{"id":195559,"date":"2025-02-28T12:47:46","date_gmt":"2025-02-28T12:47:46","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=195559"},"modified":"2025-02-28T12:48:01","modified_gmt":"2025-02-28T12:48:01","slug":"aspirin-acetylsalicylic-acid-hc9h7o4-is-a-weak-acid","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/02\/28\/aspirin-acetylsalicylic-acid-hc9h7o4-is-a-weak-acid\/","title":{"rendered":"Aspirin (acetylsalicylic acid, HC9H7O4) is a weak acid"},"content":{"rendered":"\n<p>Aspirin (acetylsalicylic acid, HC9H7O4) is a weak acid. It ionizes in water according to the equation<\/p>\n\n\n\n<p>HC9H7O4(aq) + H2O(l) \u21cc H3O+(aq) + C9H7O4-(aq)<\/p>\n\n\n\n<p>A 0.20-M aqueous solution of aspirin has a pH of 2.57 at 25\u00b0C. Determine the Ka of aspirin.<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>To determine the acid dissociation constant (Ka) of aspirin (acetylsalicylic acid, HC9H7O4), we start with the given information: a 0.20 M solution of aspirin has a pH of 2.57 at 25\u00b0C.<\/p>\n\n\n\n<p><strong>Step 1: Calculate the Hydronium Ion Concentration [H3O+].<\/strong><\/p>\n\n\n\n<p>The pH of a solution is related to the hydronium ion concentration by the equation:<\/p>\n\n\n\n<p>[ \\text{pH} = -\\log[\\text{H}_3\\text{O}^+] ]<\/p>\n\n\n\n<p>Rearranging to solve for ([\\text{H}_3\\text{O}^+]):<\/p>\n\n\n\n<p>[ [\\text{H}_3\\text{O}^+] = 10^{-\\text{pH}} ]<\/p>\n\n\n\n<p>Substituting the given pH:<\/p>\n\n\n\n<p>[ [\\text{H}_3\\text{O}^+] = 10^{-2.57} \\approx 2.69 \\times 10^{-3} \\, \\text{M} ]<\/p>\n\n\n\n<p><strong>Step 2: Determine the Degree of Ionization.<\/strong><\/p>\n\n\n\n<p>In the ionization of aspirin:<\/p>\n\n\n\n<p>[ \\text{HC}_9\\text{H}_7\\text{O}_4(aq) + \\text{H}_2\\text{O}(l) \\rightleftharpoons \\text{H}_3\\text{O}^+(aq) + \\text{C}_9\\text{H}_7\\text{O}_4^-(aq) ]<\/p>\n\n\n\n<p>Each molecule of HC9H7O4 that ionizes produces one H3O+ ion and one C9H7O4\u2212 ion. Therefore, the concentration of C9H7O4\u2212 ions at equilibrium is equal to the concentration of H3O+ ions:<\/p>\n\n\n\n<p>[ [\\text{C}_9\\text{H}_7\\text{O}_4^-] = [\\text{H}_3\\text{O}^+] = 2.69 \\times 10^{-3} \\, \\text{M} ]<\/p>\n\n\n\n<p>The change in concentration of HC9H7O4 due to ionization is also 2.69 \u00d7 10\u22123 M. Thus, the equilibrium concentration of HC9H7O4 is:<\/p>\n\n\n\n<p>[ [\\text{HC}<em>9\\text{H}_7\\text{O}_4]<\/em>{\\text{eq}} = 0.20 \\, \\text{M} &#8211; 2.69 \\times 10^{-3} \\, \\text{M} \\approx 0.1973 \\, \\text{M} ]<\/p>\n\n\n\n<p><strong>Step 3: Calculate the Acid Dissociation Constant (Ka).<\/strong><\/p>\n\n\n\n<p>The expression for the acid dissociation constant is:<\/p>\n\n\n\n<p>[ K_a = \\frac{[\\text{H}_3\\text{O}^+][\\text{C}_9\\text{H}_7\\text{O}_4^-]}{[\\text{HC}_9\\text{H}_7\\text{O}_4]} ]<\/p>\n\n\n\n<p>Substituting the equilibrium concentrations:<\/p>\n\n\n\n<p>[ K_a = \\frac{(2.69 \\times 10^{-3} \\, \\text{M}) \\times (2.69 \\times 10^{-3} \\, \\text{M})}{0.1973 \\, \\text{M}} ]<\/p>\n\n\n\n<p>[ K_a = \\frac{7.24 \\times 10^{-6} \\, \\text{M}^2}{0.1973 \\, \\text{M}} ]<\/p>\n\n\n\n<p>[ K_a \\approx 3.67 \\times 10^{-5} ]<\/p>\n\n\n\n<p>Therefore, the acid dissociation constant (Ka) of aspirin at 25\u00b0C is approximately 3.67 \u00d7 10\u22125.<\/p>\n\n\n\n<p>This value indicates that aspirin is a weak acid, as its Ka is significantly less than 1. The small degree of ionization in water corresponds to the relatively low hydronium ion concentration observed in the solution.<\/p>\n\n\n\n<p>Understanding the Ka of aspirin is important in pharmaceutical contexts, as it influences the drug&#8217;s absorption and efficacy. The ionization state can affect how well aspirin is absorbed in different parts of the gastrointestinal tract, impacting its therapeutic action.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Aspirin (acetylsalicylic acid, HC9H7O4) is a weak acid. It ionizes in water according to the equation HC9H7O4(aq) + H2O(l) \u21cc H3O+(aq) + C9H7O4-(aq) A 0.20-M aqueous solution of aspirin has a pH of 2.57 at 25\u00b0C. Determine the Ka of aspirin. The Correct Answer and Explanation is : To determine the acid dissociation constant (Ka) [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-195559","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/195559","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=195559"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/195559\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=195559"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=195559"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=195559"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}