{"id":195518,"date":"2025-02-28T10:35:11","date_gmt":"2025-02-28T10:35:11","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=195518"},"modified":"2025-02-28T10:35:13","modified_gmt":"2025-02-28T10:35:13","slug":"molecular-formula-fcn","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/28\/molecular-formula-fcn\/","title":{"rendered":"Molecular formula FCN"},"content":{"rendered":"\n<p>Molecular formula FCN<br>(a) Draw the Lewis structure<br>(b) Formal charge of C<br>(c) Polar or nonpolar<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">(a) <strong>Lewis Structure of FCN (Fluorocyanide)<\/strong><\/h3>\n\n\n\n<p>To draw the Lewis structure of FCN:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Count Valence Electrons:<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Fluorine (F) = 7 valence electrons<\/li>\n\n\n\n<li>Carbon (C) = 4 valence electrons<\/li>\n\n\n\n<li>Nitrogen (N) = 5 valence electrons<\/li>\n\n\n\n<li>Total = <strong>16 valence electrons<\/strong><\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Determine Bonding:<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Carbon is the central atom (it is the least electronegative except for hydrogen).<\/li>\n\n\n\n<li>Carbon forms a <strong>single bond with fluorine (F)<\/strong> and a <strong>triple bond with nitrogen (N)<\/strong> to satisfy the octet rule.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Distribute Electrons:<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Carbon follows the octet rule with <strong>four bonds (one with fluorine, three with nitrogen)<\/strong>.<\/li>\n\n\n\n<li>Nitrogen gets a lone pair to complete its octet.<\/li>\n\n\n\n<li>Fluorine gets three lone pairs to complete its octet.<\/li>\n<\/ul>\n\n\n\n<p>The correct <strong>Lewis structure<\/strong> has <strong>F\u2014C\u2261N<\/strong>, where:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>A <strong>single bond<\/strong> exists between <strong>C and F<\/strong>.<\/li>\n\n\n\n<li>A <strong>triple bond<\/strong> exists between <strong>C and N<\/strong>.<\/li>\n\n\n\n<li><strong>Lone pairs<\/strong> are present on <strong>F<\/strong> and <strong>N<\/strong>.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">(b) <strong>Formal Charge on Carbon<\/strong><\/h3>\n\n\n\n<p>The formal charge is calculated as:<br>[<br>\\text{Formal Charge} = \\text{Valence Electrons} &#8211; \\text{Nonbonding Electrons} &#8211; \\frac{\\text{Bonding Electrons}}{2}<br>]<\/p>\n\n\n\n<p>For <strong>Carbon (C)<\/strong> in FCN:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Valence electrons: <strong>4<\/strong><\/li>\n\n\n\n<li>Nonbonding electrons: <strong>0<\/strong><\/li>\n\n\n\n<li>Bonding electrons: <strong>8<\/strong> (one single bond with F = 2, one triple bond with N = 6)<br>[<br>4 &#8211; 0 &#8211; \\frac{8}{2} = 4 &#8211; 4 = 0<br>]<br>Thus, the <strong>formal charge on Carbon is 0<\/strong>.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">(c) <strong>Polarity: Polar or Nonpolar?<\/strong><\/h3>\n\n\n\n<p><strong>FCN is a polar molecule.<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Reasoning:<\/strong><\/li>\n\n\n\n<li>The molecule is linear (<strong>F\u2014C\u2261N<\/strong>), but the atoms have <strong>different electronegativities<\/strong>:\n<ul class=\"wp-block-list\">\n<li>Fluorine (F) = <strong>3.98<\/strong> (very electronegative)<\/li>\n\n\n\n<li>Carbon (C) = <strong>2.55<\/strong><\/li>\n\n\n\n<li>Nitrogen (N) = <strong>3.04<\/strong><\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>The <strong>C\u2013F<\/strong> bond is <strong>highly polar<\/strong>, pulling electrons towards fluorine.<\/li>\n\n\n\n<li>The <strong>C\u2261N<\/strong> bond is also polar, but less so than C\u2013F.<\/li>\n\n\n\n<li>Since fluorine is much more electronegative than nitrogen, the molecule has a <strong>net dipole moment<\/strong>, making it <strong>polar<\/strong>.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Conclusion<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Lewis Structure:<\/strong> <strong>F\u2014C\u2261N<\/strong><\/li>\n\n\n\n<li><strong>Formal Charge of Carbon:<\/strong> <strong>0<\/strong><\/li>\n\n\n\n<li><strong>Polarity:<\/strong> <strong>Polar molecule<\/strong> due to electronegativity differences and molecular dipole.<\/li>\n<\/ul>\n\n\n\n<p>Now, I&#8217;ll generate the image of the <strong>Lewis structure<\/strong> for FCN.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/02\/image-1662.png\" alt=\"\" class=\"wp-image-195519\"\/><\/figure>\n\n\n\n<p>Here is the Lewis structure diagram for the FCN (fluorocyanide) molecule. Let me know if you need any modifications or further explanations!<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Molecular formula FCN(a) Draw the Lewis structure(b) Formal charge of C(c) Polar or nonpolar The Correct Answer and Explanation is : (a) Lewis Structure of FCN (Fluorocyanide) To draw the Lewis structure of FCN: The correct Lewis structure has F\u2014C\u2261N, where: (b) Formal Charge on Carbon The formal charge is calculated as:[\\text{Formal Charge} = \\text{Valence [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-195518","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/195518","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=195518"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/195518\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=195518"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=195518"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=195518"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}