n\n<li><strong>Carbon (C)<\/strong> has <strong>four valence electrons<\/strong>.<\/li>\n\n\n\n<li><strong>Nitrogen (N)<\/strong> has <strong>five valence electrons<\/strong>.<\/li>\n\n\n\n<li>The total valence electrons available:<\/li>\n\n\n\n<li>H = 1<\/li>\n\n\n\n<li>C = 4 \u00d7 2 = 8<\/li>\n\n\n\n<li>N = 5<\/li>\n\n\n\n<li><strong>Total = 14 electrons<\/strong> The <strong>most stable<\/strong> Lewis structure of HCCN follows the octet rule:<\/li>\n\n\n\n<li>Carbon forms a <strong>triple bond<\/strong> with nitrogen (C\u2261N).<\/li>\n\n\n\n<li>The <strong>other carbon<\/strong> forms a <strong>triple bond<\/strong> with the first carbon (C\u2261C).<\/li>\n\n\n\n<li>The hydrogen is <strong>attached to the first carbon<\/strong>. The structure is:<br><strong>H\u2013C\u2261C\u2013N<\/strong><\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>2. Determine Molecular Shape Using VSEPR Theory<\/strong><\/h4>\n\n\n\n<p>VSEPR theory predicts molecular shape by considering <strong>electron domains<\/strong> around the <strong>central atom<\/strong>. The two <strong>carbon atoms<\/strong> are important here.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>First carbon (C1)<\/strong> (connected to H and C):<\/li>\n\n\n\n<li><strong>Electron domains:<\/strong> 2 (one single bond with H, one triple bond with C)<\/li>\n\n\n\n<li><strong>VSEPR shape:<\/strong> <strong>Linear (AX2)<\/strong><\/li>\n\n\n\n<li><strong>Second carbon (C2)<\/strong> (connected to C and N):<\/li>\n\n\n\n<li><strong>Electron domains:<\/strong> 2 (one triple bond with C, one single bond with N)<\/li>\n\n\n\n<li><strong>VSEPR shape:<\/strong> <strong>Linear (AX2)<\/strong><\/li>\n<\/ul>\n\n\n\n<p>Thus, both carbons <strong>adopt a linear geometry<\/strong>. Since the question asks for the VSEPR and molecular geometry for <strong>one carbon<\/strong>, the answer is:<\/p>\n\n\n\n<p>\u2714 <strong>VSEPR: Linear<\/strong><br>\u2714 <strong>Molecular shape: Linear<\/strong><\/p>\n\n\n\n<p>This makes sense because both bonds around each carbon atom have <strong>180\u00b0 bond angles<\/strong>, making the molecule <strong>entirely linear<\/strong>.<\/p>\n\n\n\n<p>Now, I will generate the Lewis structure image for <strong>HCCN<\/strong>.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/02\/image-1597.png\" alt=\"\" class=\"wp-image-195325\"\/><\/figure>\n\n\n\n<p>Here is the Lewis structure diagram of the <strong>HCCN<\/strong> molecule. The diagram accurately represents the bonding structure, showing the single bond between <strong>H and C<\/strong>, the <strong>triple bond<\/strong> between <strong>C\u2261C<\/strong>, and the <strong>triple bond<\/strong> between <strong>C\u2261N<\/strong>, along with the lone pair on nitrogen.<\/p>\n\n\n\n<p>Let me know if you need further clarifications!<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Draw the Lewis structure for HCCN. Which answer below represents its VSEPR and molecular shape for the carbon in the structure that is underlined?V trigonal planarM: trigonal planarV linearMe trigonal planarV: linearM linearV: tetrahedralM: tetrahedralV trigonal planarM: bent The Correct Answer and Explanation is : The correct answer is: V: linearM: linear Explanation: The Lewis [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-195324","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/195324","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=195324"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/195324\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=195324"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=195324"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=195324"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}