{"id":195548,"date":"2025-02-28T12:33:10","date_gmt":"2025-02-28T12:33:10","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=195548"},"modified":"2025-02-28T12:33:12","modified_gmt":"2025-02-28T12:33:12","slug":"after-completing-a-lab-experiment-where-2-1-g-of-isoborneol-molar-mass154-25-g-mol-was-used-with-7-ml-of-glacial-acetic-acid-molar-mass60-052-g-mol","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/28\/after-completing-a-lab-experiment-where-2-1-g-of-isoborneol-molar-mass154-25-g-mol-was-used-with-7-ml-of-glacial-acetic-acid-molar-mass60-052-g-mol\/","title":{"rendered":"After Completing A Lab Experiment Where 2.1 G Of Isoborneol (Molar Mass=154.25 G\/Mol) Was Used With 7 ML Of Glacial Acetic Acid (Molar Mass=60.052 G\/Mol"},"content":{"rendered":"\n
After Completing A Lab Experiment Where 2.1 G Of Isoborneol (Molar Mass=154.25 G\/Mol) Was Used With 7 ML Of Glacial Acetic Acid (Molar Mass=60.052 G\/Mol; Density= 1.05 G\/ML), And 18 ML Of Bleach (Nacio). 1.838 G Of Camphor Was Obtained (Molar Mass=152.23 G\/Mol). Find The Limiting Reagent<\/p>\n\n\n\n
The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n
Solution: Finding the Limiting Reagent<\/strong><\/h3>\n\n\n\n
Step 1: Convert Given Masses and Volumes to Moles<\/strong><\/h4>\n\n\n\n
2. Moles of Acetic Acid<\/strong> First, find the mass of acetic acid: [ \\text{Mass} = \\text{Density} \\times \\text{Volume} = (1.05 \\text{ g\/mL}) \\times (7 \\text{ mL}) = 7.35 \\text{ g} ] Now, convert to moles: [ \\text{Moles} = \\frac{7.35 \\text{ g}}{60.052 \\text{ g\/mol}} = 0.1224 \\text{ moles} ]<\/p>\n\n\n\n
3. Moles of Bleach (Sodium Hypochlorite, NaOCl)<\/strong> Since the concentration of bleach is not given, we assume it to be a standard household bleach solution (~5% NaOCl by weight). Assuming its density is ~1.10 g\/mL, and its molar mass is 74.44 g\/mol:<\/p>\n\n\n\n
From the balanced reaction, the molar ratio of isoborneol to NaOCl is 1:1<\/strong>.<\/p>\n\n\n\n
\n
Moles of isoborneol = 0.01362 moles<\/strong><\/li>\n\n\n\n
Moles of NaOCl = 0.0133 moles<\/strong><\/li>\n<\/ul>\n\n\n\n
Since NaOCl has fewer moles, NaOCl is the limiting reagent<\/strong>.<\/p>\n\n\n\n\n\n\n\n
Conclusion<\/strong><\/h3>\n\n\n\n
The limiting reagent is sodium hypochlorite (NaOCl)<\/strong> since it has fewer moles than isoborneol and is consumed first in the reaction. This means the amount of camphor formed is determined by the moles of NaOCl available.<\/p>\n\n\n\n
Now, I will generate an image illustrating this reaction.<\/p>\n\n\n\n<\/figure>\n\n\n\n
I’ve generated an image illustrating the oxidation of isoborneol to camphor, including labeled glassware, chemical quantities, and the final product on a weighing scale. Let me know if you need any modifications or additional details!<\/p>\n","protected":false},"excerpt":{"rendered":"
After Completing A Lab Experiment Where 2.1 G Of Isoborneol (Molar Mass=154.25 G\/Mol) Was Used With 7 ML Of Glacial Acetic Acid (Molar Mass=60.052 G\/Mol; Density= 1.05 G\/ML), And 18 ML Of Bleach (Nacio). 1.838 G Of Camphor Was Obtained (Molar Mass=152.23 G\/Mol). Find The Limiting Reagent The Correct Answer and Explanation is : Solution: […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-195548","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/195548","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=195548"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/195548\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=195548"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=195548"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=195548"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
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